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Question Number 114699    Answers: 1   Comments: 1

∫_0 ^(π/2) (dx/( (√(1+tan^4 x)))) ?

$$\:\:\underset{\mathrm{0}} {\overset{\frac{\pi}{\mathrm{2}}} {\int}}\:\frac{{dx}}{\:\sqrt{\mathrm{1}+\mathrm{tan}\:^{\mathrm{4}} {x}}}\:? \\ $$

Question Number 114696    Answers: 1   Comments: 0

lim_(x→0) ((sinh (2x)−sin 2x)/x^5 ) =?

$$\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sinh}\:\left(\mathrm{2}{x}\right)−\mathrm{sin}\:\mathrm{2}{x}}{{x}^{\mathrm{5}} }\:=? \\ $$

Question Number 114689    Answers: 1   Comments: 0

∫xsin^n xdx

$$\int{xsin}^{{n}} {xdx} \\ $$

Question Number 114682    Answers: 1   Comments: 0

Question Number 114681    Answers: 3   Comments: 0

Prove that ∫_0 ^∞ (x^n /(e^x −1))dx=n!ζ(n+1)

$${Prove}\:{that}\:\int_{\mathrm{0}} ^{\infty} \frac{{x}^{{n}} }{{e}^{{x}} −\mathrm{1}}{dx}={n}!\zeta\left({n}+\mathrm{1}\right) \\ $$

Question Number 114676    Answers: 1   Comments: 0

If a^(1/2) −a^(−(1/2)) =1, prove that a+a^(−1) =3

$$\mathrm{If}\:{a}^{\frac{\mathrm{1}}{\mathrm{2}}} −{a}^{−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{1},\:\mathrm{prove}\:\mathrm{that}\:{a}+{a}^{−\mathrm{1}} =\mathrm{3} \\ $$

Question Number 114673    Answers: 0   Comments: 1

★ x^3 −x−(1/6)=0 ⇒ x=?

$$\:\:\:\:\bigstar\:\:\:\mathrm{x}^{\mathrm{3}} −\mathrm{x}−\frac{\mathrm{1}}{\mathrm{6}}=\mathrm{0}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Rightarrow\:\mathrm{x}=? \\ $$

Question Number 114671    Answers: 1   Comments: 0

Integrate ∫ ((x^4 +x^(−4) )/(x^6 +x^(−6) ))dx

$$ \\ $$$$\:\mathrm{Integrate}\:\:\int\:\frac{\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{−\mathrm{4}} }{\mathrm{x}^{\mathrm{6}} +\mathrm{x}^{−\mathrm{6}} }\mathrm{dx} \\ $$

Question Number 114668    Answers: 1   Comments: 0

((x+(√(x^2 −1)))/(x−(√(x^2 −1)))) + ((x−(√(x^2 −1)))/(x+(√(x^2 −1)))) = 98

$$\frac{{x}+\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}{{x}−\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}\:+\:\frac{{x}−\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}{{x}+\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}\:=\:\mathrm{98}\: \\ $$

Question Number 114665    Answers: 1   Comments: 0

Question Number 114660    Answers: 1   Comments: 1

Question Number 114656    Answers: 1   Comments: 2

2tanx−1=1 ⇔2tanx=1+1 tanx=(2/2)=1

$$\mathrm{2}{tanx}−\mathrm{1}=\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{2}{tanx}=\mathrm{1}+\mathrm{1} \\ $$$${tanx}=\frac{\mathrm{2}}{\mathrm{2}}=\mathrm{1} \\ $$

Question Number 114654    Answers: 2   Comments: 2

Question Number 114653    Answers: 2   Comments: 0

solve 6x^4 −25x^3 +12x^2 −25x+6=0

$${solve}\:\mathrm{6}{x}^{\mathrm{4}} −\mathrm{25}{x}^{\mathrm{3}} +\mathrm{12}{x}^{\mathrm{2}} −\mathrm{25}{x}+\mathrm{6}=\mathrm{0} \\ $$

Question Number 114647    Answers: 0   Comments: 5

Question Number 114638    Answers: 1   Comments: 0

Given a = ((1^2 +2^2 +3^2 +...+16^2 −16)/(1.3+2.4+3.5+...+15.17)) c = (1−(1/2)).(1−(1/3)).(1−(1/4)).(1−(1/5)). (1+(1/5))(1+(1/4))(1+(1/3))(1+(1/2)). find a×c =

$${Given}\:{a}\:=\:\frac{\mathrm{1}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +...+\mathrm{16}^{\mathrm{2}} −\mathrm{16}}{\mathrm{1}.\mathrm{3}+\mathrm{2}.\mathrm{4}+\mathrm{3}.\mathrm{5}+...+\mathrm{15}.\mathrm{17}} \\ $$$$\:\:\:{c}\:=\:\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\right). \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{5}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}\right). \\ $$$${find}\:{a}×{c}\:=\: \\ $$

