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Question Number 211932 Answers: 0 Comments: 4

determiner R1 R2 et R3 segment de longueur a est tangent aux cercles 1et 2. MN//EF; EF=a; OM=ON=((3a)/2). (length a is tangent to cirles C1 (radius R1)and circldC2(radius R2)).

$$\mathrm{determiner}\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{1}\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{2}\:\mathrm{et}\:\boldsymbol{\mathrm{R}}\mathrm{3} \\ $$$$\mathrm{segment}\:\mathrm{de}\:\mathrm{longueur}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{est}}\:\boldsymbol{\mathrm{tangent}}\:\boldsymbol{\mathrm{aux}} \\ $$$$\boldsymbol{\mathrm{cercles}}\:\mathrm{1}\boldsymbol{\mathrm{et}}\:\mathrm{2}. \\ $$$$\:\boldsymbol{\mathrm{MN}}//\boldsymbol{\mathrm{EF}};\:\:\boldsymbol{\mathrm{EF}}=\boldsymbol{\mathrm{a}};\:\:\mathrm{OM}=\mathrm{ON}=\frac{\mathrm{3}\boldsymbol{\mathrm{a}}}{\mathrm{2}}. \\ $$$$\left(\mathrm{length}\:\boldsymbol{\mathrm{a}}\:\mathrm{is}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{cirles}\:\mathrm{C1}\:\left(\mathrm{radius}\:\mathrm{R1}\right)\mathrm{and}\:\mathrm{circldC2}\left(\mathrm{radius}\:\mathrm{R2}\right)\right). \\ $$

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Question Number 211886 Answers: 2 Comments: 0

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Question Number 211861 Answers: 1 Comments: 0

ab^(−) + ba^(−) = 4c a + b + 3c = ?

$$\overline {\mathrm{ab}}\:\:+\:\:\overline {\mathrm{ba}}\:\:=\:\:\mathrm{4c} \\ $$$$\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{3c}\:=\:? \\ $$

Question Number 211859 Answers: 0 Comments: 0

Question Number 211857 Answers: 1 Comments: 0

∫_1 ^∞ (((tan^(−1) x)/x)×((ln x)/x))dx=?

$$\underset{\mathrm{1}} {\overset{\infty} {\int}}\left(\frac{\mathrm{tan}^{−\mathrm{1}} \:{x}}{{x}}×\frac{\mathrm{ln}\:{x}}{{x}}\right){dx}=? \\ $$

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