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AlgebraQuestion and Answers: Page 62

Question Number 192542 Answers: 2 Comments: 0

Question Number 192508 Answers: 1 Comments: 1

Question Number 192481 Answers: 1 Comments: 0

Question Number 192477 Answers: 2 Comments: 0

Find: ((((25)/(42)) − (5/(16)) + ((10)/9) − (2/3))/((3/8) + (4/5) − (5/7) − (4/3))) = ?

$Find : \frac{\frac{25}{42} - \frac{5}{16} + \frac{10}{9} - \frac{2}{3}}{\frac{3}{8} + \frac{4}{5} - \frac{5}{7} - \frac{4}{3}} = ?$

Question Number 192463 Answers: 3 Comments: 0

Question Number 192440 Answers: 1 Comments: 0

Given { ((A=(((p^2 +q^2 +r^2 )^2 )/((pq)^2 +(pr)^2 +(qr)^2 )))),((B=((q^2 −pr)/(p^2 +q^2 +r^2 )) )) :} If p+q+r=0 then A^2 −4B=?

$Given {\begin{cases} A = \frac{{(p^{2} + q^{2} + r^{2})}^{2}}{{(pq)}^{2} + {(pr)}^{2} + {(qr)}^{2}} \\ B = \frac{q^{2} - pr}{p^{2} + q^{2} + r^{2}} \end{cases}$ $If p + q + r = 0 then A^{2} - 4 B = ?$

Question Number 192437 Answers: 1 Comments: 0

(1/a) + (1/b) + (1/c) = (1/(a + b + c)) . Prove that (1/a^5 ) + (1/b^5 ) + (1/c^5 ) = (1/(a^5 + b^5 + c^5 )) = (1/((a + b + c)^5 ))

$\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{1}{a + b + c} . Prove that$ $\frac{1}{a^{5}} + \frac{1}{b^{5}} + \frac{1}{c^{5}} = \frac{1}{a^{5} + b^{5} + c^{5}} = \frac{1}{{(a + b + c)}^{5}}$

Question Number 192425 Answers: 1 Comments: 0

Question if “k” is odd & A=1^k +2^k +...+n^(k ) & B=1+2+...+n prove that : B ∣ A

$Q u e s t i o n$ $i f ‘ ‘ k^{″} i s o d d & A = 1^{k} + 2^{k} + . . . + n^{k} & B = 1 + 2 + . . . + n$ $p r o v e t h a t : B ∣ A$

Question Number 192409 Answers: 1 Comments: 0

Question Number 192399 Answers: 1 Comments: 1

Algebra (1 ) G, is a group and o(G ) = p^( 2) . prove that G is an abelian group. hint: ( p is prime number ) −−−−−−−−−−−−−

$A l g e b r a (1)$ $G, i s a g r o u p a n d o (G) = p^{2} .$ $p r o v e t h a t G i s a n a b e l i a n g r o u p .$ $h i n t : (p i s p r i m e n u m b e r)$ $- - - - - - - - - - - - -$

Question Number 192387 Answers: 1 Comments: 0

Simplify (√(2(1+(√(4+(((2017^4 −1)/(2017^2 )))^2 ))))) is ....

$Simplify$ $\sqrt{2 (1 + \sqrt{4 + {(\frac{2017^{4} - 1}{2017^{2}})}^{2}})}$ $is . . . .$

Question Number 192374 Answers: 3 Comments: 1

why “ 200!<100^(200) ” ?

$w h y ‘ ‘ 200! < 100^{200}^{″} ?$

Question Number 192370 Answers: 2 Comments: 0

Solve the equation x^4 − 2x^3 + 4x^2 + 6x − 21 = 0, Given that the sum of two of its roots is zero

$Solve the equation x^{4} - {2 x}^{3} + {4 x}^{2} + 6 x - 21 = 0,$ $Given that the sum of two of its roots is zero$

Question Number 192363 Answers: 0 Comments: 0

Solve for x x_i −x+(2cx−cb)(y_i +cx^2 −cbx)=0 the following is true for this equaition i)c>0 ii)b>0 iii)there is only one real solution

$Solve for x$ $x_{i} - x + (2 c x - c b) (y_{i} + {c x}^{2} - c b x) = 0$ $the following is true for this equaition$ $i) c > 0$ $i i) b > 0$ $i i i) there is only one real solution$

Question Number 192330 Answers: 0 Comments: 0

Question Number 192350 Answers: 2 Comments: 0

Question Number 192186 Answers: 3 Comments: 0

If α, β and γ are the roots of x^3 + px + q = 0, find Σα^4 .

