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Question Number 95801 Answers: 2 Comments: 0

2y′′−y^′ =1; y(0) = 0 ; y′(0)=1

$$\mathrm{2y}''−\mathrm{y}^{'} =\mathrm{1};\:\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{0}\:;\:\mathrm{y}'\left(\mathrm{0}\right)=\mathrm{1} \\ $$

Question Number 95800 Answers: 1 Comments: 2

if f(0)=1 f(1)=2 and ∫_0 ^1 f(x) dx=3 than ∫_0 ^1 x f(x) dx = ? a. 1 b. −1 c. 2 d. −2

$${if}\:\:{f}\left(\mathrm{0}\right)=\mathrm{1} \\ $$$${f}\left(\mathrm{1}\right)=\mathrm{2}\:{and}\:\int_{\mathrm{0}} ^{\mathrm{1}} {f}\left({x}\right)\:{dx}=\mathrm{3}\: \\ $$$${than}\:\int_{\mathrm{0}} ^{\mathrm{1}} {x}\:{f}\left({x}\right)\:{dx}\:=\:? \\ $$$$ \\ $$$${a}.\:\mathrm{1} \\ $$$${b}.\:−\mathrm{1} \\ $$$${c}.\:\mathrm{2} \\ $$$${d}.\:−\mathrm{2} \\ $$$$ \\ $$

Question Number 95789 Answers: 1 Comments: 1

Find the semi−interquartile range of of the following numbers: 15, 10, 9, 15, 15, 8, 10, 11, 8, 12, 11, 14, 9 and 15

$$\:\mathrm{Find}\:\mathrm{the}\:\mathrm{semi}−\mathrm{interquartile}\:\mathrm{range}\:\mathrm{of}\: \\ $$$$\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{numbers}: \\ $$$$\:\mathrm{15},\:\mathrm{10},\:\mathrm{9},\:\mathrm{15},\:\mathrm{15},\:\mathrm{8},\:\mathrm{10},\:\mathrm{11},\:\mathrm{8},\:\mathrm{12},\:\mathrm{11},\:\mathrm{14}, \\ $$$$\:\mathrm{9}\:\mathrm{and}\:\mathrm{15} \\ $$

Question Number 95786 Answers: 1 Comments: 2

let f(x) =(1/x)ln(1+2x) 1) calculate f^((n)) (x)and f^((n)) (1) 2)developp f at integr serie at x_0 =1 3)developp f at integr serie at x_0 =0

$$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)\:=\frac{\mathrm{1}}{\mathrm{x}}\mathrm{ln}\left(\mathrm{1}+\mathrm{2x}\right) \\ $$$$\left.\mathrm{1}\right)\:\mathrm{calculate}\:\mathrm{f}^{\left(\mathrm{n}\right)} \left(\mathrm{x}\right)\mathrm{and}\:\mathrm{f}^{\left(\mathrm{n}\right)} \left(\mathrm{1}\right) \\ $$$$\left.\mathrm{2}\right)\mathrm{developp}\:\mathrm{f}\:\mathrm{at}\:\mathrm{integr}\:\mathrm{serie}\:\mathrm{at}\:\mathrm{x}_{\mathrm{0}} =\mathrm{1} \\ $$$$\left.\mathrm{3}\right)\mathrm{developp}\:\mathrm{f}\:\mathrm{at}\:\mathrm{integr}\:\mathrm{serie}\:\:\mathrm{at}\:\mathrm{x}_{\mathrm{0}} =\mathrm{0} \\ $$

Question Number 95785 Answers: 0 Comments: 0

calculate ∫_0 ^(π/2) (ln(cosx))^3 dx

$$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \left(\mathrm{ln}\left(\mathrm{cosx}\right)\right)^{\mathrm{3}} \:\mathrm{dx} \\ $$

Question Number 95784 Answers: 0 Comments: 0

calculate Σ_(n=1) ^∞ (H_n /n^2 ) H_n =Σ_(k=1) ^n (1/k)

$$\mathrm{calculate}\:\sum_{\mathrm{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{H}_{\mathrm{n}} }{\mathrm{n}^{\mathrm{2}} } \\ $$$$\mathrm{H}_{\mathrm{n}} =\sum_{\mathrm{k}=\mathrm{1}} ^{\mathrm{n}} \:\frac{\mathrm{1}}{\mathrm{k}} \\ $$

Question Number 95782 Answers: 0 Comments: 2

it looks version 2.077 has a problem. for very long loading

$$\mathrm{it}\:\mathrm{looks}\:\mathrm{version}\:\mathrm{2}.\mathrm{077}\:\mathrm{has}\:\mathrm{a}\: \\ $$$$\mathrm{problem}.\:\:\mathrm{for}\:\mathrm{very}\:\mathrm{long}\:\mathrm{loading} \\ $$

