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Question Number 118872 Answers: 1 Comments: 1

Question Number 118868 Answers: 1 Comments: 0

If the graphs of y=x^2 +2ax+6b and y=x^2 +2bx+6a intersect at? only one point in the xy−plane , what is the x−coordinate of the point of intersection ?

$${If}\:{the}\:{graphs}\:{of}\:{y}={x}^{\mathrm{2}} +\mathrm{2}{ax}+\mathrm{6}{b}\: \\ $$$${and}\:{y}={x}^{\mathrm{2}} +\mathrm{2}{bx}+\mathrm{6}{a}\:{intersect}\:{at}? \\ $$$${only}\:{one}\:{point}\:{in}\:{the}\:{xy}−{plane} \\ $$$$,\:{what}\:{is}\:{the}\:{x}−{coordinate}\:{of}\:{the} \\ $$$${point}\:{of}\:{intersection}\:? \\ $$

Question Number 118861 Answers: 1 Comments: 0

sin^(−1) (−1/2)

$${sin}^{−\mathrm{1}} \left(−\mathrm{1}/\mathrm{2}\right) \\ $$

Question Number 118966 Answers: 1 Comments: 0

lim_(x→0) (((√(x+bx^2 ))−(√x))/(bx(√x))) =?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{{x}+{bx}^{\mathrm{2}} }−\sqrt{{x}}}{{bx}\sqrt{{x}}}\:=? \\ $$

Question Number 118849 Answers: 1 Comments: 2

Question Number 118841 Answers: 1 Comments: 1

Question Number 118839 Answers: 0 Comments: 1

Question Number 118834 Answers: 2 Comments: 0

∫ ((x^4 +1)/(x^5 +4x^3 )) dx

$$\:\:\int\:\frac{{x}^{\mathrm{4}} +\mathrm{1}}{{x}^{\mathrm{5}} +\mathrm{4}{x}^{\mathrm{3}} }\:{dx}\: \\ $$

Question Number 118857 Answers: 0 Comments: 0

Question Number 118825 Answers: 2 Comments: 0

I am thinking of a two−digit number .If i write 3 to the left of my number and double this three digit number the result is 27 times my original number. what is my number ?

$${I}\:{am}\:{thinking}\:{of}\:{a}\:{two}−{digit}\:{number} \\ $$$$.{If}\:{i}\:{write}\:\mathrm{3}\:{to}\:{the}\:{left}\:{of}\:{my}\:{number} \\ $$$${and}\:{double}\:{this}\:{three}\:{digit}\:{number}\:{the} \\ $$$${result}\:{is}\:\mathrm{27}\:{times}\:{my}\:{original}\:{number}. \\ $$$${what}\:{is}\:{my}\:{number}\:? \\ $$

Question Number 118822 Answers: 2 Comments: 0

In how many ways can the letters of the word LEVITATE be arranged if the vowels must not be next to each other

$$\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{the}\:\mathrm{letters}\:\mathrm{of}\: \\ $$$$\:\mathrm{the}\:\mathrm{word}\:{LEVITATE}\:\mathrm{be}\:\mathrm{arranged}\:\mathrm{if} \\ $$$$\:\mathrm{the}\:\mathrm{vowels}\:\mathrm{must}\:\mathrm{not}\:\mathrm{be}\:\mathrm{next}\:\mathrm{to}\:\mathrm{each} \\ $$$$\:\mathrm{other} \\ $$

Question Number 118819 Answers: 3 Comments: 0

∫((x^4 +x^2 +1)/((x^2 +4)^2 (x^2 +1))) dx

$$\int\frac{{x}^{\mathrm{4}} +{x}^{\mathrm{2}} +\mathrm{1}}{\left({x}^{\mathrm{2}} +\mathrm{4}\right)^{\mathrm{2}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)}\:{dx}\: \\ $$

Question Number 118813 Answers: 1 Comments: 0

(d^2 y/dx^2 ) −4x (dy/dx) + y(3x^2 −2)= 0

$$\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:−\mathrm{4}{x}\:\frac{{dy}}{{dx}}\:+\:{y}\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}\right)=\:\mathrm{0}\: \\ $$

Question Number 118811 Answers: 1 Comments: 4

Question Number 118810 Answers: 3 Comments: 0

(√(2003)) + (√(2005)) < 2(√(2004)) ???

$$\sqrt{\mathrm{2003}}\:+\:\sqrt{\mathrm{2005}}\:<\:\mathrm{2}\sqrt{\mathrm{2004}}\:\:??? \\ $$

