Question and Answers Forum

AllQuestion and Answers: Page 1129

Question Number 103870 Answers: 0 Comments: 0

De^ montrer que la fonction f(x)=x^2 ∙sin((1/x)) admet un DL d′ordre 2.

$$\mathcal{D}\acute {\mathrm{e}montrer}\:\mathrm{que}\:\mathrm{la}\:\mathrm{fonction}\: \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{2}} \centerdot\mathrm{sin}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:\mathrm{admet}\:\mathrm{un}\:\mathrm{DL}\:\mathrm{d}'\mathrm{ordre}\:\mathrm{2}. \\ $$

Question Number 103869 Answers: 0 Comments: 0

by using the Frobinus method solve the deffrentional equation xy^(′′) −2pxy^′ +(p(p+1)+b^2 x^2 )y=0 and give for example for this when p=1,b=2 such that (p,b) be areal number ?

$${by}\:{using}\:{the}\:{Frobinus}\:{method}\:{solve}\:{the}\:{deffrentional}\:{equation} \\ $$$${xy}^{''} −\mathrm{2}{pxy}^{'} +\left({p}\left({p}+\mathrm{1}\right)+{b}^{\mathrm{2}} {x}^{\mathrm{2}} \right){y}=\mathrm{0} \\ $$$$ \\ $$$${and}\:{give}\:{for}\:{example}\:{for}\:{this}\:{when}\:{p}=\mathrm{1},{b}=\mathrm{2}\: \\ $$$${such}\:{that}\:\left({p},{b}\right)\:{be}\:{areal}\:{number}\:? \\ $$

Question Number 103863 Answers: 8 Comments: 0

Question Number 103862 Answers: 0 Comments: 0

Question Number 103860 Answers: 2 Comments: 0

find ∫ (dx/(cos^4 x))

$$\mathrm{find}\:\int\:\frac{\mathrm{dx}}{\mathrm{cos}^{\mathrm{4}} \mathrm{x}} \\ $$

Question Number 103846 Answers: 0 Comments: 2

∫(dx/(x^(1/3) +2))

$$\int\frac{{dx}}{{x}^{\frac{\mathrm{1}}{\mathrm{3}}} +\mathrm{2}} \\ $$

Question Number 103995 Answers: 1 Comments: 0

solve y^(′′) +2y^′ −y =(e^(−x) /x)

$$\mathrm{solve}\:\mathrm{y}^{''} +\mathrm{2y}^{'} −\mathrm{y}\:=\frac{\mathrm{e}^{−\mathrm{x}} }{\mathrm{x}} \\ $$

Question Number 103835 Answers: 0 Comments: 0

Question Number 103832 Answers: 1 Comments: 0

p(x) = x^4 +ax^3 +bx^2 +cx +d if p(1)=10,p(2)=20 and p(3)=30 . find ((p(12)+p(−8))/(10))

$${p}\left({x}\right)\:=\:{x}^{\mathrm{4}} +{ax}^{\mathrm{3}} +{bx}^{\mathrm{2}} +{cx}\:+{d} \\ $$$${if}\:{p}\left(\mathrm{1}\right)=\mathrm{10},{p}\left(\mathrm{2}\right)=\mathrm{20}\:{and} \\ $$$${p}\left(\mathrm{3}\right)=\mathrm{30}\:.\:{find}\:\frac{{p}\left(\mathrm{12}\right)+{p}\left(−\mathrm{8}\right)}{\mathrm{10}} \\ $$

Question Number 103828 Answers: 1 Comments: 0

min{ ∫_0 ^1 (x^3 −px−q)^2 dx , (p,q)∈R^2 }

$$\:\:\:\:\:{min}\left\{\:\int_{\mathrm{0}} ^{\mathrm{1}} \left({x}^{\mathrm{3}} −{px}−{q}\right)^{\mathrm{2}} {dx}\:,\:\:\left({p},{q}\right)\in\mathbb{R}^{\mathrm{2}} \:\right\} \\ $$

Question Number 103825 Answers: 7 Comments: 0

∫ (dx/((1−sinx)^2 )) ?

$$\int\:\frac{{dx}}{\left(\mathrm{1}−{sinx}\right)^{\mathrm{2}} }\:? \\ $$

Question Number 103826 Answers: 1 Comments: 0

In the expansion of (1+x)^(20) if the coefficient of x^r is twice the coefficient of x^(r−1) , what the value of the coefficient?

$${In}\:{the}\:{expansion}\:{of}\:\left(\mathrm{1}+{x}\right)^{\mathrm{20}} \:{if}\:{the} \\ $$$${coefficient}\:{of}\:{x}^{{r}} \:{is}\:{twice}\:{the}\:{coefficient} \\ $$$${of}\:{x}^{{r}−\mathrm{1}} ,\:{what}\:{the}\:{value}\:{of}\:{the} \\ $$$${coefficient}?\: \\ $$

Question Number 103823 Answers: 2 Comments: 0

tan (x) = 4 cos (2x)−cot (2x)

$$\mathrm{tan}\:\left({x}\right)\:=\:\mathrm{4}\:\mathrm{cos}\:\left(\mathrm{2}{x}\right)−\mathrm{cot}\:\left(\mathrm{2}{x}\right) \\ $$

Question Number 103820 Answers: 1 Comments: 0

∫_R ^ (e^(−2iπax) /((1+x^2 )^2 ))dx = πe^(−2πa) ((1/2)+πa) a>0

$$\:\:\:\int_{\mathbb{R}} ^{} \:\frac{{e}^{−\mathrm{2}{i}\pi{ax}} }{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx}\:=\:\pi{e}^{−\mathrm{2}\pi{a}} \left(\frac{\mathrm{1}}{\mathrm{2}}+\pi{a}\right)\:\:\:\:\:\:\:\:\:{a}>\mathrm{0} \\ $$