Question Number 95780 Answers: 0 Comments: 0

Question Number 95779 Answers: 2 Comments: 0

if plane 3x+4y+tz=2 and kx+6y+5z−2=0 are parallel. find the value of k and t

$$\mathrm{if}\:\mathrm{plane}\:\mathrm{3x}+\mathrm{4y}+\mathrm{tz}=\mathrm{2}\:\mathrm{and}\: \\ $$$$\mathrm{kx}+\mathrm{6y}+\mathrm{5z}−\mathrm{2}=\mathrm{0}\:\mathrm{are}\:\mathrm{parallel}. \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{and}\:\mathrm{t}\: \\ $$

Question Number 95773 Answers: 4 Comments: 0

Question Number 95772 Answers: 0 Comments: 3

Question Number 95770 Answers: 0 Comments: 8

the app doesn′t work properly for me any more. I open it and most of the time the home screen doesn′t show the forum. refreshing or trying to switch to the forum ends up in an endless turning loop...

$$\mathrm{the}\:\mathrm{app}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{work}\:\mathrm{properly}\:\mathrm{for}\:\mathrm{me}\:\mathrm{any} \\ $$$$\mathrm{more}.\:\mathrm{I}\:\mathrm{open}\:\mathrm{it}\:\mathrm{and}\:\mathrm{most}\:\mathrm{of}\:\mathrm{the}\:\mathrm{time}\:\mathrm{the} \\ $$$$\mathrm{home}\:\mathrm{screen}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{show}\:\mathrm{the}\:\mathrm{forum}. \\ $$$$\mathrm{refreshing}\:\mathrm{or}\:\mathrm{trying}\:\mathrm{to}\:\mathrm{switch}\:\mathrm{to}\:\mathrm{the}\:\mathrm{forum} \\ $$$$\mathrm{ends}\:\mathrm{up}\:\mathrm{in}\:\mathrm{an}\:\mathrm{endless}\:\mathrm{turning}\:\mathrm{loop}... \\ $$

Question Number 95768 Answers: 0 Comments: 1

find x such that x≡3 (mod5) x≡5 (mod7) x≡7(mod11)

$$\mathrm{find}\:\mathrm{x}\:\mathrm{such}\:\mathrm{that}\: \\ $$$${x}\equiv\mathrm{3}\:\left(\mathrm{mod5}\right) \\ $$$${x}\equiv\mathrm{5}\:\left(\mathrm{mod7}\right) \\ $$$${x}\equiv\mathrm{7}\left(\mathrm{mod11}\right) \\ $$

Question Number 95767 Answers: 1 Comments: 0

Question Number 95766 Answers: 0 Comments: 1

Solve the equation 2^(2x) − 5x^2 + 4 = 0

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\:\:\:\:\:\:\:\mathrm{2}^{\mathrm{2x}} \:\:−\:\:\mathrm{5x}^{\mathrm{2}} \:\:+\:\:\mathrm{4}\:\:\:=\:\:\:\mathrm{0} \\ $$

Question Number 95765 Answers: 0 Comments: 3

Sum the series: 2((1/(40)) + (1/(20)) + (1/(10)) + ... + n)

$$\mathrm{Sum}\:\mathrm{the}\:\mathrm{series}: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{2}\left(\frac{\mathrm{1}}{\mathrm{40}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{20}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{10}}\:\:+\:\:...\:\:+\:\:\boldsymbol{\mathrm{n}}\right) \\ $$

Question Number 95763 Answers: 0 Comments: 3

∫ x (√(x^3 +1)) dx ?

$$\int\:{x}\:\sqrt{{x}^{\mathrm{3}} +\mathrm{1}}\:{dx}\:? \\ $$

Question Number 95760 Answers: 1 Comments: 0

(d/(d(x)))(W(x))=? W(x) is lambert W function

$$\frac{{d}}{{d}\left({x}\right)}\left({W}\left({x}\right)\right)=? \\ $$$$\:{W}\left({x}\right)\:{is}\:{lambert}\:{W}\:{function} \\ $$

Question Number 95748 Answers: 2 Comments: 0

y′′ = sin x−cos x

$$\mathrm{y}''\:=\:\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x} \\ $$

Question Number 95742 Answers: 2 Comments: 2

(0/0)=2 ((100−100)/(100−100))=((10^2 −10^2 )/(10^2 −10^2 ))=(((10+10)(10−10))/(10(10−10))) ((20)/(10))=2 where is the mastike

$$\frac{\mathrm{0}}{\mathrm{0}}=\mathrm{2} \\ $$$$\frac{\mathrm{100}−\mathrm{100}}{\mathrm{100}−\mathrm{100}}=\frac{\mathrm{10}^{\mathrm{2}} −\mathrm{10}^{\mathrm{2}} }{\mathrm{10}^{\mathrm{2}} −\mathrm{10}^{\mathrm{2}} }=\frac{\left(\mathrm{10}+\mathrm{10}\right)\left(\mathrm{10}−\mathrm{10}\right)}{\mathrm{10}\left(\mathrm{10}−\mathrm{10}\right)} \\ $$$$\frac{\mathrm{20}}{\mathrm{10}}=\mathrm{2} \\ $$$$\mathrm{where}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mastike} \\ $$