Question Number 118798 Answers: 2 Comments: 0

1)Find (dy/dx) ; if x = at^2 , y = 2at 2)

$$\left.\:\mathrm{1}\right){Find}\:\frac{{dy}}{{dx}}\:\:;\:\:\:{if}\:\:\:{x}\:=\:{at}^{\mathrm{2}} \:,\:\:{y}\:=\:\mathrm{2}{at} \\ $$$$ \\ $$$$\left.\mathrm{2}\right)\: \\ $$

Question Number 118793 Answers: 0 Comments: 0

Question Number 118791 Answers: 2 Comments: 0

Question Number 118790 Answers: 0 Comments: 0

Show by recurence that (a+b)^n =Σ_(k=0 ) ^n C_n ^k ×a^k ×b^(n−k)

$$\mathrm{Show}\:\mathrm{by}\:\mathrm{recurence}\:\mathrm{that} \\ $$$$\left(\mathrm{a}+\mathrm{b}\right)^{\mathrm{n}} =\underset{\mathrm{k}=\mathrm{0}\:} {\overset{\mathrm{n}} {\sum}}\mathrm{C}_{\mathrm{n}} ^{\mathrm{k}} ×\mathrm{a}^{\mathrm{k}} ×\mathrm{b}^{\mathrm{n}−\mathrm{k}} \\ $$

Question Number 118781 Answers: 0 Comments: 6

Question Number 118780 Answers: 2 Comments: 0

z and z′ ∈ C . show that: 1. zz′^(−) =z^− ×z′^(−) 2. ((z/(z′)))^(−) =(z^− /(z′^(−) ))

$$\mathrm{z}\:\mathrm{and}\:\mathrm{z}'\:\in\:\mathbb{C}\:. \\ $$$$\mathrm{show}\:\mathrm{that}: \\ $$$$\mathrm{1}.\:\:\:\:\:\:\overline {\mathrm{zz}'}=\overset{−} {\mathrm{z}}×\overline {\mathrm{z}'} \\ $$$$\mathrm{2}.\:\:\:\:\:\:\:\overline {\left(\frac{\mathrm{z}}{\mathrm{z}'}\right)}=\frac{\overset{−} {\mathrm{z}}}{\overline {\mathrm{z}'}} \\ $$$$ \\ $$

Question Number 118777 Answers: 1 Comments: 0

lim_(n→∞) (((n!)/n^n ))^(1/n) =lim_(n→∞) ((((√(2nπ)) n^n )/(n^n ×e^n )))^(1/n) ⇒lim_(n→∞) (1/e)((√(2nπ)))^(1/n) =(1/e)

$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{{n}!}{{n}^{{n}} }\right)^{\frac{\mathrm{1}}{{n}}} =\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\sqrt{\mathrm{2}{n}\pi}\:{n}^{{n}} }{{n}^{{n}} ×{e}^{{n}} }\right)^{\frac{\mathrm{1}}{{n}}} \\ $$$$\Rightarrow\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}}{{e}}\left(\sqrt{\mathrm{2}{n}\pi}\right)^{\frac{\mathrm{1}}{{n}}} =\frac{\mathrm{1}}{{e}} \\ $$

Question Number 207634 Answers: 1 Comments: 0

calculer lim n→+oo f_n (x) f_n (x)=∫_0^ ^(+oo) ((ne^(−x) )/(1+nx))dx /x∈[0+oo[

$${calculer}\:{lim}\:\:{n}\rightarrow+{oo}\:{f}_{{n}} \left({x}\right) \\ $$$${f}_{{n}} \left({x}\right)=\int_{\mathrm{0}^{} } ^{+{oo}} \frac{{ne}^{−{x}} }{\mathrm{1}+{nx}}{dx}\:\:\:/{x}\in\left[\mathrm{0}+{oo}\left[\right.\right. \\ $$

Question Number 118768 Answers: 1 Comments: 0

Question Number 118759 Answers: 0 Comments: 4

The first three terms in the binomial expansion (p−q)^m , in ascending order of q, are denoted by a,b and c respectively. Show that (b^2 /(ac))=((2m)/(m−1))

$$\mathrm{The}\:\mathrm{first}\:\mathrm{three}\:\mathrm{terms}\:\mathrm{in}\:\mathrm{the}\:\mathrm{binomial}\:\mathrm{expansion} \\ $$$$\left({p}−{q}\right)^{{m}} \:,\:\mathrm{in}\:\mathrm{ascending}\:\mathrm{order}\:\mathrm{of}\:{q},\:\mathrm{are}\:\mathrm{denoted} \\ $$$$\mathrm{by}\:{a},{b}\:\mathrm{and}\:{c}\:\mathrm{respectively}. \\ $$$$\mathrm{Show}\:\mathrm{that}\:\frac{{b}^{\mathrm{2}} }{{ac}}=\frac{\mathrm{2}{m}}{{m}−\mathrm{1}} \\ $$

Question Number 118757 Answers: 2 Comments: 1

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