$If α, β and γ are the roots of x^{3} + px + q = 0, find Σ α^{4} .$

Question Number 192171 Answers: 1 Comments: 2

2^x^x^x =2^(√2) x=?

$2^{x^{x^{x}}} = 2^{\sqrt{2}}$ $x = ?$

Question Number 192173 Answers: 1 Comments: 0

prove that (x^2 +a^2 )^4 = (x^4 −6x^2 a^2 +a^4 )^2 +(4x^3 a−4xa^3 )^2

$p r o v e t h a t$ ${(x^{2} + a^{2})}^{4} = {(x^{4} - 6 x^{2} a^{2} + a^{4})}^{2} + {(4 x^{3} a - 4 {x a}^{3})}^{2}$

Question Number 192149 Answers: 5 Comments: 0

Find: (1/2) + (3/2^3 ) + (5/2^5 ) + (7/2^7 ) + ...

$Find :$ $\frac{1}{2} + \frac{3}{2^{3}} + \frac{5}{2^{5}} + \frac{7}{2^{7}} + . . .$

Question Number 192143 Answers: 1 Comments: 2

Find: (7/2) + ((77)/(22)) + ((777)/(222)) + ((7777)/(2222)) +...+ ((77777777)/(22222222))

$Find :$ $\frac{7}{2} + \frac{77}{22} + \frac{777}{222} + \frac{7777}{2222} + . . . + \frac{77777777}{22222222}$

Question Number 192142 Answers: 1 Comments: 0

Question let x=<a_n a_(n−1) ...a_1 a_0 > ∈N ; a_0 ≠0 & y=<a_n a_(n−1) ...a_1 > ∈N be two natural numbers such that (x/y)∈N find the number “ x ” ?

$Q u e s t i o n$ $l e t x =< a_{n} a_{n - 1} . . . a_{1} a_{0} > \in N; a_{0} \neq 0 &$ $y =< a_{n} a_{n - 1} . . . a_{1} > \in N b e$ $t w o n a t u r a l n u m b e r s$ $s u c h t h a t \frac{x}{y} \in N$ $f i n d t h e n u m b e r ‘ ‘ x^{″} ?$

Question Number 192134 Answers: 1 Comments: 0

when ((√2)+1)^7 =(√(57125))+(√(57124)) then ((√2)−1)^7 =?

$when {(\sqrt{2} + 1)}^{7} = \sqrt{57125} + \sqrt{57124}$ $then {(\sqrt{2} - 1)}^{7} = ?$

Question Number 192172 Answers: 1 Comments: 0

Q1 ∴ x=<1a_1 a_2 ...a_n >∈N & y=<a_1 a_2 ...a_n 1>∈N if y=3x then , find the smallest value of x Q2 ∴ with the above conditions ,what other values can be placed besides the number “ 1 ”

$Q 1 ∴ x =< 1 a_{1} a_{2} . . . a_{n} >\in N & y =< a_{1} a_{2} . . . a_{n} 1 >\in N$ $i f y = 3 x t h e n, f i n d t h e s m a l l e s t$ $v a l u e o f x$ $Q 2 ∴ w i t h t h e a b o v e c o n d i t i o n s, w h a t o t h e r v a l u e s$ $c a n b e p l a c e d b e s i d e s t h e n u m b e r ‘ ‘ 1^{″}$

Question Number 192087 Answers: 0 Comments: 3

Let {H_α } ∈ Ω, be a family of subgroup of a group G, then prove that ∩_(α ∈ Ω) H_α .

$Let {H_{α}} \in Ω, be a family of$ $subgroup of a group G, then$ $prove that \cap_{α \in Ω} H_{α} .$

Question Number 192062 Answers: 2 Comments: 3

prove it : times_n ; (√(4+(√(4+(√(4+...+(√4))))) )) < 3

$p r o v e i t :$ $t i m e s_n; \sqrt{4 + \sqrt{4 + \sqrt{4 + . . . + \sqrt{4}}}} < 3$

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