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Question Number 99300 Answers: 1 Comments: 0

Find Σ_(n=1) ^∞ (1/((3n)!))=?

$$\mathrm{Find}\:\:\underset{\boldsymbol{{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{3}\boldsymbol{{n}}\right)!}=? \\ $$

Question Number 97963 Answers: 0 Comments: 0

Question Number 97956 Answers: 1 Comments: 0

prove Σ_(n=1) ^∞ ((9n+4)/(3n(3n+1)(3n+2)))=(3/2)−ln(3)

$${prove} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{9}{n}+\mathrm{4}}{\mathrm{3}{n}\left(\mathrm{3}{n}+\mathrm{1}\right)\left(\mathrm{3}{n}+\mathrm{2}\right)}=\frac{\mathrm{3}}{\mathrm{2}}−{ln}\left(\mathrm{3}\right) \\ $$

Question Number 97953 Answers: 1 Comments: 3

Question Number 97942 Answers: 2 Comments: 0

Question Number 97936 Answers: 1 Comments: 1

Find the value of (√(45−(√(2000)) )) + (√(45+(√(2000))))

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\sqrt{\mathrm{45}−\sqrt{\mathrm{2000}}\:}\:\:+\:\:\sqrt{\mathrm{45}+\sqrt{\mathrm{2000}}}\: \\ $$

Question Number 97929 Answers: 0 Comments: 1

Find equation of line through A(1,2,3) and parallel to y axis ?

$$\mathrm{Find}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{line}\:\mathrm{through}\:\mathrm{A}\left(\mathrm{1},\mathrm{2},\mathrm{3}\right) \\ $$$$\mathrm{and}\:\mathrm{parallel}\:\mathrm{to}\:\mathrm{y}\:\mathrm{axis}\:?\: \\ $$

Question Number 97928 Answers: 1 Comments: 0

find the general formula ∫_0 ^(π/2) tan^α (x) dx

$${find}\:{the}\:{general}\:{formula} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {tan}^{\alpha} \left({x}\right)\:{dx} \\ $$

Question Number 97922 Answers: 1 Comments: 0

y′′ + y = cot x

$$\mathrm{y}''\:+\:\mathrm{y}\:=\:\mathrm{cot}\:{x}\: \\ $$

Question Number 97918 Answers: 0 Comments: 1

Deleted one of the previous post. There is an option in app where you can use preferred font size. Soon another option will be added where you will able to use your preferred color combination.

$$\mathrm{Deleted}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{previous}\:\mathrm{post}.\: \\ $$$$\mathrm{There}\:\mathrm{is}\:\mathrm{an}\:\mathrm{option}\:\mathrm{in}\:\mathrm{app}\:\mathrm{where} \\ $$$$\mathrm{you}\:\mathrm{can}\:\mathrm{use}\:\mathrm{preferred}\:\mathrm{font}\:\mathrm{size}. \\ $$$$\mathrm{Soon}\:\mathrm{another}\:\mathrm{option}\:\mathrm{will}\:\mathrm{be}\:\mathrm{added} \\ $$$$\mathrm{where}\:\mathrm{you}\:\mathrm{will}\:\mathrm{able}\:\mathrm{to}\:\mathrm{use}\:\mathrm{your} \\ $$$$\mathrm{preferred}\:\mathrm{color}\:\mathrm{combination}. \\ $$

Question Number 97920 Answers: 0 Comments: 4

Question Number 97919 Answers: 1 Comments: 2

Question Number 97901 Answers: 2 Comments: 2

Question Number 97888 Answers: 1 Comments: 2

how to prove ((the volumn of dimensional sphare)) formula V_N (R)=(π^(N/2) /(Γ((N/2)+1))) R^N

$${how}\:{to}\:{prove}\:\left(\left({the}\:{volumn}\:{of}\right.\right. \\ $$$$\left.{d}\left.{imensional}\:{sphare}\right)\right)\:{formula} \\ $$$${V}_{{N}} \left({R}\right)=\frac{\pi^{{N}/\mathrm{2}} }{\Gamma\left(\frac{{N}}{\mathrm{2}}+\mathrm{1}\right)}\:{R}^{{N}} \\ $$$$ \\ $$

