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Question Number 101436 Answers: 1 Comments: 0

Question Number 101425 Answers: 3 Comments: 2

A student wrote three papers in mathematics examinations. Her marks for the two of papers were 77 and 72 respectively. To obtain grade A, an average of not less than 75 marks is required for the three papers. How many marks must she get in the third paper to get grade A?

$$\mathrm{A}\:\mathrm{student}\:\mathrm{wrote}\:\mathrm{three}\:\mathrm{papers}\:\mathrm{in}\:\mathrm{mathematics} \\ $$$$\mathrm{examinations}.\:\mathrm{Her}\:\mathrm{marks}\:\mathrm{for}\:\mathrm{the}\:\mathrm{two}\:\mathrm{of} \\ $$$$\mathrm{papers}\:\mathrm{were}\:\mathrm{77}\:\mathrm{and}\:\mathrm{72}\:\mathrm{respectively}.\:\mathrm{To} \\ $$$$\mathrm{obtain}\:\mathrm{grade}\:\mathrm{A},\:\mathrm{an}\:\mathrm{average}\:\mathrm{of}\:\mathrm{not}\:\mathrm{less} \\ $$$$\mathrm{than}\:\mathrm{75}\:\mathrm{marks}\:\mathrm{is}\:\mathrm{required}\:\mathrm{for}\:\mathrm{the}\:\mathrm{three} \\ $$$$\mathrm{papers}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{marks}\:\mathrm{must}\:\mathrm{she}\:\mathrm{get} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{third}\:\mathrm{paper}\:\mathrm{to}\:\mathrm{get}\:\mathrm{grade}\:\mathrm{A}? \\ $$

Question Number 101422 Answers: 0 Comments: 2

lim_(h→0 ) ((sin ((α+h)^2 )−sin (α^2 ))/(cos ((α+h)^2 sin (α+h)−cos (α^2 )sin (α))) =?

$$\underset{\mathrm{h}\rightarrow\mathrm{0}\:} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\left(\left(\alpha+\mathrm{h}\right)^{\mathrm{2}} \right)−\mathrm{sin}\:\left(\alpha^{\mathrm{2}} \right)}{\mathrm{cos}\:\left(\left(\alpha+\mathrm{h}\right)^{\mathrm{2}} \mathrm{sin}\:\left(\alpha+\mathrm{h}\right)−\mathrm{cos}\:\left(\alpha^{\mathrm{2}} \right)\mathrm{sin}\:\left(\alpha\right)\right.}\:=? \\ $$

Question Number 101419 Answers: 2 Comments: 0

y′′−4y′+3y = (e^x /(1+e^x ))

$$\mathrm{y}''−\mathrm{4y}'+\mathrm{3y}\:=\:\frac{\mathrm{e}^{\mathrm{x}} }{\mathrm{1}+\mathrm{e}^{\mathrm{x}} } \\ $$

Question Number 101418 Answers: 0 Comments: 6

Find 2020 term from series (1/1),(2/1),(1/2),(3/1),(2/2),(1/3),(4/1),(3/2),(2/3),(1/4) ,(5/1),(4/2),... is ___ (A) ((2019)/(2020)) (B) ((61)/4) (C)((63)/1) (D) ((96)/4) (E) ((2020)/(2019))

