The coordinates of two points A
& B are (0,8) and (9,4)
respectively. The point P with
coordinate (p,0) lies on the
x−axis where 0<p<9. Let s
denotes the sum of the length of
two segments PA and PB . by
expressing s in terms of p
otherwise, show that (ds/dp) =
(p/(√(64+p^2 ))) − ((9−p)/(√(16+(9−p)^2 )))
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