Question Number 97891 Answers: 0 Comments: 6

Question Number 97885 Answers: 2 Comments: 2

hello every one how do they calculated the universe old wich is 13.8 billion years

$${hello}\:{every}\:{one} \\ $$$${how}\:{do}\:{they}\:{calculated}\:{the}\:{universe}\:{old} \\ $$$${wich}\:{is}\:\mathrm{13}.\mathrm{8}\:{billion}\:{years} \\ $$

Question Number 97868 Answers: 2 Comments: 0

3y′ = 2x+y−1

$$\mathrm{3y}'\:=\:\mathrm{2x}+\mathrm{y}−\mathrm{1}\: \\ $$

Question Number 97866 Answers: 5 Comments: 4

Question Number 97858 Answers: 1 Comments: 1

Question Number 97847 Answers: 1 Comments: 0

(x^2 +x) (d^2 y/dx^2 ) + (1−2x^2 ) (dy/dx) + (x^2 −x−1)y = x^2 −x−1

$$\left(\mathrm{x}^{\mathrm{2}} +\mathrm{x}\right)\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:+\:\left(\mathrm{1}−\mathrm{2x}^{\mathrm{2}} \right)\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}−\mathrm{1}\right)\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} −\mathrm{x}−\mathrm{1} \\ $$

Question Number 97840 Answers: 0 Comments: 1

lim_(γ→0) (arc sin ((k cos γ)/(√(1+k^2 ))) − arc sin (k/(√(1+k^2 )))) =?

$$\underset{\gamma\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\mathrm{arc}\:\mathrm{sin}\:\frac{\mathrm{k}\:\mathrm{cos}\:\gamma}{\sqrt{\mathrm{1}+\mathrm{k}^{\mathrm{2}} }}\:−\:\mathrm{arc}\:\mathrm{sin}\:\frac{\mathrm{k}}{\sqrt{\mathrm{1}+\mathrm{k}^{\mathrm{2}} }}\right)\:=? \\ $$

Question Number 97839 Answers: 3 Comments: 1

calculate A_n =∫_0 ^((nπ)/4) (dx/(3cos^4 x +3sin^4 x−1))

$$\mathrm{calculate}\:\mathrm{A}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\frac{\mathrm{n}\pi}{\mathrm{4}}} \:\frac{\mathrm{dx}}{\mathrm{3cos}^{\mathrm{4}} \mathrm{x}\:+\mathrm{3sin}^{\mathrm{4}} \mathrm{x}−\mathrm{1}} \\ $$

Question Number 97833 Answers: 0 Comments: 10

Hello members of maths editor i want to say something concerning this forum. Well it is my own point of view: This forum is a place where people from all over the world come to interact together. A place where people from different back grounds, class and qualification speak a common language − mathematics. I in particular thank Tinkutara′s team for such a great platform. But i notice some people literally don′t show respect to others, like persuading others to answer thier questions, others show no appreciation for the given answers while others give rude comments with no reason behind them. please i just want to urge the Maths editor users to show more respect for others since we don′t know the identity or qualification of people who post and solve questions here. we remain one family as God guides us through our endervous.

