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AlgebraQuestion and Answers: Page 349

Question Number 14594 Answers: 1 Comments: 0

Question Number 14559 Answers: 1 Comments: 0

Solve for x ((6x + 2a + 3b + c )/(6x + 2a − 3b − c)) = ((2x + 6a + b + 3c)/(2x + 6a − b − 3c))

$$\mathrm{Solve}\:\mathrm{for}\:\:\mathrm{x} \\ $$$$\frac{\mathrm{6x}\:+\:\mathrm{2a}\:+\:\mathrm{3b}\:+\:\mathrm{c}\:}{\mathrm{6x}\:+\:\mathrm{2a}\:−\:\mathrm{3b}\:−\:\mathrm{c}}\:=\:\frac{\mathrm{2x}\:+\:\mathrm{6a}\:+\:\mathrm{b}\:+\:\mathrm{3c}}{\mathrm{2x}\:+\:\mathrm{6a}\:−\:\mathrm{b}\:−\:\mathrm{3c}} \\ $$

Question Number 14535 Answers: 2 Comments: 6

Question Number 14521 Answers: 0 Comments: 0

Question Number 14491 Answers: 1 Comments: 0

(√(25))

$$\sqrt{\mathrm{25}} \\ $$$$ \\ $$

Question Number 14483 Answers: 0 Comments: 8

x^y +y^x =3.....(1) x+y=3.....(2) solve the equation

$$\mathrm{x}^{\mathrm{y}} +\mathrm{y}^{\mathrm{x}} =\mathrm{3}.....\left(\mathrm{1}\right) \\ $$$$\mathrm{x}+\mathrm{y}=\mathrm{3}.....\left(\mathrm{2}\right) \\ $$$$ \\ $$$$\mathrm{solve}\:\mathrm{the}\:\mathrm{equation} \\ $$

Question Number 14435 Answers: 0 Comments: 0

∫e^(−x^2 ) dx=?

$$\int{e}^{−{x}^{\mathrm{2}} } {dx}=? \\ $$

Question Number 14398 Answers: 1 Comments: 0

Solve: (7/2) + ((3y)/(x + y)) = (√x) + 4(√y) .......... equation (i) (x^2 + y^2 )(x + 1) = 4 + 2xy(x − 1) .......... equation (ii)

$$\mathrm{Solve}:\: \\ $$$$\frac{\mathrm{7}}{\mathrm{2}}\:+\:\frac{\mathrm{3y}}{\mathrm{x}\:+\:\mathrm{y}}\:=\:\sqrt{\mathrm{x}}\:+\:\mathrm{4}\sqrt{\mathrm{y}}\:\:\:\:\:\:\:\:\:\:\:\:..........\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \right)\left(\mathrm{x}\:+\:\mathrm{1}\right)\:=\:\mathrm{4}\:+\:\mathrm{2xy}\left(\mathrm{x}\:−\:\mathrm{1}\right)\:\:\:\:..........\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$

Question Number 14396 Answers: 1 Comments: 2

Question Number 14354 Answers: 1 Comments: 0

Question Number 14245 Answers: 0 Comments: 0

pls no; 6,7,10,11,and 13

$$\mathrm{pls}\:\mathrm{no};\:\mathrm{6},\mathrm{7},\mathrm{10},\mathrm{11},\mathrm{and}\:\mathrm{13} \\ $$

Question Number 14244 Answers: 1 Comments: 0

Question Number 14211 Answers: 0 Comments: 11

x^2 +y^2 +xy=4 y^2 +z^2 +yz=9 z^2 +x^2 +zx=16

$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{xy}=\mathrm{4} \\ $$$${y}^{\mathrm{2}} +{z}^{\mathrm{2}} +{yz}=\mathrm{9} \\ $$$${z}^{\mathrm{2}} +{x}^{\mathrm{2}} +{zx}=\mathrm{16} \\ $$

Question Number 14157 Answers: 2 Comments: 11

Question Number 14148 Answers: 2 Comments: 0

Determine (a) i^i (b) ω^ω (c) i^ω (d) ω^i

$$\mathrm{Determine} \\ $$$$\left({a}\right)\:{i}^{{i}} \\ $$$$\left({b}\right)\:\omega^{\omega} \\ $$$$\left({c}\right)\:{i}^{\omega} \\ $$$$\left({d}\right)\:\omega^{{i}} \\ $$

Question Number 14147 Answers: 0 Comments: 1

Determine: (a) e^ω (b) ω^e

$$\mathrm{Determine}: \\ $$$$\left({a}\right)\:\mathrm{e}^{\omega} \\ $$$$\left({b}\right)\:\omega^{\mathrm{e}} \\ $$

Question Number 14119 Answers: 0 Comments: 10

For what values of n∈N, ω^(1/n) can be expressed as ω^m where m∈Z?