$$\mathrm{Find}\:\mathrm{2020}\:\mathrm{term}\:\mathrm{from}\:\mathrm{series} \\ $$$$\frac{\mathrm{1}}{\mathrm{1}},\frac{\mathrm{2}}{\mathrm{1}},\frac{\mathrm{1}}{\mathrm{2}},\frac{\mathrm{3}}{\mathrm{1}},\frac{\mathrm{2}}{\mathrm{2}},\frac{\mathrm{1}}{\mathrm{3}},\frac{\mathrm{4}}{\mathrm{1}},\frac{\mathrm{3}}{\mathrm{2}},\frac{\mathrm{2}}{\mathrm{3}},\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$,\frac{\mathrm{5}}{\mathrm{1}},\frac{\mathrm{4}}{\mathrm{2}},...\:\mathrm{is}\:\_\_\_ \\ $$$$\left(\mathrm{A}\right)\:\frac{\mathrm{2019}}{\mathrm{2020}}\:\:\:\:\:\:\left(\mathrm{B}\right)\:\frac{\mathrm{61}}{\mathrm{4}}\:\:\:\:\:\left(\mathrm{C}\right)\frac{\mathrm{63}}{\mathrm{1}} \\ $$$$\left(\mathrm{D}\right)\:\frac{\mathrm{96}}{\mathrm{4}}\:\:\:\:\:\:\left(\mathrm{E}\right)\:\frac{\mathrm{2020}}{\mathrm{2019}} \\ $$

Question Number 101409 Answers: 0 Comments: 1

which is correct ∫((5x^4 +4x^5 )/((x^5 +x+1)^2 )) dx is equal to a) (x^5 /(x^5 +x+1)) b)−((x+1)/(x^5 +x+1))

$$\mathrm{which}\:\mathrm{is}\:\mathrm{correct} \\ $$$$\int\frac{\mathrm{5x}^{\mathrm{4}} +\mathrm{4x}^{\mathrm{5}} }{\left(\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }\:\mathrm{dx}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left.\mathrm{a}\left.\right)\:\frac{\mathrm{x}^{\mathrm{5}} }{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{b}\right)−\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}} \\ $$

Question Number 101393 Answers: 1 Comments: 0

Question Number 101400 Answers: 0 Comments: 4

App Updates: Show and Hide Keyboard Request by teachers using this app along with screen sharing apps for online classes Set Home Screen to Forum Requested by Mr W

Question Number 101382 Answers: 2 Comments: 0

Question Number 105239 Answers: 1 Comments: 0

Σ_(Σ_(p=5) ^6 p) ^(Σ_(p=8) ^(11) p) ∫_(11) ^(13) (((12ky)/x^2 ) + 6x) dx = Σ_(Σ_(p=4) ^7 p) ^(Σ_(p=9) ^(12) p) ∫_(11) ^(16) (x^2 y−(3/2)k)dx solve for y

$$\underset{\underset{{p}=\mathrm{5}} {\overset{\mathrm{6}} {\sum}}{p}} {\overset{\underset{{p}=\mathrm{8}} {\overset{\mathrm{11}} {\sum}}{p}} {\sum}}\:\underset{\mathrm{11}} {\overset{\mathrm{13}} {\int}}\left(\frac{\mathrm{12}{ky}}{{x}^{\mathrm{2}} }\:+\:\mathrm{6}{x}\right)\:{dx}\:=\:\underset{\underset{{p}=\mathrm{4}} {\overset{\mathrm{7}} {\sum}}{p}} {\overset{\underset{{p}=\mathrm{9}} {\overset{\mathrm{12}} {\sum}}{p}} {\sum}}\:\underset{\mathrm{11}} {\overset{\mathrm{16}} {\int}}\left({x}^{\mathrm{2}} {y}−\frac{\mathrm{3}}{\mathrm{2}}{k}\right){dx} \\ $$$${solve}\:{for}\:{y} \\ $$

Question Number 105238 Answers: 1 Comments: 0

(dy/dx) = (1/(3e^y −2x)) ?

$$\frac{{dy}}{{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{3}{e}^{{y}} −\mathrm{2}{x}}\:? \\ $$

Question Number 101378 Answers: 2 Comments: 1

∫_(1/e) ^(tanx) (t/(1+t^2 ))dt + ∫_(1/e) ^(cotx) (1/(t(1+t^2 )))dt

$$\int_{\frac{\mathrm{1}}{{e}}} ^{{tanx}} \frac{{t}}{\mathrm{1}+{t}^{\mathrm{2}} }{dt}\:+\:\int_{\frac{\mathrm{1}}{{e}}} ^{{cotx}} \frac{\mathrm{1}}{{t}\left(\mathrm{1}+{t}^{\mathrm{2}} \right)}{dt} \\ $$

