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Question Number 109909 Answers: 2 Comments: 6
Question Number 109905 Answers: 1 Comments: 0
Question Number 109901 Answers: 1 Comments: 0
$${If}\:{first}\:{n}\:{terms}\:{of}\:{an}\:{A}.{P}.\:{is}\:{cn}^{\mathrm{2}} , \\ $$$${find}\:{sum}\:{of}\:{squares}\:{of}\:{its}\:{first} \\ $$$${n}\:{terms}. \\ $$
Question Number 109895 Answers: 1 Comments: 3
Question Number 109891 Answers: 1 Comments: 0
$$\:\:\frac{\Delta{be}\bigtriangledown}{{math}} \\ $$$$\int\:\frac{\mathrm{arc}\:\mathrm{tan}\:{x}}{\left(\mathrm{1}+\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)}\:{dx}\:? \\ $$
Question Number 109888 Answers: 3 Comments: 0
$$\mathrm{2}^{{x}+\mathrm{5}} =\sqrt{\mathrm{8}^{{x}} } \\ $$
Question Number 109884 Answers: 1 Comments: 1
Question Number 109872 Answers: 2 Comments: 1
$$\:\:\frac{\bigstar{be}\bigstar}{\mathcal{M}{ath}} \\ $$$$\int\:\frac{\mathrm{cos}\:{x}\:{dx}}{\mathrm{sin}\:^{\mathrm{2}} {x}+\mathrm{4sin}\:{x}−\mathrm{5}}\:? \\ $$
Question Number 109863 Answers: 1 Comments: 0
Question Number 109861 Answers: 3 Comments: 0
$$\:\:\frac{{JS}}{\blacksquare\bigstar\bigstar\blacksquare} \\ $$$$\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\mathrm{5}−\mathrm{2}{x}+\sqrt{{x}−\mathrm{2}}}{{x}−\mathrm{4}+\sqrt{{x}−\mathrm{2}}}\:? \\ $$
Question Number 109858 Answers: 3 Comments: 0
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{for}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{3}.\:\mathrm{12}.\:\mathrm{27}.\:\mathrm{48}.\:\mathrm{75}... \\ $$
Question Number 109855 Answers: 3 Comments: 0
Question Number 109854 Answers: 4 Comments: 1
$$\:\frac{\bigstar{be}\bigstar}{{math}} \\ $$$$\left(\mathrm{1}\right)\int\:\frac{\mathrm{3}+\mathrm{2cos}\:{x}}{\left(\mathrm{2}+\mathrm{3cos}\:{x}\right)^{\mathrm{3}} }\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\left(\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}\:\right)^{{y}} −\left(\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}\:\right)^{{y}} \:=\:\mathrm{14} \\ $$$$\:\:\:\:\:{y}=? \\ $$
Question Number 109853 Answers: 0 Comments: 2
$${is}\:{there}\:{any}\:{diffrence}\:{between}\:{greatest} \\ $$$${coefficient}\:{and}\:{largest}\:{coefficient}? \\ $$
Question Number 109849 Answers: 0 Comments: 0
Question Number 109852 Answers: 0 Comments: 1
$${pls}\:{is}\:{there}\:{anyone}\:{with}\:{any}\:{material}\:{that} \\ $$$${can}\:{help}\:{me}\:{for}\:{binomial}\:{expansion}\:{for} \\ $$$${negative}\:{powers} \\ $$
Question Number 109839 Answers: 4 Comments: 1
$$\:\frac{{JS}}{\approx\heartsuit\approx} \\ $$$$\left(\mathrm{1}\right)\:\int\:\frac{\sqrt{{x}+\mathrm{1}}−\sqrt{{x}−\mathrm{1}}}{\:\sqrt{{x}+\mathrm{1}}+\sqrt{{x}−\mathrm{1}}}\:{dx} \\ $$$$\left(\mathrm{2}\right)\:\int\:\frac{\sqrt{\mathrm{tan}\:{x}}}{\mathrm{1}+\sqrt{\mathrm{tan}\:{x}}\:}\:{dx}\: \\ $$
Question Number 109838 Answers: 1 Comments: 0
$$ \\ $$$$ \\ $$$$\:\:\:\:{please}\:{prove}::: \\ $$$$\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}}}{log}\left(\frac{{x}}{\mathrm{1}−{x}}\right){dx}\:=\mathrm{4}{log}\left(\mathrm{2}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$$$ \\ $$
Question Number 109834 Answers: 3 Comments: 1
Question Number 109823 Answers: 1 Comments: 1
Question Number 109820 Answers: 0 Comments: 2
$${tan}^{\mathrm{2}} {x}+{tan}^{\mathrm{2}} \mathrm{2}{x}+{tan}^{\mathrm{2}} \mathrm{4}{x}=\mathrm{33} \\ $$$${find}\:{x}\:\:\:\left({show}\:{full}\:{solution}\:{please}\right) \\ $$
Question Number 109818 Answers: 1 Comments: 7
$${tanx}+{tan}\mathrm{2}{x}=\mathrm{1} \\ $$$${find}\:{the}\:{general}\:{solution} \\ $$
Question Number 109817 Answers: 0 Comments: 1
Question Number 109806 Answers: 0 Comments: 0
$$\mathrm{a}\:\mathrm{handy}\:\mathrm{little}\:\mathrm{formula}\:\mathrm{to}\:\mathrm{remember} \\ $$$$\left.\mathrm{in}\:\mathrm{case}\:\mathrm{you}\:\mathrm{forget}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{3}\::\right) \\ $$$$ \\ $$$$\:\:\:^{\frac{\mathrm{2}}{\left(\frac{\mathrm{log}_{\mathrm{2}} \left(\mathrm{3}\right)}{\mathrm{2}}\right)}} \sqrt{\mathrm{2}^{\mathrm{4}} }=\mathrm{3} \\ $$
Question Number 109801 Answers: 0 Comments: 2
$$\mathrm{calculste}\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{6}} }\mathrm{dx} \\ $$
Question Number 109794 Answers: 0 Comments: 0
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