$$\:\mathrm{Hello}\:\mathrm{members}\:\mathrm{of}\:\mathrm{maths}\:\mathrm{editor}\:\mathrm{i}\:\mathrm{want}\:\mathrm{to}\:\mathrm{say} \\ $$$$\mathrm{something}\:\mathrm{concerning}\:\mathrm{this}\:\mathrm{forum}.\:\mathrm{Well}\:\mathrm{it} \\ $$$$\mathrm{is}\:\mathrm{my}\:\mathrm{own}\:\mathrm{point}\:\mathrm{of}\:\mathrm{view}:\:\mathrm{This}\:\mathrm{forum}\:\mathrm{is}\:\mathrm{a}\:\mathrm{place}\:\mathrm{where} \\ $$$$\mathrm{people}\:\mathrm{from}\:\mathrm{all}\:\mathrm{over}\:\mathrm{the}\:\mathrm{world}\:\mathrm{come}\:\mathrm{to}\:\mathrm{interact}\:\mathrm{together}. \\ $$$$\mathrm{A}\:\mathrm{place}\:\mathrm{where}\:\mathrm{people}\:\mathrm{from}\:\mathrm{different}\:\mathrm{back}\:\mathrm{grounds}, \\ $$$$\mathrm{class}\:\mathrm{and}\:\mathrm{qualification}\:\mathrm{speak}\:\mathrm{a}\:\mathrm{common}\:\mathrm{language}\:−\: \\ $$$$\mathrm{mathematics}.\:\mathrm{I}\:\mathrm{in}\:\mathrm{particular}\:\mathrm{thank}\:\mathrm{Tinkutara}'\mathrm{s}\:\mathrm{team}\:\mathrm{for} \\ $$$$\mathrm{such}\:\mathrm{a}\:\mathrm{great}\:\mathrm{platform}.\:\mathrm{But}\:\mathrm{i}\:\mathrm{notice}\:\mathrm{some}\:\mathrm{people}\:\mathrm{literally} \\ $$$$\mathrm{don}'\mathrm{t}\:\mathrm{show}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{others},\:\mathrm{like}\:\mathrm{persuading}\:\mathrm{others} \\ $$$$\mathrm{to}\:\mathrm{answer}\:\mathrm{thier}\:\mathrm{questions},\:\mathrm{others}\:\mathrm{show}\:\mathrm{no}\: \\ $$$$\mathrm{appreciation}\:\mathrm{for}\:\mathrm{the}\:\mathrm{given}\:\mathrm{answers}\:\mathrm{while}\:\mathrm{others}\:\mathrm{give}\:\mathrm{rude} \\ $$$$\mathrm{comments}\:\mathrm{with}\:\mathrm{no}\:\mathrm{reason}\:\mathrm{behind}\:\mathrm{them}. \\ $$$$\mathrm{please}\:\mathrm{i}\:\mathrm{just}\:\mathrm{want}\:\mathrm{to}\:\mathrm{urge}\:\mathrm{the}\:\mathrm{Maths}\:\mathrm{editor}\:\mathrm{users}\:\mathrm{to}\:\mathrm{show} \\ $$$$\mathrm{more}\:\mathrm{respect}\:\mathrm{for}\:\mathrm{others}\:\mathrm{since}\:\mathrm{we}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{the}\:\mathrm{identity}\:\mathrm{or} \\ $$$$\mathrm{qualification}\:\mathrm{of}\:\mathrm{people}\:\mathrm{who}\:\mathrm{post}\:\mathrm{and}\:\mathrm{solve}\:\mathrm{questions}\:\mathrm{here}. \\ $$$$\mathrm{we}\:\mathrm{remain}\:\mathrm{one}\:\mathrm{family}\:\mathrm{as}\:\mathrm{God}\:\mathrm{guides}\:\mathrm{us}\:\mathrm{through}\:\mathrm{our}\:\mathrm{endervous}. \\ $$

Question Number 97827 Answers: 0 Comments: 1

Question Number 97823 Answers: 4 Comments: 2

If x and y are integers , prove that x^3 −7x divisible by 3

$$\mathrm{If}\:{x}\:\mathrm{and}\:{y}\:\mathrm{are}\:\mathrm{integers}\:,\:\mathrm{prove} \\ $$$$\mathrm{that}\:{x}^{\mathrm{3}} −\mathrm{7}{x}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{3}\: \\ $$

Question Number 97818 Answers: 1 Comments: 0

if y^2 = ax^2 + bx + c Show that: y (d^3 y/dx^3 ) + 3 (dy/dx) (d^2 y/dx^2 ) = 0

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