Question Number 103887 Answers: 1 Comments: 3

how do you prove sin (a+b) = sin a cos b + cos a sin b geometrically ?

$${how}\:{do}\:{you}\:{prove}\:\mathrm{sin}\:\left({a}+{b}\right)\:=\:\mathrm{sin} \\ $$$${a}\:\mathrm{cos}\:{b}\:+\:\mathrm{cos}\:{a}\:\mathrm{sin}\:{b} \\ $$$${geometrically}\:? \\ $$

Question Number 103804 Answers: 0 Comments: 0

Solve for r ((h−p^2 )/(p−r))=(1/(2p)) , ((h−q)/(q^2 −r))= 2q (h−p^2 )^2 +(p−r)^2 =r^2 (h−q)^2 +(q^2 −r)^2 =r^2

$$\:\:\:\boldsymbol{{S}}{olve}\:{for}\:\boldsymbol{{r}} \\ $$$$\:\:\frac{\boldsymbol{{h}}−\boldsymbol{{p}}^{\mathrm{2}} }{\boldsymbol{{p}}−\boldsymbol{{r}}}=\frac{\mathrm{1}}{\mathrm{2}\boldsymbol{{p}}}\:\:\:\:,\:\:\:\:\frac{\boldsymbol{{h}}−\boldsymbol{{q}}}{\boldsymbol{{q}}^{\mathrm{2}} −\boldsymbol{{r}}}=\:\mathrm{2}\boldsymbol{{q}} \\ $$$$\left(\boldsymbol{{h}}−\boldsymbol{{p}}^{\mathrm{2}} \right)^{\mathrm{2}} +\left(\boldsymbol{{p}}−\boldsymbol{{r}}\right)^{\mathrm{2}} =\boldsymbol{{r}}^{\mathrm{2}} \\ $$$$\:\left(\boldsymbol{{h}}−\boldsymbol{{q}}\right)^{\mathrm{2}} +\left(\boldsymbol{{q}}^{\mathrm{2}} −\boldsymbol{{r}}\right)^{\mathrm{2}} =\boldsymbol{{r}}^{\mathrm{2}} \\ $$

Question Number 103792 Answers: 2 Comments: 0

Question Number 103790 Answers: 1 Comments: 1

Question Number 103788 Answers: 1 Comments: 0

y′′−y = cot x

$${y}''−{y}\:=\:\mathrm{cot}\:{x}\: \\ $$

Question Number 105290 Answers: 2 Comments: 0

Given ((sin 2a−sin 2b)/(cos 2a+cos 2b)) = (2/3) find the value of cos (a−b)

$$\mathcal{G}{iven}\:\frac{\mathrm{sin}\:\mathrm{2}{a}−\mathrm{sin}\:\mathrm{2}{b}}{\mathrm{cos}\:\mathrm{2}{a}+\mathrm{cos}\:\mathrm{2}{b}}\:=\:\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${find}\:{the}\:{value}\:{of}\:\mathrm{cos}\:\left({a}−{b}\right)\: \\ $$

Question Number 105289 Answers: 1 Comments: 0

(√(52))+(√3)−(√(4/6)) = ?

$$\sqrt{\mathrm{52}}+\sqrt{\mathrm{3}}−\sqrt{\frac{\mathrm{4}}{\mathrm{6}}}\:=\:? \\ $$

Question Number 103781 Answers: 0 Comments: 4

Question Number 103780 Answers: 1 Comments: 0

the third, sixth and seventh terms of a geometric progression (whose common ratio is neither 0 nor 1 ) are in arithmetic progression . prove that the sum of the first three terms is equal to fourth .

$${the}\:{third},\:{sixth}\:{and}\:{seventh}\:{terms}\:{of}\:{a} \\ $$$${geometric}\:{progression}\:\left({whose}\:{common}\right. \\ $$$$\left.{ratio}\:{is}\:{neither}\:\mathrm{0}\:{nor}\:\mathrm{1}\:\right)\:{are}\:{in} \\ $$$${arithmetic}\:{progression}\:.\:{prove}\:{that}\:{the} \\ $$$${sum}\:{of}\:{the}\:{first}\:{three}\:{terms}\:{is}\:{equal}\:{to} \\ $$$${fourth}\:. \\ $$

Question Number 103776 Answers: 2 Comments: 0

y′ − (y/(x^2 −1)) = y^2

$${y}'\:−\:\frac{{y}}{{x}^{\mathrm{2}} −\mathrm{1}}\:=\:{y}^{\mathrm{2}} \\ $$

Question Number 103774 Answers: 1 Comments: 0

Question Number 103773 Answers: 1 Comments: 0

∫_c ((x^2 +2xy^2 )dx+(x^2 y^2 −1)dy) where C is the boundary of region define by y^2 = 4x and y =1 ?

$$\int_{{c}} \left(\left({x}^{\mathrm{2}} +\mathrm{2}{xy}^{\mathrm{2}} \right){dx}+\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} −\mathrm{1}\right){dy}\right) \\ $$$${where}\:{C}\:{is}\:{the}\:{boundary}\:{of} \\ $$$${region}\:{define}\:{by}\:{y}^{\mathrm{2}} =\:\mathrm{4}{x}\:{and}\:{y} \\ $$$$=\mathrm{1}\:? \\ $$

Pg 1124 Pg 1125 Pg 1126 Pg 1127 Pg 1128 Pg 1129 Pg 1130 Pg 1131 Pg 1132 Pg 1133

Contact: info@tinkutara.com