$$\mathrm{For}\:\mathrm{what}\:\mathrm{values}\:\mathrm{of}\:\mathrm{n}\in\mathbb{N}, \\ $$$$\omega^{\mathrm{1}/\mathrm{n}} \:\mathrm{can}\:\mathrm{be}\:\mathrm{expressed}\:\mathrm{as}\:\omega^{\mathrm{m}} \\ $$$$\mathrm{where}\:\mathrm{m}\in\mathbb{Z}? \\ $$

Question Number 14113 Answers: 0 Comments: 4

Is this incorrect: S=2×2×... S=2(2×2×...) S=2S S=0 Please explain why

$$\mathrm{Is}\:\mathrm{this}\:\mathrm{incorrect}: \\ $$$${S}=\mathrm{2}×\mathrm{2}×... \\ $$$${S}=\mathrm{2}\left(\mathrm{2}×\mathrm{2}×...\right) \\ $$$${S}=\mathrm{2}{S} \\ $$$${S}=\mathrm{0} \\ $$$$\: \\ $$$$\mathrm{Please}\:\mathrm{explain}\:\mathrm{why} \\ $$

Question Number 14109 Answers: 0 Comments: 3

(a^p −a) mod p = 0 when is this true? a,p∈Z

$$\left({a}^{{p}} −{a}\right)\:\mathrm{mod}\:{p}\:=\:\mathrm{0} \\ $$$$\mathrm{when}\:\mathrm{is}\:\mathrm{this}\:\mathrm{true}? \\ $$$${a},{p}\in\mathbb{Z} \\ $$

Question Number 14046 Answers: 2 Comments: 0

Calculate: (√ω)

$$\mathrm{Calculate}:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\sqrt{\omega} \\ $$

Question Number 14042 Answers: 0 Comments: 2

Can we express ω^(1/2) in terms of whole powers of ω?

$$\mathrm{Can}\:\mathrm{we}\:\mathrm{express}\:\:\omega^{\mathrm{1}/\mathrm{2}} \:\mathrm{in}\:\mathrm{terms} \\ $$$$\mathrm{of}\:\mathrm{whole}\:\mathrm{powers}\:\mathrm{of}\:\omega? \\ $$

Question Number 14002 Answers: 2 Comments: 0

If (√(−1)) = i, then what is the value of (√i) ?

$$\mathrm{If}\:\sqrt{−\mathrm{1}}\:=\:{i},\:\mathrm{then}\: \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\sqrt{{i}}\:? \\ $$

Question Number 13986 Answers: 0 Comments: 4

Solve the following system of equations. (x^2 /(√x))+((√y)/y^2 )=((1729)/(64)) (y^2 /(√x))−((√y)/x^2 )=((6908)/(81))

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{following}\:\mathrm{system} \\ $$$$\mathrm{of}\:\mathrm{equations}. \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{x}^{\mathrm{2}} }{\sqrt{\mathrm{x}}}+\frac{\sqrt{\mathrm{y}}}{\mathrm{y}^{\mathrm{2}} }=\frac{\mathrm{1729}}{\mathrm{64}} \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{y}^{\mathrm{2}} }{\sqrt{\mathrm{x}}}−\frac{\sqrt{\mathrm{y}}}{\mathrm{x}^{\mathrm{2}} }=\frac{\mathrm{6908}}{\mathrm{81}} \\ $$$$ \\ $$

Question Number 13929 Answers: 1 Comments: 0

prove for real x,y and a that (√((x+a)^2 +y^2 ))+(√((x−a)^2 +y^2 ))≥2(√(x^2 +y^2 )) .

$${prove}\:{for}\:{real}\:\boldsymbol{{x}},\boldsymbol{{y}}\:{and}\:\boldsymbol{{a}}\:{that} \\ $$$$\sqrt{\left(\boldsymbol{{x}}+\boldsymbol{{a}}\right)^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} }+\sqrt{\left(\boldsymbol{{x}}−\boldsymbol{{a}}\right)^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} }\geqslant\mathrm{2}\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\:. \\ $$$$ \\ $$

Question Number 13731 Answers: 0 Comments: 1

Prove that if p>q>0 and x≥0 (1/p)((x^p /(p+1))−1)≥(1/q)((x^q /(q+1))−1).

$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:{p}>{q}>\mathrm{0}\:\mathrm{and}\:{x}\geqslant\mathrm{0} \\ $$$$\frac{\mathrm{1}}{{p}}\left(\frac{{x}^{{p}} }{{p}+\mathrm{1}}−\mathrm{1}\right)\geqslant\frac{\mathrm{1}}{{q}}\left(\frac{{x}^{{q}} }{{q}+\mathrm{1}}−\mathrm{1}\right).\: \\ $$

Question Number 13647 Answers: 0 Comments: 6

x^2 +y^2 =5.....(1) 3x^2 +xy+y^2 =1.....(2) please help find x and y

$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\mathrm{5}.....\left(\mathrm{1}\right) \\ $$$$\mathrm{3x}^{\mathrm{2}} +\mathrm{xy}+\mathrm{y}^{\mathrm{2}} =\mathrm{1}.....\left(\mathrm{2}\right) \\ $$$$ \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{find}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y} \\ $$

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