Question Number 95738 Answers: 1 Comments: 2

∫ ((p−tan x)/(p+tan x)) dx

$$\int\:\frac{\mathrm{p}−\mathrm{tan}\:\mathrm{x}}{\mathrm{p}+\mathrm{tan}\:\mathrm{x}}\:\mathrm{dx}\: \\ $$

Question Number 95846 Answers: 1 Comments: 0

A = { 0, 1, 2, 3, ... , 2020 } how many zero on A ?

$${A}\:=\:\left\{\:\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:...\:,\:\mathrm{2020}\:\right\} \\ $$$${how}\:\:{many}\:\:{zero}\:\:{on}\:\:{A}\:? \\ $$

Question Number 95726 Answers: 0 Comments: 1

th forces F_1 ,F_2 ,F_3 act at points ith position vectors r_1 ,r_2 ,r_3 where F_1 = (4i + j + 2k)N r_1 = (6i + 4j + k) m F_2 = (i−2j + k)N r_2 = (i + 5j −2k) m F_3 = (−5i + j−3k)N r_3 = (i + j + k) m (a) show that this system reduces to a couple and find its magnitude. (b) if F_3 is removed and replaced with F_4 such that the system is now in equilibrium find the force vector F_4 . (c) the equation of the line of action of F_4 (d) the moment of F_4 about the origin.

$$\mathrm{th}\:\mathrm{forces}\:{F}_{\mathrm{1}} \:,{F}_{\mathrm{2}} ,{F}_{\mathrm{3}} \:\mathrm{act}\:\mathrm{at}\:\mathrm{points}\:\mathrm{ith}\:\mathrm{position}\:\mathrm{vectors}\:{r}_{\mathrm{1}} ,{r}_{\mathrm{2}} ,{r}_{\mathrm{3}} \:\:\mathrm{where} \\ $$$${F}_{\mathrm{1}} \:=\:\left(\mathrm{4}{i}\:+\:{j}\:+\:\mathrm{2}{k}\right){N}\:\:\:\:\:\:\:{r}_{\mathrm{1}} \:=\:\left(\mathrm{6}{i}\:+\:\mathrm{4}{j}\:+\:{k}\right)\:\mathrm{m} \\ $$$${F}_{\mathrm{2}} \:=\:\left({i}−\mathrm{2}{j}\:+\:{k}\right){N}\:\:\:\:\:\:\:\:\:\:\:{r}_{\mathrm{2}} \:=\:\left({i}\:+\:\mathrm{5}{j}\:−\mathrm{2}{k}\right)\:\mathrm{m} \\ $$$$\:{F}_{\mathrm{3}} \:=\:\left(−\mathrm{5}{i}\:+\:{j}−\mathrm{3}{k}\right){N}\:\:\:\:{r}_{\mathrm{3}} \:=\:\left({i}\:+\:{j}\:+\:{k}\right)\:\mathrm{m} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{show}\:\mathrm{that}\:\mathrm{this}\:\mathrm{system}\:\mathrm{reduces}\:\mathrm{to}\:\mathrm{a}\:\mathrm{couple}\:\mathrm{and}\:\mathrm{find}\:\mathrm{its}\:\mathrm{magnitude}. \\ $$$$\left(\mathrm{b}\right)\:\mathrm{if}\:\mathrm{F}_{\mathrm{3}} \:\mathrm{is}\:\mathrm{removed}\:\mathrm{and}\:\mathrm{replaced}\:\mathrm{with}\:{F}_{\mathrm{4}} \:\:\mathrm{such}\:\mathrm{that}\:\mathrm{the}\:\mathrm{system}\:\mathrm{is}\: \\ $$$$\mathrm{now}\:\mathrm{in}\:\mathrm{equilibrium}\:\mathrm{find}\:\mathrm{the}\:\mathrm{force}\:\mathrm{vector}\:{F}_{\mathrm{4}} . \\ $$$$\left(\mathrm{c}\right)\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{line}\:\mathrm{of}\:\mathrm{action}\:\mathrm{of}\:{F}_{\mathrm{4}} \\ $$$$\left(\mathrm{d}\right)\:\mathrm{the}\:\mathrm{moment}\:\mathrm{of}\:\mathrm{F}_{\mathrm{4}} \:\mathrm{about}\:\mathrm{the}\:\mathrm{origin}. \\ $$

Question Number 95723 Answers: 3 Comments: 1

Question Number 95722 Answers: 2 Comments: 0

use cylinder ring method y = 2x−1 y = −2x + 3 x = 2 y−axis

$${use}\:{cylinder}\:{ring}\:{method} \\ $$$$ \\ $$$${y}\:=\:\mathrm{2}{x}−\mathrm{1} \\ $$$${y}\:=\:−\mathrm{2}{x}\:+\:\mathrm{3} \\ $$$${x}\:=\:\mathrm{2}\: \\ $$$$ \\ $$$${y}−{axis}\: \\ $$$$ \\ $$$$ \\ $$

Question Number 95707 Answers: 1 Comments: 3

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