Developed the formula for the cubic
equation when it has three real roots
and Cardano is just not suitable as
discriminant gets negative..
Given x^3 −bx−c=0
with b>0 , c>0
(t/b)=1+((15)/2)((c^2 /b^3 ))+(√(((c^2 /b^3 ))[49−((75)/4)((c^2 /b^3 ))]))
x=(√(t+((4c^2 )/b^2 ))) −((3c)/b) ★
mrW Sir, MjS Sir please check!
if (x^2 −(h+1)x+6i−6=0) then find the value of h
if you know that one of the roots of the equation is three
times the square of the other root
(h∈ complex number)