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AllQuestion and Answers: Page 12

Question Number 212131    Answers: 0   Comments: 0

Question Number 212130    Answers: 2   Comments: 0

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Question Number 212123    Answers: 1   Comments: 0

solve an equation: (√(ln x))=ln(√x)

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{solve}\:\mathrm{an}\:\mathrm{equation}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\sqrt{\boldsymbol{\mathrm{ln}}\:\boldsymbol{{x}}}=\boldsymbol{\mathrm{ln}}\sqrt{\boldsymbol{{x}}} \\ $$

Question Number 212114    Answers: 4   Comments: 0

(x^2 + 1)(y^2 + 1) + 9 = 6(x+y) Find that: x^2 + y^2 = ?

$$ \\ $$$$\:\:\:\left({x}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({y}^{\mathrm{2}} \:+\:\mathrm{1}\right)\:+\:\mathrm{9}\:=\:\mathrm{6}\left({x}+{y}\right) \\ $$$$\:\:\:\mathcal{F}{ind}\:{that}:\:\:{x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:=\:? \\ $$$$ \\ $$

Question Number 212108    Answers: 1   Comments: 0

∫_( −1) ^( 1) ∣ x ∣ ∙ ln(x^2 − x + 1) dx = ? Help me, please

$$ \\ $$$$\:\:\:\int_{\:−\mathrm{1}} ^{\:\:\mathrm{1}} \mid\:{x}\:\mid\:\centerdot\:{ln}\left({x}^{\mathrm{2}} \:−\:{x}\:+\:\mathrm{1}\right)\:{dx}\:=\:? \\ $$$$\:\:\:\mathcal{H}{elp}\:{me},\:{please} \\ $$$$ \\ $$

Question Number 212101    Answers: 0   Comments: 0

Question Number 212099    Answers: 3   Comments: 0

Question Number 212098    Answers: 1   Comments: 0

Prove that ln (((√(13))−1)/(10)) + (√(13)) − 2 >0 without calculator.

$$\mathrm{Prove}\:\mathrm{that} \\ $$$$\mathrm{ln}\:\frac{\sqrt{\mathrm{13}}−\mathrm{1}}{\mathrm{10}}\:+\:\sqrt{\mathrm{13}}\:−\:\mathrm{2}\:>\mathrm{0} \\ $$$$\mathrm{without}\:\mathrm{calculator}. \\ $$

Question Number 212097    Answers: 1   Comments: 0

lim_(x→0) (x^2 +e^x )^(1/x) =?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({x}^{\mathrm{2}} +{e}^{{x}} \right)^{\frac{\mathrm{1}}{{x}}} =? \\ $$

Question Number 212107    Answers: 1   Comments: 0

I=∫_0 ^∞ ((x cos x−sin x)/x^2 )dx.

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{I}=\int_{\mathrm{0}} ^{\infty} \frac{{x}\:\mathrm{cos}\:{x}−\mathrm{sin}\:{x}}{{x}^{\mathrm{2}} }{dx}. \\ $$$$ \\ $$

Question Number 212094    Answers: 1   Comments: 0

[1+(1/( (√2)))+(1/( (√3)))+(1/( (√4)))+.......+(1/( (√(1000000))))]=? note: [6.25]=6 ,[0.47]=0

$$\left[\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{4}}}+.......+\frac{\mathrm{1}}{\:\sqrt{\mathrm{1000000}}}\right]=? \\ $$$$\boldsymbol{{note}}:\:\:\:\left[\mathrm{6}.\mathrm{25}\right]=\mathrm{6}\:\:\:,\left[\mathrm{0}.\mathrm{47}\right]=\mathrm{0} \\ $$

Question Number 212085    Answers: 1   Comments: 1

a,b,c ∈ N 5a + 6b + 7c = 70 find: max(a) = ?

$$\mathrm{a},\mathrm{b},\mathrm{c}\:\in\:\mathbb{N} \\ $$$$\mathrm{5a}\:+\:\mathrm{6b}\:+\:\mathrm{7c}\:=\:\mathrm{70} \\ $$$$\mathrm{find}:\:\:\mathrm{max}\left(\mathrm{a}\right)\:=\:? \\ $$

Question Number 212084    Answers: 0   Comments: 0

Question Number 212083    Answers: 1   Comments: 0

Question Number 212075    Answers: 3   Comments: 0

Question Number 212067    Answers: 1   Comments: 0

Question Number 212066    Answers: 1   Comments: 0

Question Number 212065    Answers: 0   Comments: 0

Question Number 212053    Answers: 1   Comments: 0

∫_0 ^1 (∫_0 ^( y) e^(x^2 +y^2 ) dx)dy +∫_1 ^2 (∫_0 ^( 2−y) e^(x^2 +y^2 ) dx)dy = ?

$$ \\ $$$$\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\int_{\mathrm{0}} ^{\:\boldsymbol{{y}}} \:\boldsymbol{{e}}^{\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} } \boldsymbol{{dx}}\right)\boldsymbol{{dy}}\:+\int_{\mathrm{1}} ^{\mathrm{2}} \left(\int_{\mathrm{0}} ^{\:\mathrm{2}−\boldsymbol{{y}}} \:\boldsymbol{{e}}^{\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} } \boldsymbol{{dx}}\right)\boldsymbol{{dy}}\:=\:? \\ $$$$ \\ $$

Question Number 212052    Answers: 1   Comments: 0

Question Number 212051    Answers: 3   Comments: 0

Question Number 212050    Answers: 2   Comments: 0

Question Number 212049    Answers: 1   Comments: 0

Question Number 212048    Answers: 1   Comments: 0

Question Number 212047    Answers: 2   Comments: 0

Question Number 212046    Answers: 3   Comments: 0

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