Question Number 101375 Answers: 1 Comments: 4

Question Number 101373 Answers: 0 Comments: 1

lim_(n→∞ ) Σ_(r=1) ^(4n) ((√n)/((√r)(3(√r)+4(√n))^2 ))

$$\underset{{n}\rightarrow\infty\:} {\mathrm{lim}}\underset{{r}=\mathrm{1}} {\overset{\mathrm{4}{n}} {\sum}}\frac{\sqrt{{n}}}{\sqrt{{r}}\left(\mathrm{3}\sqrt{{r}}+\mathrm{4}\sqrt{{n}}\right)^{\mathrm{2}} } \\ $$

Question Number 101366 Answers: 1 Comments: 2

lim_(x→0) ((x^3 −sin^3 x)/x^5 ) =?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{3}} −\mathrm{sin}\:^{\mathrm{3}} {x}}{{x}^{\mathrm{5}} }\:=? \\ $$

Question Number 101363 Answers: 1 Comments: 0

The solution set of inequality (((√((3x−7)^2 ))−2)/(x−3)) ≤ ((3−(√x^2 ))/(x−3)) is __ (A) (−∞, (1/2)] (D) [(1/2), ∞) (B) [(1/2),1 ] (E) (−∞,(2/3)] (C) (−∞,1 ]

$$\mathrm{The}\:\mathrm{solution}\:\mathrm{set}\:\mathrm{of}\:\mathrm{inequality} \\ $$$$\frac{\sqrt{\left(\mathrm{3x}−\mathrm{7}\right)^{\mathrm{2}} }−\mathrm{2}}{\mathrm{x}−\mathrm{3}}\:\leqslant\:\frac{\mathrm{3}−\sqrt{\mathrm{x}^{\mathrm{2}} }}{\mathrm{x}−\mathrm{3}}\:\mathrm{is}\:\_\_ \\ $$$$\left(\mathrm{A}\right)\:\left(−\infty,\:\frac{\mathrm{1}}{\mathrm{2}}\right]\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\left[\frac{\mathrm{1}}{\mathrm{2}},\:\infty\right) \\ $$$$\left(\mathrm{B}\right)\:\left[\frac{\mathrm{1}}{\mathrm{2}},\mathrm{1}\:\right]\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{E}\right)\:\left(−\infty,\frac{\mathrm{2}}{\mathrm{3}}\right] \\ $$$$\left(\mathrm{C}\right)\:\left(−\infty,\mathrm{1}\:\right]\: \\ $$

Question Number 101362 Answers: 0 Comments: 1

Question Number 101360 Answers: 0 Comments: 0

xy′=y(ylnx+1)

$${xy}'={y}\left({ylnx}+\mathrm{1}\right) \\ $$

Question Number 101350 Answers: 1 Comments: 0

Question Number 101345 Answers: 0 Comments: 3

(1)∫ ((sec^4 x tan x)/(sec^4 x+4)) dx= (2) ∫x^(2x) (2lnx +2) dx = (3) ∫_0 ^1 (√(1−x^2 )) dx =

$$\left(\mathrm{1}\right)\int\:\frac{\mathrm{sec}\:^{\mathrm{4}} {x}\:\mathrm{tan}\:{x}}{\mathrm{sec}\:^{\mathrm{4}} {x}+\mathrm{4}}\:{dx}= \\ $$$$\left(\mathrm{2}\right)\:\int{x}^{\mathrm{2}{x}} \left(\mathrm{2ln}{x}\:+\mathrm{2}\right)\:{dx}\:= \\ $$$$\left(\mathrm{3}\right)\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:{dx}\:=\: \\ $$

