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Question Number 191439 Answers: 0 Comments: 0

Question Number 191436 Answers: 1 Comments: 0

Factorize x^2 + (1/a) (bx + c)

$$\mathrm{Factorize} \\ $$$$\boldsymbol{{x}}^{\mathrm{2}} \:+\:\frac{\mathrm{1}}{\boldsymbol{{a}}}\:\left(\boldsymbol{{bx}}\:+\:\boldsymbol{{c}}\right) \\ $$

Question Number 191395 Answers: 1 Comments: 0

Question Number 191394 Answers: 1 Comments: 0

Question Number 191393 Answers: 0 Comments: 0

Question Number 191389 Answers: 1 Comments: 0

Factorize: x^3 +(1/x^3 )+((11)/8)

$$\mathrm{Factorize}: \\ $$$${x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}^{\mathrm{3}} }+\frac{\mathrm{11}}{\mathrm{8}} \\ $$

Question Number 191343 Answers: 1 Comments: 0

solve in R ⌊ (1/x) ⌋ + ⌊ (2/x) ⌋ + ⌊ (3/x) ⌋ = 1

$$ \\ $$$$\:\:\:\:\:\:\mathrm{solve}\:\:{in}\:\:\mathbb{R} \\ $$$$ \\ $$$$\:\:\:\:\:\:\lfloor\:\frac{\mathrm{1}}{{x}}\:\rfloor\:+\:\lfloor\:\frac{\mathrm{2}}{{x}}\:\rfloor\:+\:\lfloor\:\frac{\mathrm{3}}{{x}}\:\rfloor\:=\:\mathrm{1} \\ $$$$ \\ $$

Question Number 191301 Answers: 2 Comments: 0

Question Number 191300 Answers: 1 Comments: 0

Question Number 191304 Answers: 2 Comments: 0

Question Number 191250 Answers: 0 Comments: 4

Question Number 191283 Answers: 1 Comments: 0

Question Number 191222 Answers: 0 Comments: 0

Question Number 191221 Answers: 0 Comments: 0

Question Number 191430 Answers: 3 Comments: 0

factorise 4x^4 +81

$${factorise}\:\mathrm{4}{x}^{\mathrm{4}} +\mathrm{81} \\ $$

Question Number 191191 Answers: 3 Comments: 0

Question Number 191169 Answers: 1 Comments: 0

Question Number 191148 Answers: 0 Comments: 0

Question Number 191147 Answers: 0 Comments: 0

Question Number 191146 Answers: 0 Comments: 0

Question Number 191138 Answers: 0 Comments: 0

Question Number 191127 Answers: 0 Comments: 0

Question Number 191111 Answers: 0 Comments: 2

bb55bb

$${bb}\mathrm{55}{bb} \\ $$

Question Number 191103 Answers: 1 Comments: 0

Question Number 191077 Answers: 3 Comments: 2

a^→ ∙ b^(→) = 4 b^→ ∙ c^(→) = 5 7a^(→) = 4b^(→) + 2c^(→) Find: ∣c^(→) ∣ = ?

$$\overset{\rightarrow} {\mathrm{a}}\:\centerdot\:\overset{\rightarrow} {\mathrm{b}}\:=\:\mathrm{4} \\ $$$$\overset{\rightarrow} {\mathrm{b}}\:\centerdot\:\overset{\rightarrow} {\mathrm{c}}\:=\:\mathrm{5} \\ $$$$\overset{\rightarrow} {\mathrm{7a}}\:=\:\overset{\rightarrow} {\mathrm{4b}}\:+\:\overset{\rightarrow} {\mathrm{2c}}\:\: \\ $$$$\mathrm{Find}:\:\:\:\mid\overset{\rightarrow} {\mathrm{c}}\:\mid\:=\:? \\ $$

Question Number 191061 Answers: 0 Comments: 0

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