2F1((1/2),(1/2);(1/2);z)=(1−z)^(1/2) ∗∗1
by kummer transformation
2F1((1/2),(1/2);(1/2);z)=2F1((1/2),(1/2);1+(1/2)+(1/2)−(1/2);z)
2F1((1/2),(1/2);(1/2);z)=((sin^(−1) (√(1−z)))/(√(1−z)))∗∗2
why do i get different answer in
∗∗1 and 2∗∗
E is a vectorial plane. his base is
B=(i^→ ;j^→ ). f is an endomorphism defined
by f(i^→ )=−((√2)/2)i^→ +((√2)/2)j^→ and f(j^→ )=((√2)/2)i^→ −((√2)/2)j^→
1)Show that ker f is a vectorial straigh
line and his base is e_1 ^→ =(√2)i^→ +(√2)j^→
2)show that G, the set of vectors u^→
∈ E such as f(u^→ )=(√2)u^→ is a vectorial straigh
line and his Base is e_(2 ) ^→ =i^→ +j^→
3) Determine the matrix A′ of f in
B′ if B′=(e_1 ^→ ;e_2 ^→ ).