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Question Number 109754    Answers: 1   Comments: 0

1.specify value absolute x if ? b.∣2x+3∣+x−3=0

$$\mathrm{1}.{specify}\:{value}\:{absolute}\:{x}\:{if}\:? \\ $$$$ \\ $$$${b}.\mid\mathrm{2}{x}+\mathrm{3}\mid+{x}−\mathrm{3}=\mathrm{0} \\ $$$$ \\ $$

Question Number 109750    Answers: 2   Comments: 0

Question Number 109749    Answers: 1   Comments: 0

Question Number 109746    Answers: 0   Comments: 3

Find the value of Σ_(n = 0) ^(2020) [(2^n /(1 + 3^((2^n )) ))]

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\underset{{n}\:=\:\mathrm{0}} {\overset{\mathrm{2020}} {\sum}}\:\left[\frac{\mathrm{2}^{{n}} }{\mathrm{1}\:+\:\mathrm{3}^{\left(\mathrm{2}^{{n}} \right)} }\right] \\ $$

Question Number 109738    Answers: 4   Comments: 1

(((x/y)−(y/x))/((x^2 +2xy+y^2 )/(x^2 −y^2 )))=(9/4) (x/y)=?

$$\frac{\frac{\mathrm{x}}{\mathrm{y}}−\frac{\mathrm{y}}{\mathrm{x}}}{\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2xy}+\mathrm{y}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} }}=\frac{\mathrm{9}}{\mathrm{4}} \\ $$$$\frac{\mathrm{x}}{\mathrm{y}}=? \\ $$

Question Number 109736    Answers: 1   Comments: 0

please solve : lim_(n→∞) ((1 +(√2) +(3)^(1/3) +(4)^(1/4) +......((2n))^(1/(2n)) )/(3n−4)) =???

$$\:\:\:\:{please}\:{solve}\:: \\ $$$$\:\: \\ $$$${lim}_{{n}\rightarrow\infty} \frac{\mathrm{1}\:+\sqrt{\mathrm{2}}\:+\sqrt[{\mathrm{3}}]{\mathrm{3}}\:+\sqrt[{\mathrm{4}}]{\mathrm{4}}\:+......\sqrt[{\mathrm{2}{n}}]{\mathrm{2}{n}}}{\mathrm{3}{n}−\mathrm{4}} \\ $$$$=??? \\ $$

Question Number 109724    Answers: 4   Comments: 0

y = (√(x+(√(x+(√x))))) ⇒ (dy/dx) ?

$$\:\:{y}\:=\:\sqrt{{x}+\sqrt{{x}+\sqrt{{x}}}}\:\Rightarrow\:\frac{{dy}}{{dx}}\:?\: \\ $$

Question Number 109721    Answers: 1   Comments: 0

Question Number 109722    Answers: 2   Comments: 1

⊸((♭ε)/(math))⊸ lim_(x→0) ((sin x)/( (√(1−cos x)))) = ?

$$\:\:\:\:\:\multimap\frac{\flat\epsilon}{{math}}\multimap \\ $$$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:{x}}{\:\sqrt{\mathrm{1}−\mathrm{cos}\:{x}}}\:=\:?\: \\ $$

Question Number 109715    Answers: 1   Comments: 0

{ ((sin 2x+sin 2y=(5/4))),((cos (x−y)=2sin (x+y))) :}where 0<x,y<(π/2) cos^2 (x+y) = ? △((♭o♭)/(hans))▽

$$\begin{cases}{\mathrm{sin}\:\mathrm{2}{x}+\mathrm{sin}\:\mathrm{2}{y}=\frac{\mathrm{5}}{\mathrm{4}}}\\{\mathrm{cos}\:\left({x}−{y}\right)=\mathrm{2sin}\:\left({x}+{y}\right)}\end{cases}{where}\:\mathrm{0}<{x},{y}<\frac{\pi}{\mathrm{2}} \\ $$$$\:\:\:\:\:\mathrm{cos}\:^{\mathrm{2}} \left({x}+{y}\right)\:=\:? \\ $$$$\:\:\:\:\:\:\bigtriangleup\frac{\flat{o}\flat}{{hans}}\bigtriangledown \\ $$

