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AlgebraQuestion and Answers: Page 336
Question Number 35153 Answers: 1 Comments: 0
Question Number 35152 Answers: 0 Comments: 2
Question Number 35080 Answers: 2 Comments: 0
$${If}\:\frac{{a}}{{b}+{c}}\:+\frac{{b}}{{c}+{a}}\:+\frac{{c}}{{a}+{b}}=\mathrm{1}\:{then}\:{prove}\:{that} \\ $$$$\frac{{a}^{\mathrm{2}} }{{b}+{c}}\:+\frac{{b}^{\mathrm{2}} }{{c}+{a}}\:+\frac{{c}^{\mathrm{2}} }{{a}+{b}}=\mathrm{0} \\ $$
Question Number 35056 Answers: 0 Comments: 2
$${let}\:{p}\left({x}\right)=\left(\mathrm{1}+{jx}\right)^{{n}} \:−\left(\mathrm{1}−{jx}\right)^{{n}} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{roots}\:{of}\:{p}\left({x}\right) \\ $$$$\left.\mathrm{2}\right){factorize}\:{p}\left({x}\right)\:{inside}\:{C}\left[{x}\right] \\ $$$${j}\:={e}^{{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \:. \\ $$
Question Number 34870 Answers: 3 Comments: 4
Question Number 34760 Answers: 2 Comments: 0
Question Number 34739 Answers: 3 Comments: 3
Question Number 34738 Answers: 0 Comments: 2
Question Number 34686 Answers: 0 Comments: 0
$${decompose}\:{F}\left({x}\right)\:\:=\:\frac{\left(\mathrm{2}{n}\right)!}{\left({x}^{\mathrm{2}} −\mathrm{1}\right)\left({x}^{\mathrm{2}} \:−\mathrm{2}\right)....\left({x}^{\mathrm{2}} \:−{n}\right)} \\ $$
Question Number 34685 Answers: 0 Comments: 0
$${decompose}\:{the}\:{fraction} \\ $$$${F}\left({x}\right)=\:\:\frac{\mathrm{1}}{\left({x}+\mathrm{2}\right)\left(\:{x}^{{n}} \:\:−\mathrm{1}\right)}\:\:{with}\:{n}\:\in\:{N}^{\bigstar} \\ $$
Question Number 34680 Answers: 0 Comments: 0
$${decompose}\:{inside}\:{C}\left({x}\right)\:{the}\:{fraction} \\ $$$${F}\left({x}\right)\:=\:\:\:\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{2}} {cos}\left(\mathrm{2}{a}\right)\:+\mathrm{1}}\:. \\ $$
Question Number 34673 Answers: 0 Comments: 0
$${solve}\:\left(\frac{\mathrm{1}+{iz}}{\mathrm{1}−{iz}}\right)^{{n}} \:=\:\frac{\mathrm{1}+{itan}\alpha}{\mathrm{1}−{itan}\alpha}\:\:{with}\:−\frac{\pi}{\mathrm{2}}<\alpha<\frac{\pi}{\mathrm{2}} \\ $$
Question Number 34669 Answers: 0 Comments: 1
$${let}\:{P}\left({x}\right)=\left(\mathrm{1}+{x}+{ix}^{\mathrm{2}} \right)^{{n}} \:−\left(\mathrm{1}+{x}\:−{ix}^{\mathrm{2}} \right)^{{n}} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{roots}\:{of}\:{P}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{factorize}\:{inside}\:{C}\left[{x}\right]\:{P}\left({x}\right) \\ $$$$\left.\mathrm{3}\right)\:{factorize}\:{indide}\:{R}\left[{x}\right]\:{P}\left({x}\right). \\ $$
Question Number 34668 Answers: 0 Comments: 0
$${find}\:{the}\:{roots}\:{of}?{p}\left({x}\right)\:=\:{x}^{\mathrm{2}{n}} \:−\mathrm{2}{x}^{{n}} \:{cos}\left({n}\theta\right)\:+\mathrm{1} \\ $$$$\left.\mathrm{2}\right)?{factorize}\:{p}\left({x}\right)\: \\ $$
Question Number 34667 Answers: 0 Comments: 0
$${solve}\:\:\left({x}+\mathrm{1}\right)^{{n}} \:=\:{e}^{\mathrm{2}{ina}} \:\:\:{then}\:{find}\:{the}\:{value}\:{of} \\ $$$${P}_{{n}} =\:\prod_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{sin}\left({a}\:+\frac{{k}\pi}{{n}}\right) \\ $$