Question Number 114637    Answers: 1   Comments: 0

lim_(x→(π/2)) (((π/2)−cos^(−1) (2x−π))/(1−sin^(−1) (((2x)/π)))) ?

$$\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\frac{\frac{\pi}{\mathrm{2}}−\mathrm{cos}\:^{−\mathrm{1}} \left(\mathrm{2}{x}−\pi\right)}{\mathrm{1}−\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{2}{x}}{\pi}\right)}\:? \\ $$

Question Number 114635    Answers: 1   Comments: 3

find ∫_0 ^1 x^4 ln(x)ln(1−x^2 )dx

$$\mathrm{find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\mathrm{x}^{\mathrm{4}} \mathrm{ln}\left(\mathrm{x}\right)\mathrm{ln}\left(\mathrm{1}−\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx}\:\: \\ $$

Question Number 114627    Answers: 2   Comments: 0

sin A+sin 2A+sin 3A+...+sin nA =??

$$\mathrm{sin}\:{A}+\mathrm{sin}\:\mathrm{2}{A}+\mathrm{sin}\:\mathrm{3}{A}+...+\mathrm{sin}\:{nA}\:=?? \\ $$

Question Number 114625    Answers: 1   Comments: 0

Question Number 114615    Answers: 1   Comments: 0

Question Number 114597    Answers: 3   Comments: 0

What is the number value of f[((log((( (√(x )) − 1 )/(x − 1))) ))^(1/3) ] = (√((√(x )) + x )) for f(−1)? a) 0,1 b) 27 c) 81 d) 10 e) 12

$$\: \\ $$$$\:\:\:\boldsymbol{\mathrm{What}}\:\:\boldsymbol{\mathrm{is}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{number}}\:\:\boldsymbol{\mathrm{value}}\:\:\boldsymbol{\mathrm{of}}\:\:\:\boldsymbol{\mathrm{f}}\left[\sqrt[{\mathrm{3}}]{\boldsymbol{\mathrm{log}}\left(\frac{\:\sqrt{\boldsymbol{\mathrm{x}}\:\:}\:−\:\:\:\mathrm{1}\:}{\boldsymbol{\mathrm{x}}\:\:\:−\:\:\:\mathrm{1}}\right)\:\:}\right]\:\:=\:\:\sqrt{\sqrt{\boldsymbol{\mathrm{x}}\:}\:\:\:+\:\:\:\boldsymbol{\mathrm{x}}\:}\:\:\boldsymbol{\mathrm{for}}\:\:\boldsymbol{\mathrm{f}}\left(−\mathrm{1}\right)? \\ $$$$\: \\ $$$$\left.\:\:\:\boldsymbol{\mathrm{a}}\right)\:\mathrm{0},\mathrm{1} \\ $$$$\left.\:\:\:\boldsymbol{\mathrm{b}}\right)\:\mathrm{27} \\ $$$$\left.\:\:\:\boldsymbol{\mathrm{c}}\right)\:\mathrm{81} \\ $$$$\left.\:\:\:\boldsymbol{\mathrm{d}}\right)\:\mathrm{10} \\ $$$$\left.\:\:\:\boldsymbol{\mathrm{e}}\right)\:\mathrm{12} \\ $$$$\: \\ $$

Question Number 114593    Answers: 1   Comments: 0

((∣x−1∣)/(∣x∣−1)) ≤ 1

$$\frac{\mid{x}−\mathrm{1}\mid}{\mid{x}\mid−\mathrm{1}}\:\leqslant\:\mathrm{1} \\ $$

Question Number 114592    Answers: 3   Comments: 0

Solve : x^2 +2x−1≡0(mod 3)

$$\mathrm{Solve}\::\:{x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{1}\equiv\mathrm{0}\left(\mathrm{mod}\:\mathrm{3}\right) \\ $$

Question Number 114586    Answers: 1   Comments: 2

f(x)−2f((1/2))=3x−2 f(x)=?

$$\mathrm{f}\left(\mathrm{x}\right)−\mathrm{2f}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)=\mathrm{3x}−\mathrm{2} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=? \\ $$

Question Number 114582    Answers: 0   Comments: 1

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