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...nice calculus ... prove : i:∫_0 ^( ∞) ((ln(x))/((1+x^(√2) )^(√2) )) =0 ✓ ii: ∫_0 ^( ∞) (dx/((1+x^(1+(√2)) )^(1+(√2)) )) =(1/( (√2))) ✓ iii: ∫_0 ^( (π/2)) ln(x^2 +ln^2 (cos(x)))dx=πln(ln(2))✓ ... m.n. july.1970...

$$\:\:\:\:\:\:\:...{nice}\:\:{calculus}\:...\:\:\: \\ $$$$\:{prove}\:: \\ $$$$\:\:\:{i}:\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{\left(\mathrm{1}+{x}^{\sqrt{\mathrm{2}}} \right)^{\sqrt{\mathrm{2}}} }\:=\mathrm{0}\:\:\:\:\:\:\checkmark \\ $$$$\:\:\:{ii}:\:\int_{\mathrm{0}} ^{\:\infty} \:\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{1}+\sqrt{\mathrm{2}}} \right)^{\mathrm{1}+\sqrt{\mathrm{2}}} }\:=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\:\checkmark\:\: \\ $$$$\:\:\:{iii}:\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {ln}\left({x}^{\mathrm{2}} +{ln}^{\mathrm{2}} \left({cos}\left({x}\right)\right)\right){dx}=\pi{ln}\left({ln}\left(\mathrm{2}\right)\right)\checkmark \\ $$$$\:\:\:\:\:\:\:...\:{m}.{n}.\:{july}.\mathrm{1970}... \\ $$$$ \\ $$

Question Number 116009 Answers: 2 Comments: 0

{ ((tan(a+b)=y)),((tan (a−b)=x)) :} tan2a=?

$$\begin{cases}{\mathrm{tan}\left(\mathrm{a}+\mathrm{b}\right)=\mathrm{y}}\\{\mathrm{tan}\:\left(\mathrm{a}−\mathrm{b}\right)=\mathrm{x}}\end{cases}\:\:\:\mathrm{tan2a}=? \\ $$

Question Number 116007 Answers: 2 Comments: 0

lim_(x→∝) ((√x)/(√(x+(√(x(√x))))))

$$\underset{{x}\rightarrow\propto} {\mathrm{lim}}\frac{\sqrt{\mathrm{x}}}{\sqrt{\mathrm{x}+\sqrt{\mathrm{x}\sqrt{\mathrm{x}}}}} \\ $$

Question Number 116006 Answers: 1 Comments: 0

3(sin x−cos x)^4 +6(sin x+cos x)^2 +4(sin^6 x+cos^6 x) = _____.

$$\mathrm{3}\left(\mathrm{sin}\:{x}−\mathrm{cos}\:{x}\right)^{\mathrm{4}} +\mathrm{6}\left(\mathrm{sin}\:{x}+\mathrm{cos}\:{x}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:+\mathrm{4}\left(\mathrm{sin}^{\mathrm{6}} {x}+\mathrm{cos}^{\mathrm{6}} {x}\right)\:=\:\_\_\_\_\_. \\ $$

Question Number 116005 Answers: 0 Comments: 0

... advanced mathematics... prove that::: lim_(x→1^+ ) ( ζ( x ) −(1/(x − 1))) =^(???) γ γ:: Euler − mascheroni constant. m.n.huly 1970

$$\:\:\:\:\:\:\:\:\:...\:{advanced}\:\:{mathematics}... \\ $$$$ \\ $$$$\:\:\:\:\:{prove}\:\:{that}::: \\ $$$$\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{lim}_{{x}\rightarrow\mathrm{1}^{+} } \left(\:\zeta\left(\:{x}\:\right)\:−\frac{\mathrm{1}}{{x}\:−\:\mathrm{1}}\right)\:\overset{???} {=}\gamma\:\:\: \\ $$$$\:\:\gamma::\:\mathscr{E}{uler}\:−\:{mascheroni}\:{constant}. \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{m}.{n}.{huly}\:\mathrm{1970} \\ $$$$ \\ $$

Question Number 116000 Answers: 0 Comments: 0

U(n)=∫_0 ^∞ ((1−tanh x)/( ((tanh x))^(1/n) ))dx another way?

$${U}\left({n}\right)=\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{1}−\mathrm{tanh}\:{x}}{\:\sqrt[{{n}}]{\mathrm{tanh}\:{x}}}{dx} \\ $$$${another}\:{way}? \\ $$$$ \\ $$

Question Number 115999 Answers: 1 Comments: 0

lim_(x→0) ((1−cos x (√(cos 2x)) ((cos 3x))^(1/(3 )) ((cos 4x))^(1/(4 )) )/x^2 )

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:{x}\:\sqrt{\mathrm{cos}\:\mathrm{2}{x}}\:\sqrt[{\mathrm{3}\:}]{\mathrm{cos}\:\mathrm{3}{x}}\:\sqrt[{\mathrm{4}\:}]{\mathrm{cos}\:\mathrm{4}{x}}}{{x}^{\mathrm{2}} } \\ $$

Question Number 115997 Answers: 1 Comments: 0

Question Number 115988 Answers: 1 Comments: 2

Question Number 115986 Answers: 1 Comments: 0

Question Number 115974 Answers: 0 Comments: 0

∫((e^(3x) −e^x )/(x(e^(3x) +1)(e^x +1)))dx = ?

$$\int\frac{{e}^{\mathrm{3}{x}} −{e}^{{x}} }{{x}\left({e}^{\mathrm{3}{x}} +\mathrm{1}\right)\left({e}^{{x}} +\mathrm{1}\right)}{dx}\:=\:? \\ $$

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