(−1)^π =?
(−1)^((22)/7)
=(−1)^(3+(1/7))
=(−1)^3 .(−1)^(1/7)
=−(−1)^(1/7)
let (−1)^π =t
⇒−(−1)^(1/7) =t
⇒(−1)^(1/7) =−t
⇒(−1)=(−t)^7
⇒−1=−t^7
⇒1=t^7
hence t=1
∴(−1)^π =1
i request all math
professionals to
check this and if
any error then pls
comment.