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AllQuestion and Answers: Page 1129

Question Number 101489 Answers: 1 Comments: 0

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Question Number 101447 Answers: 0 Comments: 6

To sir Tinkutara: please sir can you help us with a development which allows our maths work which is saved to be converted directly to a portable document format(PDF)?

$$\mathrm{To}\:\mathrm{sir}\:\mathrm{Tinkutara}:\:\mathrm{please}\:\mathrm{sir}\:\mathrm{can}\:\mathrm{you}\:\mathrm{help}\:\mathrm{us} \\ $$$$\mathrm{with}\:\mathrm{a}\:\mathrm{development}\:\mathrm{which}\:\mathrm{allows}\:\mathrm{our}\:\mathrm{maths}\:\mathrm{work} \\ $$$$\mathrm{which}\:\mathrm{is}\:\mathrm{saved}\:\mathrm{to}\:\mathrm{be}\:\mathrm{converted}\:\mathrm{directly}\:\mathrm{to}\:\mathrm{a}\: \\ $$$$\mathrm{portable}\:\mathrm{document}\:\mathrm{format}\left(\mathrm{PDF}\right)?\: \\ $$

Question Number 101439 Answers: 0 Comments: 10

Question Number 101436 Answers: 1 Comments: 0

Question Number 101425 Answers: 3 Comments: 2

A student wrote three papers in mathematics examinations. Her marks for the two of papers were 77 and 72 respectively. To obtain grade A, an average of not less than 75 marks is required for the three papers. How many marks must she get in the third paper to get grade A?

$$\mathrm{A}\:\mathrm{student}\:\mathrm{wrote}\:\mathrm{three}\:\mathrm{papers}\:\mathrm{in}\:\mathrm{mathematics} \\ $$$$\mathrm{examinations}.\:\mathrm{Her}\:\mathrm{marks}\:\mathrm{for}\:\mathrm{the}\:\mathrm{two}\:\mathrm{of} \\ $$$$\mathrm{papers}\:\mathrm{were}\:\mathrm{77}\:\mathrm{and}\:\mathrm{72}\:\mathrm{respectively}.\:\mathrm{To} \\ $$$$\mathrm{obtain}\:\mathrm{grade}\:\mathrm{A},\:\mathrm{an}\:\mathrm{average}\:\mathrm{of}\:\mathrm{not}\:\mathrm{less} \\ $$$$\mathrm{than}\:\mathrm{75}\:\mathrm{marks}\:\mathrm{is}\:\mathrm{required}\:\mathrm{for}\:\mathrm{the}\:\mathrm{three} \\ $$$$\mathrm{papers}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{marks}\:\mathrm{must}\:\mathrm{she}\:\mathrm{get} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{third}\:\mathrm{paper}\:\mathrm{to}\:\mathrm{get}\:\mathrm{grade}\:\mathrm{A}? \\ $$

Question Number 101422 Answers: 0 Comments: 2

lim_(h→0 ) ((sin ((α+h)^2 )−sin (α^2 ))/(cos ((α+h)^2 sin (α+h)−cos (α^2 )sin (α))) =?

$$\underset{\mathrm{h}\rightarrow\mathrm{0}\:} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\left(\left(\alpha+\mathrm{h}\right)^{\mathrm{2}} \right)−\mathrm{sin}\:\left(\alpha^{\mathrm{2}} \right)}{\mathrm{cos}\:\left(\left(\alpha+\mathrm{h}\right)^{\mathrm{2}} \mathrm{sin}\:\left(\alpha+\mathrm{h}\right)−\mathrm{cos}\:\left(\alpha^{\mathrm{2}} \right)\mathrm{sin}\:\left(\alpha\right)\right.}\:=? \\ $$

Question Number 101419 Answers: 2 Comments: 0

y′′−4y′+3y = (e^x /(1+e^x ))

$$\mathrm{y}''−\mathrm{4y}'+\mathrm{3y}\:=\:\frac{\mathrm{e}^{\mathrm{x}} }{\mathrm{1}+\mathrm{e}^{\mathrm{x}} } \\ $$

Question Number 101418 Answers: 0 Comments: 6

Find 2020 term from series (1/1),(2/1),(1/2),(3/1),(2/2),(1/3),(4/1),(3/2),(2/3),(1/4) ,(5/1),(4/2),... is ___ (A) ((2019)/(2020)) (B) ((61)/4) (C)((63)/1) (D) ((96)/4) (E) ((2020)/(2019))

