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Question Number 199817    Answers: 2   Comments: 0

Question Number 199801    Answers: 1   Comments: 0

Question Number 199783    Answers: 1   Comments: 0

∫xdx=?

$$\int{xdx}=? \\ $$

Question Number 199781    Answers: 1   Comments: 0

$$\:\:\: \\ $$

Question Number 199775    Answers: 2   Comments: 0

Question Number 199774    Answers: 1   Comments: 0

Question Number 199772    Answers: 0   Comments: 0

Question Number 199771    Answers: 3   Comments: 0

Question Number 199770    Answers: 4   Comments: 0

Question Number 199769    Answers: 0   Comments: 0

62n7z7

$$\mathrm{62}{n}\mathrm{7}{z}\mathrm{7} \\ $$

Question Number 199766    Answers: 1   Comments: 0

Question Number 199753    Answers: 1   Comments: 0

Question Number 199752    Answers: 0   Comments: 0

Question Number 199738    Answers: 1   Comments: 0

Question Number 199733    Answers: 1   Comments: 0

Question Number 199732    Answers: 2   Comments: 0

Question Number 199731    Answers: 2   Comments: 0

Question Number 199730    Answers: 1   Comments: 0

Question Number 199729    Answers: 1   Comments: 0

Question Number 199728    Answers: 1   Comments: 0

Question Number 199723    Answers: 1   Comments: 0

Question Number 199721    Answers: 0   Comments: 0

Question Number 199719    Answers: 1   Comments: 0

Question Number 199718    Answers: 1   Comments: 0

{ ((cos x+cos y=(1/2))),((sin x+sin y=(1/4))),((sin 2x + sin 2y=−((27)/(20)))) :} sin (x+y) = ...

$$\:\begin{cases}{\mathrm{cos}\:\mathrm{x}+\mathrm{cos}\:\mathrm{y}=\frac{\mathrm{1}}{\mathrm{2}}}\\{\mathrm{sin}\:\mathrm{x}+\mathrm{sin}\:\mathrm{y}=\frac{\mathrm{1}}{\mathrm{4}}}\\{\mathrm{sin}\:\mathrm{2x}\:+\:\mathrm{sin}\:\mathrm{2y}=−\frac{\mathrm{27}}{\mathrm{20}}}\end{cases} \\ $$$$\:\:\:\mathrm{sin}\:\left(\mathrm{x}+\mathrm{y}\right)\:=\:... \\ $$

Question Number 199714    Answers: 0   Comments: 3

Statement Does the number of data have to be more than 100 in order to have a percentile value ?

$$\:{Statement}\: \\ $$$$\:{Does}\:{the}\:{number}\:{of}\:{data}\:{have} \\ $$$$\:{to}\:{be}\:{more}\:{than}\:\mathrm{100}\:{in}\:{order}\: \\ $$$$\:{to}\:{have}\:{a}\:{percentile}\:{value}\:? \\ $$

Question Number 199711    Answers: 3   Comments: 0

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