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AlgebraQuestion and Answers: Page 93

Question Number 177856 Answers: 1 Comments: 0

p(x)+p(x−1)=2x+4 p(x)=?

$${p}\left({x}\right)+{p}\left({x}−\mathrm{1}\right)=\mathrm{2}{x}+\mathrm{4} \\ $$$${p}\left({x}\right)=? \\ $$

Question Number 177826 Answers: 0 Comments: 0

Question Number 177822 Answers: 1 Comments: 2

what is coefficient of x^2 in (1−x)(1+2x)(1−3x)(1+4x)(1−5x) ... (1+14x)(1−15x) ?

$$\:\:\:\mathrm{what}\:\mathrm{is}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} \:\mathrm{in}\: \\ $$$$\:\:\:\left(\mathrm{1}−\mathrm{x}\right)\left(\mathrm{1}+\mathrm{2x}\right)\left(\mathrm{1}−\mathrm{3x}\right)\left(\mathrm{1}+\mathrm{4x}\right)\left(\mathrm{1}−\mathrm{5x}\right) \\ $$$$\:\:\:\:...\:\left(\mathrm{1}+\mathrm{14x}\right)\left(\mathrm{1}−\mathrm{15x}\right)\:? \\ $$

Question Number 177815 Answers: 2 Comments: 0

Question Number 177812 Answers: 1 Comments: 0

Question Number 177811 Answers: 1 Comments: 0

Question Number 177810 Answers: 1 Comments: 0

Question Number 177802 Answers: 0 Comments: 0

Question Number 177741 Answers: 2 Comments: 0

Question Number 177711 Answers: 0 Comments: 0

(4/(20))+((4.7)/(20.30))+((4.7.10)/(20.30.40))+.....

$$\frac{\mathrm{4}}{\mathrm{20}}+\frac{\mathrm{4}.\mathrm{7}}{\mathrm{20}.\mathrm{30}}+\frac{\mathrm{4}.\mathrm{7}.\mathrm{10}}{\mathrm{20}.\mathrm{30}.\mathrm{40}}+..... \\ $$

Question Number 177698 Answers: 0 Comments: 0

In △ABC 36 R r ≤ Σ ((m_b ^2 + m_c ^2 )/(sin B sin C)) ≤ ((9 R^4 )/(2 r^2 ))

$$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC} \\ $$$$\mathrm{36}\:\mathrm{R}\:\mathrm{r}\:\leqslant\:\Sigma\:\frac{\mathrm{m}_{\boldsymbol{\mathrm{b}}} ^{\mathrm{2}} \:+\:\mathrm{m}_{\boldsymbol{\mathrm{c}}} ^{\mathrm{2}} }{\mathrm{sin}\:\mathrm{B}\:\mathrm{sin}\:\mathrm{C}}\:\leqslant\:\frac{\mathrm{9}\:\mathrm{R}^{\mathrm{4}} }{\mathrm{2}\:\mathrm{r}^{\mathrm{2}} } \\ $$

Question Number 177688 Answers: 0 Comments: 2

fog^(−1) =3x+2 (gof)_x =2x−1 ^( {: (),() } (fof)_3 =?)

$${fog}^{−\mathrm{1}} =\mathrm{3}{x}+\mathrm{2} \\ $$$$\left({gof}\right)_{{x}} =\mathrm{2}{x}−\mathrm{1}\:\:\:\:\:\overset{\left.\begin{matrix}{}\\{}\end{matrix}\right\}\:\:\left({fof}\right)_{\mathrm{3}} =?} {\:} \\ $$

Question Number 177675 Answers: 3 Comments: 4

Question Number 177630 Answers: 1 Comments: 0

Question Number 177629 Answers: 1 Comments: 0

Question Number 177627 Answers: 1 Comments: 0

Question Number 177579 Answers: 2 Comments: 0

if x^3 +y^3 +((x+y)/4)=((15)/2), find maximum value of x+y.

$${if}\:{x}^{\mathrm{3}} +{y}^{\mathrm{3}} +\frac{{x}+{y}}{\mathrm{4}}=\frac{\mathrm{15}}{\mathrm{2}},\:{find}\:{maximum} \\ $$$${value}\:{of}\:{x}+{y}. \\ $$

Question Number 177557 Answers: 0 Comments: 0

Question Number 177530 Answers: 3 Comments: 0

f (x ) + f ((( 1)/( ((1 −x^( 3) ))^(1/3) )) )= x^( 3) is given. find the value of: f (−1)=?

$$ \\ $$$${f}\:\left({x}\:\right)\:+\:{f}\:\left(\frac{\:\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}\:−{x}^{\:\mathrm{3}} }}\:\right)=\:{x}^{\:\mathrm{3}} \\ $$$$\:\:\:\:\:\:{is}\:{given}.\:{find}\:{the}\:{value}\:{of}: \\ $$$$\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:{f}\:\left(−\mathrm{1}\right)=? \\ $$$$ \\ $$

Question Number 177519 Answers: 2 Comments: 0

Question Number 177525 Answers: 1 Comments: 3

Question Number 177510 Answers: 1 Comments: 1

Question Number 177475 Answers: 1 Comments: 0

Question Number 177473 Answers: 0 Comments: 0

Question Number 178486 Answers: 1 Comments: 0

Reduce (((2n)!)/(1×3×5×...×(2n−1)))

$$\:{Reduce}\:\frac{\left(\mathrm{2}{n}\right)!}{\mathrm{1}×\mathrm{3}×\mathrm{5}×...×\left(\mathrm{2}{n}−\mathrm{1}\right)}\: \\ $$

Question Number 177492 Answers: 0 Comments: 0

If 0<a≤b then: ∫_( a) ^( b) ∫_( a) ^( b) ((dx dy)/( (√(xy (x + y))))) ≤ ((b−a)/2) ∙ log ((b/a)) + log^2 ((b/a))

$$\mathrm{If}\:\:\:\mathrm{0}<\mathrm{a}\leqslant\mathrm{b}\:\:\:\mathrm{then}: \\ $$$$\int_{\:\boldsymbol{\mathrm{a}}} ^{\:\boldsymbol{\mathrm{b}}} \:\int_{\:\boldsymbol{\mathrm{a}}} ^{\:\boldsymbol{\mathrm{b}}} \:\:\frac{\mathrm{dx}\:\mathrm{dy}}{\:\sqrt{\mathrm{xy}\:\left(\mathrm{x}\:+\:\mathrm{y}\right)}}\:\:\leqslant\:\:\frac{\mathrm{b}−\mathrm{a}}{\mathrm{2}}\:\centerdot\:\mathrm{log}\:\left(\frac{\mathrm{b}}{\mathrm{a}}\right)\:+\:\mathrm{log}^{\mathrm{2}} \:\left(\frac{\mathrm{b}}{\mathrm{a}}\right) \\ $$

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