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AlgebraQuestion and Answers: Page 57

Question Number 201047    Answers: 0   Comments: 0

Question Number 201041    Answers: 1   Comments: 0

4(33)7 4(24)6 5( ? )4 a)9 b)18 c)27 d)36

$$\mathrm{4}\left(\mathrm{33}\right)\mathrm{7} \\ $$$$\mathrm{4}\left(\mathrm{24}\right)\mathrm{6} \\ $$$$\mathrm{5}\left(\:?\:\right)\mathrm{4} \\ $$$$ \\ $$$$\left.{a}\left.\right)\left.\mathrm{9}\left.\:\:\:\:\:{b}\right)\mathrm{18}\:\:\:\:\:{c}\right)\mathrm{27}\:\:\:\:\:{d}\right)\mathrm{36} \\ $$

Question Number 201034    Answers: 0   Comments: 0

Question Number 200971    Answers: 1   Comments: 0

Question Number 200961    Answers: 2   Comments: 0

−x^3 +1=((−x+1))^(1/3) ⇒x=?

$$\: \\ $$$$\:\:\:\:\:−{x}^{\mathrm{3}} +\mathrm{1}=\sqrt[{\mathrm{3}}]{−{x}+\mathrm{1}}\:\Rightarrow{x}=? \\ $$$$ \\ $$

Question Number 200937    Answers: 2   Comments: 0

Question Number 200942    Answers: 1   Comments: 0

Question Number 200931    Answers: 1   Comments: 0

(1/9)+(1/(18))+(1/(30))+(1/(45))+(1/(63))+(1/(84))+...∞=?

$$\frac{\mathrm{1}}{\mathrm{9}}+\frac{\mathrm{1}}{\mathrm{18}}+\frac{\mathrm{1}}{\mathrm{30}}+\frac{\mathrm{1}}{\mathrm{45}}+\frac{\mathrm{1}}{\mathrm{63}}+\frac{\mathrm{1}}{\mathrm{84}}+...\infty=? \\ $$$$ \\ $$

Question Number 200885    Answers: 1   Comments: 1

(√((32^4 +41^4 +73^4 )/2))

$$\:\:\: \sqrt{\frac{\mathrm{32}^{\mathrm{4}} +\mathrm{41}^{\mathrm{4}} +\mathrm{73}^{\mathrm{4}} }{\mathrm{2}}}\: \\ $$

Question Number 200877    Answers: 0   Comments: 5

Question Number 200795    Answers: 1   Comments: 0

lim_(x→sin1) ((1−x^2 )/(1+cosx))=?

$$\underset{{x}\rightarrow{sin}\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\mathrm{1}+{cosx}}=? \\ $$

Question Number 200788    Answers: 1   Comments: 0

sinx + cosx = tgx x = ?

$$\mathrm{sin}\boldsymbol{\mathrm{x}}\:\:\:+\:\:\:\mathrm{cos}\boldsymbol{\mathrm{x}}\:\:\:=\:\:\:\mathrm{tg}\boldsymbol{\mathrm{x}} \\ $$$$\mathrm{x}\:=\:? \\ $$

Question Number 200768    Answers: 2   Comments: 0

Question Number 200739    Answers: 3   Comments: 2

solve for x∈R x^3 −3((3x−2))^(1/3) +2=0

$${solve}\:{for}\:{x}\in{R} \\ $$$${x}^{\mathrm{3}} −\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}{x}−\mathrm{2}}+\mathrm{2}=\mathrm{0} \\ $$

Question Number 200729    Answers: 1   Comments: 0

if a<b<0 and (√( a^4 +2a^2 b^2 +b^4 )) +(√(a^4 −2a^2 b^2 +b^4 )) = ?

$$ \\ $$$$\:\:\:{if}\:\:\:\:{a}<{b}<\mathrm{0}\:\:\: \\ $$$$\:\:\:{and}\:\:\sqrt{\:{a}^{\mathrm{4}} +\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:+\sqrt{{a}^{\mathrm{4}} −\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:=\:? \\ $$$$ \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\: \\ $$

Question Number 200723    Answers: 0   Comments: 0

Question Number 200718    Answers: 3   Comments: 0

3. 1+3+5+7+...+(2n+1) = ?

$$\mathrm{3}. \\ $$$$\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+...+\left(\mathrm{2}{n}+\mathrm{1}\right)\:=\:? \\ $$

Question Number 200717    Answers: 1   Comments: 0

2. A = 12 − 2x B = 3 + 2x (A∙B)_(min) = ?

$$\mathrm{2}. \\ $$$${A}\:=\:\mathrm{12}\:−\:\mathrm{2}{x} \\ $$$${B}\:=\:\mathrm{3}\:+\:\mathrm{2}{x} \\ $$$$\left({A}\centerdot{B}\right)_{\boldsymbol{{min}}} \:=\:? \\ $$

Question Number 200716    Answers: 1   Comments: 0

1. (a/8) + (b/5) = 6 ⇒ (a+b)_(max) = ?

$$\mathrm{1}.\: \\ $$$$\frac{{a}}{\mathrm{8}}\:+\:\frac{{b}}{\mathrm{5}}\:=\:\mathrm{6}\:\:\:\Rightarrow\:\:\:\left({a}+{b}\right)_{\boldsymbol{{max}}} \:=\:? \\ $$

Question Number 200696    Answers: 4   Comments: 0

Question Number 200589    Answers: 1   Comments: 0

Question Number 200565    Answers: 1   Comments: 2

sin^(10) x + cos^(10) x = ((29)/(16)) cos^4 2x find: x = ?

$$\mathrm{sin}^{\mathrm{10}} \mathrm{x}\:\:+\:\:\mathrm{cos}^{\mathrm{10}} \mathrm{x}\:\:=\:\:\frac{\mathrm{29}}{\mathrm{16}}\:\mathrm{cos}^{\mathrm{4}} \mathrm{2x} \\ $$$$\mathrm{find}:\:\:\:\mathrm{x}\:=\:? \\ $$

Question Number 200594    Answers: 2   Comments: 0

Question Number 200498    Answers: 5   Comments: 3

solve for x∈R (√(x−(1/x)))+(√(1−(1/x)))=x

$${solve}\:{for}\:{x}\in{R} \\ $$$$\sqrt{{x}−\frac{\mathrm{1}}{{x}}}+\sqrt{\mathrm{1}−\frac{\mathrm{1}}{{x}}}={x} \\ $$

Question Number 200472    Answers: 0   Comments: 0

Question Number 200465    Answers: 2   Comments: 1

Find the sum of the fifth powers of the roots of x^3 −2x^2 +x−1=0 by applying synthetic division

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{fifth}\:\mathrm{powers}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{x}^{\mathrm{3}} −\mathrm{2x}^{\mathrm{2}} +\mathrm{x}−\mathrm{1}=\mathrm{0}\:\mathrm{by} \\ $$$$\mathrm{applying}\:\mathrm{synthetic}\:\mathrm{division} \\ $$

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