Question Number 109734    Answers: 1   Comments: 0

solve the following integral 1)∫_3 ^7 4(√((x−3)(7−x)))dx 2)∫_0 ^∞ ((xln^2 (1+x))/((1+x)^3 ))dx 3)∫_0 ^(π/4) [ln(1−tanx)]^2 dx=(π/2)ln2−2G 4)∫_0 ^(π/4) ln(1+cotx)dx=(π/8)ln2+G 5)∫_0 ^(π/2) ln(2+cosx)dx

$${solve}\:{the}\:{following}\:{integral} \\ $$$$\left.\mathrm{1}\right)\int_{\mathrm{3}} ^{\mathrm{7}} \mathrm{4}\sqrt{\left({x}−\mathrm{3}\right)\left(\mathrm{7}−{x}\right)}{dx} \\ $$$$\left.\mathrm{2}\right)\int_{\mathrm{0}} ^{\infty} \frac{{x}\mathrm{ln}^{\mathrm{2}} \left(\mathrm{1}+{x}\right)}{\left(\mathrm{1}+{x}\right)^{\mathrm{3}} }{dx} \\ $$$$\left.\mathrm{3}\right)\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \left[\mathrm{ln}\left(\mathrm{1}−\mathrm{tan}{x}\right)\right]^{\mathrm{2}} {dx}=\frac{\pi}{\mathrm{2}}\mathrm{ln2}−\mathrm{2}{G} \\ $$$$\left.\mathrm{4}\right)\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{ln}\left(\mathrm{1}+\mathrm{cot}{x}\right){dx}=\frac{\pi}{\mathrm{8}}\mathrm{ln2}+{G} \\ $$$$\left.\mathrm{5}\right)\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{ln}\left(\mathrm{2}+\mathrm{cos}{x}\right){dx} \\ $$

Question Number 109733    Answers: 2   Comments: 0

lim_(x→0) ((x−tan x)/(sin x−x)) ?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−\mathrm{tan}\:{x}}{\mathrm{sin}\:{x}−{x}}\:? \\ $$

Question Number 109709    Answers: 2   Comments: 0

∫_(0 ) ^(π/4) ln(tanx+1)dx

$$\:\:\:\:\:\int_{\mathrm{0}\:} ^{\frac{\pi}{\mathrm{4}}} \mathrm{ln}\left(\mathrm{tanx}+\mathrm{1}\right)\mathrm{dx} \\ $$

Question Number 109729    Answers: 3   Comments: 0

Question Number 109728    Answers: 4   Comments: 1

△((♭ε)/(math))▽ lim_(x→π) ((sin^2 x)/(cos 3x+1))

$$\:\:\:\bigtriangleup\frac{\flat\epsilon}{{math}}\bigtriangledown \\ $$$$\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{sin}\:^{\mathrm{2}} {x}}{\mathrm{cos}\:\mathrm{3}{x}+\mathrm{1}} \\ $$

Question Number 109699    Answers: 1   Comments: 0

x(x−1)^2 ≥ 12(x−1)

$$\:\:\:\:\:{x}\left({x}−\mathrm{1}\right)^{\mathrm{2}} \:\geqslant\:\mathrm{12}\left({x}−\mathrm{1}\right) \\ $$

Question Number 109674    Answers: 2   Comments: 0

Find the area of the region enclose by the curve y = 1 − x^2 , and the line y = 1 + 3x, x = 1.

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\:\mathrm{enclose}\:\mathrm{by}\:\mathrm{the}\:\mathrm{curve}\:\:\:\mathrm{y}\:\:=\:\:\mathrm{1}\:\:−\:\:\mathrm{x}^{\mathrm{2}} \:, \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{line}\:\:\:\:\mathrm{y}\:\:=\:\:\mathrm{1}\:\:+\:\:\mathrm{3x},\:\:\:\:\mathrm{x}\:\:=\:\:\mathrm{1}. \\ $$

Question Number 109658    Answers: 1   Comments: 0

Question Number 109848    Answers: 0   Comments: 0

Question Number 109655    Answers: 0   Comments: 0

Question Number 109642    Answers: 1   Comments: 0

Question Number 109640    Answers: 0   Comments: 2

Question Number 109639    Answers: 2   Comments: 0

Question Number 109626    Answers: 1   Comments: 1

Question Number 109625    Answers: 0   Comments: 2

((sin 2𝛂+2sin 𝛂∙cos 2𝛂)/(1+cos 𝛂+cos2 𝛂+cos3 𝛂))

$$\frac{\mathrm{sin}\:\mathrm{2}\boldsymbol{\alpha}+\mathrm{2sin}\:\boldsymbol{\alpha}\centerdot\mathrm{cos}\:\mathrm{2}\boldsymbol{\alpha}}{\mathrm{1}+\mathrm{cos}\:\boldsymbol{\alpha}+\mathrm{cos2}\:\boldsymbol{\alpha}+\mathrm{cos3}\:\boldsymbol{\alpha}} \\ $$

Question Number 109619    Answers: 0   Comments: 2

Σ_(n=1) ^∞ ((n!)/n^n )

$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{n}!}{{n}^{{n}} } \\ $$

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