Question Number 34653 Answers: 0 Comments: 0
Question Number 34615 Answers: 0 Comments: 0
$${decompose}\:{inside}\:{R}\left({x}\right)\:{the}\:{fraction} \\ $$$${F}\left({x}\right)=\:\:\:\frac{{x}^{\mathrm{2}} }{\left({x}+\mathrm{1}\right)^{\mathrm{5}} \left(\:{x}+\mathrm{3}\right)^{\mathrm{8}} } \\ $$
Question Number 34607 Answers: 0 Comments: 0
$${let}\:{p}\in{C}\left[{x}\right]\:{degp}={n}\:\:\:\left({x}_{{i}} \right)_{\mathrm{1}\leqslant{k}\leqslant{n}} {the}\:{roots}\:{of}\:{p}\left({x}\right) \\ $$$${a}\in{C}?/{p}\left({a}\right)\neq\mathrm{0} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{S}_{\mathrm{1}} =\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\frac{\mathrm{1}}{{x}_{{k}} −{a}}\:{interms}\:{of}\:{p},{p}^{'} \:{and}\:{a} \\ $$$$\left.\mathrm{2}\right){calculste}\:{S}_{\mathrm{2}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\mathrm{1}}{\left({x}_{{k}} −{a}\right)^{\mathrm{2}} }\:\:{interms}\:{of}\:{p},{p}^{,} \\ $$$${p}^{''} \:{and}\:{a}. \\ $$
Question Number 34606 Answers: 0 Comments: 0
$${let}\:{give}\:{p}\left({x}\right)=\left({x}+\mathrm{1}\right)^{{n}} \:−\left({x}−\mathrm{1}\right)^{{n}} \\ $$$$\left.\mathrm{1}\right)\:{factorize}\:{p}\left({x}\right)\:{inside}\:{C}\left[{x}\right] \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\prod_{{k}=\mathrm{1}} ^{{p}} \:\:{cotan}\left(\frac{{k}\pi}{\mathrm{2}{p}+\mathrm{1}}\right) \\ $$
Question Number 34604 Answers: 0 Comments: 0
$${let}\:\:{p}\left({x}\right)=\:{x}^{{n}} \:+{x}+\mathrm{1}\:\in{C}\left[{x}\right]\:{and}\:{z}\in{C}/{p}\left({z}\right)=\mathrm{0} \\ $$$${prove}\:{that}\:\mid{z}\mid<\mathrm{2}\:. \\ $$
Question Number 34603 Answers: 0 Comments: 0
$${prove}\:{that}\:\forall\:{p}\in{K}\left[{x}\right]\:{p}\left({x}\right)\:−{x}\:{divide}\:{p}\left({p}\left({x}\right)\right)−{x} \\ $$
Question Number 34602 Answers: 0 Comments: 0
$${simplify}\:\sum_{{k}=\mathrm{0}} ^{{n}} \left(\frac{{k}}{{n}}\:−\alpha\right)^{\mathrm{2}} {C}_{{n}} ^{{k}} \:{x}^{{k}} \left(\mathrm{1}−{x}\right)^{{n}−{k}\:} \\ $$$$\alpha\in{C}. \\ $$
Question Number 34595 Answers: 0 Comments: 0
$${simplify}\:\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} }{{k}}\:{C}_{{n}} ^{{k}} \\ $$
Question Number 34614 Answers: 0 Comments: 1
$${decompose}\:{inside}\:{R}\left({x}\right)\:{the}\:{fraction} \\ $$$${F}\left({x}\right)=\:\frac{\mathrm{1}}{\left({x}−\mathrm{3}\right)^{\mathrm{6}} \left({x}+\mathrm{2}\right)}\:. \\ $$
Question Number 34533 Answers: 2 Comments: 5
$$\mathrm{Solve}\:\mathrm{for}\:\:\mathrm{x}\::\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5}\:\mathrm{log}_{\mathrm{4}} \mathrm{x}\:\:\:+\:\:\:\mathrm{48}\:\mathrm{log}_{\mathrm{x}} \mathrm{4}\:\:\:\:=\:\:\:\:\frac{\mathrm{x}}{\mathrm{8}} \\ $$
Question Number 34429 Answers: 2 Comments: 0
$${Prove}\:{that} \\ $$$$\mathrm{3}^{{m}} +\mathrm{3}^{{n}} +\mathrm{1}\:{is}\:{not}\:{a}\:{perfect}\:{square}. \\ $$$${where}\:{m}\:{and}\:{n}\:{are}\:{positive}\:{integers}. \\ $$
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