Question Number 101342 Answers: 1 Comments: 0

find U_n =∫_0 ^1 ((x^(2n) −1)/(lnx))dx with n integr natural and n≥2 find nature of the serie Σ U_n

$$\mathrm{find}\:\:\mathrm{U}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{\mathrm{x}^{\mathrm{2n}} −\mathrm{1}}{\mathrm{lnx}}\mathrm{dx}\:\:\mathrm{with}\:\mathrm{n}\:\mathrm{integr}\:\mathrm{natural}\:\mathrm{and}\:\mathrm{n}\geqslant\mathrm{2} \\ $$$$\mathrm{find}\:\mathrm{nature}\:\mathrm{of}\:\mathrm{the}\:\mathrm{serie}\:\Sigma\:\mathrm{U}_{\mathrm{n}} \\ $$

Question Number 101402 Answers: 0 Comments: 3

I desire the developmenter of this apps improve adding some other functions like as:choose whole text by tap in text or choose some line at one time has many colours more

$$\mathrm{I}\:\mathrm{desire}\:\mathrm{the}\:\mathrm{developmenter}\:\mathrm{of}\:\mathrm{this}\:\mathrm{apps} \\ $$$$\mathrm{improve}\:\mathrm{adding}\:\mathrm{some}\:\mathrm{other}\:\mathrm{functions} \\ $$$$\mathrm{like}\:\mathrm{as}:\mathrm{choose}\:\mathrm{whole}\:\mathrm{text}\:\mathrm{by}\:\mathrm{tap}\:\mathrm{in} \\ $$$$\mathrm{text}\:\mathrm{or}\:\mathrm{choose}\:\mathrm{some}\:\mathrm{line}\:\mathrm{at}\:\mathrm{one}\:\mathrm{time} \\ $$$$\mathrm{has}\:\mathrm{many}\:\mathrm{colours}\:\mathrm{more} \\ $$

Question Number 101330 Answers: 0 Comments: 5

Evaluate. ∫_(−π) ^π x^9 cos x dx

$${Evaluate}. \\ $$$$\int_{−\pi} ^{\pi} {x}^{\mathrm{9}} \mathrm{cos}\:{x}\:{dx} \\ $$

Question Number 101329 Answers: 1 Comments: 0

Question Number 101328 Answers: 0 Comments: 1

this i a beautifull old question in the forum by sir.Ali Esam i Reposted it trying to find any idea to solve I=∫_(−1) ^1 (((sin(x))/(sinh^(−1) (x))))(((sin^(−1) (x))/(sinh(x))))dx i solved it numerical the value is 2.03383

$${this}\:{i}\:{a}\:{beautifull}\:{old}\:{question}\:{in}\:{the}\:{forum} \\ $$$${by}\:{sir}.{Ali}\:{Esam}\:{i}\:{Reposted}\:{it}\:{trying}\:{to} \\ $$$${find}\:{any}\:{idea}\:{to}\:{solve} \\ $$$$ \\ $$$${I}=\int_{−\mathrm{1}} ^{\mathrm{1}} \left(\frac{{sin}\left({x}\right)}{{sinh}^{−\mathrm{1}} \left({x}\right)}\right)\left(\frac{{sin}^{−\mathrm{1}} \left({x}\right)}{{sinh}\left({x}\right)}\right){dx} \\ $$$$ \\ $$$${i}\:{solved}\:{it}\:{numerical}\: \\ $$$${the}\:{value}\:{is}\:\mathrm{2}.\mathrm{03383} \\ $$

Question Number 101319 Answers: 1 Comments: 4

find the area bounded the parabola y=4x^2 and y=8−4x^2 ? by using intigral? help me

$${find}\:{the}\:{area}\:{bounded}\:{the}\:{parabola}\: \\ $$$${y}=\mathrm{4}{x}^{\mathrm{2}} \:\:\:{and}\:\:{y}=\mathrm{8}−\mathrm{4}{x}^{\mathrm{2}} \:\:?\:\:{by}\:{using}\:{intigral}? \\ $$$${help}\:{me} \\ $$

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