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Question Number 208999 Answers: 3 Comments: 0

Question Number 208980 Answers: 1 Comments: 0

please . find 2^(11001^(666) ) mod 23 thanks.

$${please}\:.\:\:\:\:\:{find}\:\:\mathrm{2}^{\mathrm{11001}^{\mathrm{666}} } {mod}\:\mathrm{23}\:\:\:\:\:\:\:\:{thanks}. \\ $$

Question Number 208976 Answers: 4 Comments: 0

Question Number 208975 Answers: 0 Comments: 0

Question Number 208974 Answers: 4 Comments: 0

Question Number 208973 Answers: 1 Comments: 5

Question Number 208972 Answers: 3 Comments: 0

Question Number 208970 Answers: 5 Comments: 0

Question Number 208969 Answers: 5 Comments: 0

Question Number 208968 Answers: 0 Comments: 0

hello everyone. Im writing a project on the topic“ Solution of Nonlinear partial differential equation using charpits methods” curently writing chapter 2 but I′m a little bit confused about what ih should include in my theoretical framework. Any ideas?

$$ \\ $$$$\mathrm{hello}\:\mathrm{everyone}.\:\mathrm{Im}\:\mathrm{writing}\:\mathrm{a}\:\mathrm{project}\:\:\mathrm{on}\:\mathrm{the}\:\mathrm{topic}``\:\mathrm{Solution}\:\mathrm{of} \\ $$$$\mathrm{Nonlinear}\:\mathrm{partial}\:\mathrm{differential}\:\mathrm{equation}\:\mathrm{using}\:\mathrm{charpits}\:\mathrm{methods}'' \\ $$$$\mathrm{curently}\:\mathrm{writing}\:\mathrm{chapter}\:\mathrm{2}\:\mathrm{but}\:\mathrm{I}'\mathrm{m}\:\mathrm{a}\:\mathrm{little}\:\mathrm{bit}\:\mathrm{confused}\:\mathrm{about}\:\mathrm{what}\:\mathrm{ih} \\ $$$$\mathrm{should}\:\mathrm{include}\:\mathrm{in}\:\mathrm{my}\:\mathrm{theoretical}\:\mathrm{framework}.\:\mathrm{Any}\:\mathrm{ideas}? \\ $$

Question Number 208962 Answers: 1 Comments: 3

Question Number 208959 Answers: 5 Comments: 0

If z = − (1/2) + ((√3)/2) i Find (z^4 + 2z)∙(z^3 + z) = ?

$$\mathrm{If}\:\:\:\boldsymbol{\mathrm{z}}\:=\:−\:\frac{\mathrm{1}}{\mathrm{2}}\:\:+\:\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:\boldsymbol{\mathrm{i}} \\ $$$$\mathrm{Find}\:\:\:\left(\mathrm{z}^{\mathrm{4}} \:+\:\mathrm{2z}\right)\centerdot\left(\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{z}\right)\:=\:? \\ $$

Question Number 208951 Answers: 1 Comments: 0

2^(2024) : 2024 = ... (Remainder = ?)

$$\mathrm{2}^{\mathrm{2024}} \::\:\mathrm{2024}\:=\:...\:\left(\mathrm{Remainder}\:=\:?\right) \\ $$

Question Number 208945 Answers: 1 Comments: 0

4 cos^2 x − 4 cos^2 3x cos x + cos^2 3x = 0 [ 0 ; (π/2) ] Find: x = ?

$$\mathrm{4}\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{x}\:−\:\mathrm{4}\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{3x}\:\mathrm{cos}\:\mathrm{x}\:+\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{3x}\:=\:\mathrm{0} \\ $$$$\left[\:\mathrm{0}\:;\:\frac{\pi}{\mathrm{2}}\:\right] \\ $$$$\mathrm{Find}:\:\:\mathrm{x}\:=\:? \\ $$

Question Number 208943 Answers: 1 Comments: 0

Question Number 208940 Answers: 1 Comments: 0

Question Number 208931 Answers: 1 Comments: 0

Question Number 208913 Answers: 3 Comments: 0

Question Number 208912 Answers: 0 Comments: 1

⋐ π

$$\:\:\:\underbrace{\Subset} \underbrace{ \cancel{} }\pi \\ $$

Question Number 208909 Answers: 0 Comments: 1

soit la fonction f(x)=x^3 +x definie sur R on note g(x)=f^(−1) (x) alors que la primitive G(x)=∫_0 ^x g(t)dt

$$\:\:\:\:\:\boldsymbol{{soit}}\:\boldsymbol{{la}}\:\boldsymbol{{fonction}}\:\boldsymbol{{f}}\left(\boldsymbol{{x}}\right)=\boldsymbol{{x}}^{\mathrm{3}} +\boldsymbol{{x}}\:\:\boldsymbol{{definie}} \\ $$$$\boldsymbol{{sur}}\:\mathbb{R}\:\boldsymbol{{on}}\:\boldsymbol{{note}}\:\boldsymbol{{g}}\left(\boldsymbol{{x}}\right)=\boldsymbol{{f}}^{−\mathrm{1}} \left(\boldsymbol{{x}}\right) \\ $$$$\boldsymbol{{alors}}\:\boldsymbol{{que}}\:\:\boldsymbol{{la}}\:\boldsymbol{{primitive}}\:\boldsymbol{{G}}\left(\boldsymbol{{x}}\right)=\int_{\mathrm{0}} ^{\boldsymbol{{x}}} \boldsymbol{{g}}\left(\boldsymbol{{t}}\right)\boldsymbol{{dt}} \\ $$

Question Number 208900 Answers: 0 Comments: 0

Does anyone know of an intuition behind the integral form of the remainder in Taylor′s theorem?

$${Does}\:{anyone}\:{know}\:{of}\:{an}\:{intuition} \\ $$$${behind}\:{the}\:{integral}\:{form}\:{of}\:{the} \\ $$$${remainder}\:{in}\:{Taylor}'{s}\:{theorem}? \\ $$

Question Number 208915 Answers: 1 Comments: 0

Question Number 208896 Answers: 2 Comments: 0

Question Number 208891 Answers: 0 Comments: 0

κ

$$\:\:\:\underline{\kappa} \\ $$

Question Number 208892 Answers: 2 Comments: 1

Find: (√(−16)) ∙ (√(−9)) = ?

$$\mathrm{Find}: \\ $$$$\sqrt{−\mathrm{16}}\:\:\centerdot\:\:\sqrt{−\mathrm{9}}\:\:=\:\:? \\ $$

Question Number 208880 Answers: 1 Comments: 0

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