$$\mathrm{Find}\:\mathrm{2020}\:\mathrm{term}\:\mathrm{from}\:\mathrm{series} \\ $$$$\frac{\mathrm{1}}{\mathrm{1}},\frac{\mathrm{2}}{\mathrm{1}},\frac{\mathrm{1}}{\mathrm{2}},\frac{\mathrm{3}}{\mathrm{1}},\frac{\mathrm{2}}{\mathrm{2}},\frac{\mathrm{1}}{\mathrm{3}},\frac{\mathrm{4}}{\mathrm{1}},\frac{\mathrm{3}}{\mathrm{2}},\frac{\mathrm{2}}{\mathrm{3}},\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$,\frac{\mathrm{5}}{\mathrm{1}},\frac{\mathrm{4}}{\mathrm{2}},...\:\mathrm{is}\:\_\_\_ \\ $$$$\left(\mathrm{A}\right)\:\frac{\mathrm{2019}}{\mathrm{2020}}\:\:\:\:\:\:\left(\mathrm{B}\right)\:\frac{\mathrm{61}}{\mathrm{4}}\:\:\:\:\:\left(\mathrm{C}\right)\frac{\mathrm{63}}{\mathrm{1}} \\ $$$$\left(\mathrm{D}\right)\:\frac{\mathrm{96}}{\mathrm{4}}\:\:\:\:\:\:\left(\mathrm{E}\right)\:\frac{\mathrm{2020}}{\mathrm{2019}} \\ $$

Question Number 101409 Answers: 0 Comments: 1

which is correct ∫((5x^4 +4x^5 )/((x^5 +x+1)^2 )) dx is equal to a) (x^5 /(x^5 +x+1)) b)−((x+1)/(x^5 +x+1))

$$\mathrm{which}\:\mathrm{is}\:\mathrm{correct} \\ $$$$\int\frac{\mathrm{5x}^{\mathrm{4}} +\mathrm{4x}^{\mathrm{5}} }{\left(\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }\:\mathrm{dx}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left.\mathrm{a}\left.\right)\:\frac{\mathrm{x}^{\mathrm{5}} }{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{b}\right)−\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}} \\ $$

Question Number 101393 Answers: 1 Comments: 0

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App Updates: Show and Hide Keyboard Request by teachers using this app along with screen sharing apps for online classes Set Home Screen to Forum Requested by Mr W

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Question Number 105239 Answers: 1 Comments: 0

Σ_(Σ_(p=5) ^6 p) ^(Σ_(p=8) ^(11) p) ∫_(11) ^(13) (((12ky)/x^2 ) + 6x) dx = Σ_(Σ_(p=4) ^7 p) ^(Σ_(p=9) ^(12) p) ∫_(11) ^(16) (x^2 y−(3/2)k)dx solve for y

$$\underset{\underset{{p}=\mathrm{5}} {\overset{\mathrm{6}} {\sum}}{p}} {\overset{\underset{{p}=\mathrm{8}} {\overset{\mathrm{11}} {\sum}}{p}} {\sum}}\:\underset{\mathrm{11}} {\overset{\mathrm{13}} {\int}}\left(\frac{\mathrm{12}{ky}}{{x}^{\mathrm{2}} }\:+\:\mathrm{6}{x}\right)\:{dx}\:=\:\underset{\underset{{p}=\mathrm{4}} {\overset{\mathrm{7}} {\sum}}{p}} {\overset{\underset{{p}=\mathrm{9}} {\overset{\mathrm{12}} {\sum}}{p}} {\sum}}\:\underset{\mathrm{11}} {\overset{\mathrm{16}} {\int}}\left({x}^{\mathrm{2}} {y}−\frac{\mathrm{3}}{\mathrm{2}}{k}\right){dx} \\ $$$${solve}\:{for}\:{y} \\ $$

Question Number 105238 Answers: 1 Comments: 0

(dy/dx) = (1/(3e^y −2x)) ?

$$\frac{{dy}}{{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{3}{e}^{{y}} −\mathrm{2}{x}}\:? \\ $$

Question Number 101378 Answers: 2 Comments: 1

∫_(1/e) ^(tanx) (t/(1+t^2 ))dt + ∫_(1/e) ^(cotx) (1/(t(1+t^2 )))dt

$$\int_{\frac{\mathrm{1}}{{e}}} ^{{tanx}} \frac{{t}}{\mathrm{1}+{t}^{\mathrm{2}} }{dt}\:+\:\int_{\frac{\mathrm{1}}{{e}}} ^{{cotx}} \frac{\mathrm{1}}{{t}\left(\mathrm{1}+{t}^{\mathrm{2}} \right)}{dt} \\ $$

Question Number 101375 Answers: 1 Comments: 4

Question Number 101373 Answers: 0 Comments: 1

lim_(n→∞ ) Σ_(r=1) ^(4n) ((√n)/((√r)(3(√r)+4(√n))^2 ))

$$\underset{{n}\rightarrow\infty\:} {\mathrm{lim}}\underset{{r}=\mathrm{1}} {\overset{\mathrm{4}{n}} {\sum}}\frac{\sqrt{{n}}}{\sqrt{{r}}\left(\mathrm{3}\sqrt{{r}}+\mathrm{4}\sqrt{{n}}\right)^{\mathrm{2}} } \\ $$

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