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verify the formulae Σ_(n=−∞) ^(+∞) (1/((na +1)^p )) =−(π/a^n ) lim_(z→−(1/a)) (1/((p−1)!)){cotan(πz)}^((p−1)) inthis case 1) a =1 and p=2 2) a=2 and p=2 3)a=2 and p=3 4) a=3 and p=2

$$\mathrm{verify}\:\mathrm{the}\:\mathrm{formulae} \\ $$$$\sum_{\mathrm{n}=−\infty} ^{+\infty} \:\frac{\mathrm{1}}{\left(\mathrm{na}\:+\mathrm{1}\right)^{\mathrm{p}} }\:=−\frac{\pi}{\mathrm{a}^{\mathrm{n}} }\:\mathrm{lim}_{\mathrm{z}\rightarrow−\frac{\mathrm{1}}{\mathrm{a}}} \:\:\:\frac{\mathrm{1}}{\left(\mathrm{p}−\mathrm{1}\right)!}\left\{\mathrm{cotan}\left(\pi\mathrm{z}\right)\right\}^{\left(\mathrm{p}−\mathrm{1}\right)} \\ $$$$\left.\mathrm{inthis}\:\mathrm{case}\:\:\mathrm{1}\right)\:\:\mathrm{a}\:=\mathrm{1}\:\mathrm{and}\:\mathrm{p}=\mathrm{2} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{a}=\mathrm{2}\:\:\:\mathrm{and}\:\mathrm{p}=\mathrm{2} \\ $$$$\left.\mathrm{3}\right)\mathrm{a}=\mathrm{2}\:\mathrm{and}\:\mathrm{p}=\mathrm{3} \\ $$$$\left.\mathrm{4}\right)\:\mathrm{a}=\mathrm{3}\:\mathrm{and}\:\mathrm{p}=\mathrm{2} \\ $$

Question Number 110953 Answers: 0 Comments: 1

Question Number 110951 Answers: 2 Comments: 0

Question Number 110948 Answers: 1 Comments: 6

(√(bemath)) If each point on the line 3x+4y=2 is transformed by matrix M= (((2 0)),((0 1)) ) , the image is a line ___

$$\:\:\:\:\:\sqrt{\mathrm{bemath}} \\ $$$$\mathrm{If}\:\mathrm{each}\:\mathrm{point}\:\mathrm{on}\:\mathrm{the}\:\mathrm{line}\:\mathrm{3x}+\mathrm{4y}=\mathrm{2} \\ $$$$\mathrm{is}\:\mathrm{transformed}\:\mathrm{by}\:\mathrm{matrix}\:\mathrm{M}=\begin{pmatrix}{\mathrm{2}\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\mathrm{1}}\end{pmatrix}\:,\:\mathrm{the} \\ $$$$\mathrm{image}\:\mathrm{is}\:\mathrm{a}\:\mathrm{line}\:\_\_\_ \\ $$

Question Number 110944 Answers: 5 Comments: 3

■(√(bemath))★ (1)If (√a) −(√b) = 20 , a,b∈R , find maximum value of a−5b ? (2)lim_(x→4) (((√x)−(√(3(√x)−2)))/(x^2 −16)) ? (3)∫ ((tan (ln x) tan (ln ((x/2))))/x) dx (4)((((√(3x−7)))^2 −2)/(x−3)) ≤ ((3−((√x))^2 )/(x−3))

$$\:\:\:\blacksquare\sqrt{\mathrm{bemath}}\bigstar \\ $$$$\left(\mathrm{1}\right)\mathrm{If}\:\sqrt{\mathrm{a}}\:−\sqrt{\mathrm{b}}\:=\:\mathrm{20}\:,\:\mathrm{a},\mathrm{b}\in\mathbb{R}\:,\:\mathrm{find}\:\mathrm{maximum} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{a}−\mathrm{5b}\:? \\ $$$$\left(\mathrm{2}\right)\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\frac{\sqrt{\mathrm{x}}−\sqrt{\mathrm{3}\sqrt{\mathrm{x}}−\mathrm{2}}}{\mathrm{x}^{\mathrm{2}} −\mathrm{16}}\:? \\ $$$$\left(\mathrm{3}\right)\int\:\frac{\mathrm{tan}\:\left(\mathrm{ln}\:\mathrm{x}\right)\:\mathrm{tan}\:\left(\mathrm{ln}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)}{\mathrm{x}}\:\mathrm{dx} \\ $$$$\left(\mathrm{4}\right)\frac{\left(\sqrt{\mathrm{3x}−\mathrm{7}}\right)^{\mathrm{2}} −\mathrm{2}}{\mathrm{x}−\mathrm{3}}\:\leqslant\:\frac{\mathrm{3}−\left(\sqrt{\mathrm{x}}\right)^{\mathrm{2}} }{\mathrm{x}−\mathrm{3}} \\ $$

Question Number 110939 Answers: 2 Comments: 1

Question Number 110926 Answers: 1 Comments: 0

A 2000kg car start from rest and accelerated to a final velocity of 20m/s in 16 seconds. Assuming a constant air resistance of 500N, find (i) the average power developed by the engine of the car. (ii) the instantaneous power developed by the engine when the car reaches its final speed.

$$\mathrm{A}\:\mathrm{2000kg}\:\mathrm{car}\:\mathrm{start}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{and} \\ $$$$\mathrm{accelerated}\:\mathrm{to}\:\mathrm{a}\:\mathrm{final}\:\mathrm{velocity}\:\mathrm{of} \\ $$$$\mathrm{20m}/\mathrm{s}\:\mathrm{in}\:\mathrm{16}\:\mathrm{seconds}.\:\mathrm{Assuming}\:\mathrm{a} \\ $$$$\mathrm{constant}\:\mathrm{air}\:\mathrm{resistance}\:\mathrm{of}\:\mathrm{500N},\:\mathrm{find} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{the}\:\mathrm{average}\:\mathrm{power}\:\mathrm{developed}\:\mathrm{by} \\ $$$$\mathrm{the}\:\mathrm{engine}\:\mathrm{of}\:\mathrm{the}\:\mathrm{car}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{the}\:\mathrm{instantaneous}\:\mathrm{power} \\ $$$$\mathrm{developed}\:\mathrm{by}\:\mathrm{the}\:\mathrm{engine}\:\mathrm{when}\:\mathrm{the}\:\mathrm{car} \\ $$$$\mathrm{reaches}\:\mathrm{its}\:\mathrm{final}\:\mathrm{speed}. \\ $$

Question Number 110970 Answers: 2 Comments: 1

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