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Question Number 41167 Answers: 1 Comments: 0

The LCM and the GCF of three intergers are 180 and 3 respectively. Two numbers are 45 and 60. What is the third number

$${The}\:{LCM}\:{and}\:{the}\:{GCF}\:{of}\:{three} \\ $$$${intergers}\:{are}\:\mathrm{180}\:{and}\:\mathrm{3}\:{respectively}. \\ $$$${Two}\:{numbers}\:{are}\:\mathrm{45}\:{and}\:\mathrm{60}. \\ $$$${What}\:{is}\:{the}\:{third}\:{number} \\ $$

Question Number 41160 Answers: 3 Comments: 3

Question Number 41095 Answers: 1 Comments: 0

For all real values of x solve the inequality ∣((1−x^3 )/(x^6 −2x^3 +5))∣≤(1/4)

$${For}\:{all}\:{real}\:{values}\:{of}\:{x}\:{solve}\:{the} \\ $$$${inequality} \\ $$$$\:\mid\frac{\mathrm{1}−{x}^{\mathrm{3}} }{{x}^{\mathrm{6}} −\mathrm{2}{x}^{\mathrm{3}} +\mathrm{5}}\mid\leqslant\frac{\mathrm{1}}{\mathrm{4}} \\ $$

Question Number 41086 Answers: 1 Comments: 0

A woman is four times older than her daughter. Six years ago the product of their ages is 136. How old is the woman?

$$\mathrm{A}\:\mathrm{woman}\:\mathrm{is}\:\mathrm{four}\:\mathrm{times}\:\mathrm{older}\:\mathrm{than}\: \\ $$$$\mathrm{her}\:\mathrm{daughter}.\:\mathrm{Six}\:\mathrm{years}\:\mathrm{ago}\:\mathrm{the} \\ $$$$\mathrm{product}\:\mathrm{of}\:\mathrm{their}\:\mathrm{ages}\:\mathrm{is}\:\mathrm{136}. \\ $$$$\mathrm{How}\:\mathrm{old}\:\mathrm{is}\:\mathrm{the}\:\mathrm{woman}? \\ $$

Question Number 41044 Answers: 1 Comments: 0

Question Number 41032 Answers: 1 Comments: 0

(a/(x−a)) +(b/(x−b))=2.find x.

$$\frac{{a}}{{x}−{a}}\:+\frac{{b}}{{x}−{b}}=\mathrm{2}.{find}\:{x}. \\ $$

Question Number 47179 Answers: 1 Comments: 0

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Question Number 40764 Answers: 1 Comments: 0

a piece of wire 40cm long is cut into two parts and each part is then bent into a square.if the sum of these squares is 68cm^2 find the lengths of the two pieces of wire.

Question Number 40763 Answers: 2 Comments: 0

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Question Number 40375 Answers: 1 Comments: 0

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Question Number 40222 Answers: 1 Comments: 0

please help Kate was given 602.00 dollas for shopping. She spent (1/4) on chocolate and later (2/3) on goods. How much money was left?

$$\mathrm{please}\:\mathrm{help} \\ $$$$\mathrm{Kate}\:\mathrm{was}\:\mathrm{given}\:\mathrm{602}.\mathrm{00}\:\mathrm{dollas}\:\mathrm{for}\: \\ $$$$\mathrm{shopping}.\:\mathrm{She}\:\mathrm{spent}\:\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{on}\:\mathrm{chocolate} \\ $$$$\mathrm{and}\:\mathrm{later}\:\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{on}\:\mathrm{goods}.\:\mathrm{How}\:\mathrm{much} \\ $$$$\mathrm{money}\:\mathrm{was}\:\mathrm{left}? \\ $$

Question Number 40042 Answers: 0 Comments: 0

1) find the roots of p(x)=(1+ix +x^2 )^n −(1−ix+x^2 )^n with n integr natural 2) factorize p(x) inside C(x) 3) give p(x) at form Σ a_p x^p

$$\left.\mathrm{1}\right)\:{find}\:{the}\:{roots}\:{of}\:\: \\ $$$${p}\left({x}\right)=\left(\mathrm{1}+{ix}\:+{x}^{\mathrm{2}} \right)^{{n}} −\left(\mathrm{1}−{ix}+{x}^{\mathrm{2}} \right)^{{n}} \:{with}\:{n}\:{integr} \\ $$$${natural} \\ $$$$\left.\mathrm{2}\right)\:{factorize}\:{p}\left({x}\right)\:{inside}\:\:{C}\left({x}\right) \\ $$$$\left.\mathrm{3}\right)\:{give}\:{p}\left({x}\right)\:{at}\:{form}\:\:\Sigma\:{a}_{{p}} {x}^{{p}} \\ $$

Question Number 39995 Answers: 2 Comments: 0

Question Number 39971 Answers: 3 Comments: 0

a>0,b>0, What is the minimum value of ((b^2 +2)/(a+b))+(a^2 /(ab+1)) ?

$${a}>\mathrm{0},{b}>\mathrm{0}, \\ $$$${What}\:{is}\:{the}\:{minimum}\:{value}\:{of} \\ $$$$\frac{{b}^{\mathrm{2}} +\mathrm{2}}{{a}+{b}}+\frac{{a}^{\mathrm{2}} }{{ab}+\mathrm{1}}\:\:\:? \\ $$

Question Number 39868 Answers: 2 Comments: 0

a,b,c>0,if ((8a^2 )/(a^2 +9))=b, ((10b^2 )/(b^2 +16))=c, ((6c^2 )/(c^2 +25))=a, then,what is the minimum value of a+b+c?

$${a},{b},{c}>\mathrm{0},{if} \\ $$$$\frac{\mathrm{8}{a}^{\mathrm{2}} }{{a}^{\mathrm{2}} +\mathrm{9}}={b},\:\:\frac{\mathrm{10}{b}^{\mathrm{2}} }{{b}^{\mathrm{2}} +\mathrm{16}}={c},\:\:\frac{\mathrm{6}{c}^{\mathrm{2}} }{{c}^{\mathrm{2}} +\mathrm{25}}={a}, \\ $$$${then},{what}\:{is}\:{the}\:{minimum}\:{value}\:{of}\:\:{a}+{b}+{c}? \\ $$

Question Number 39814 Answers: 2 Comments: 0

kwame, ama and yaw shared an amount of money in the ratio 3:4:5. if ama had $8,400 more than kwame. find the total amount shared.

$$\mathrm{kwame},\:\mathrm{ama}\:\mathrm{and}\:\mathrm{yaw}\:\mathrm{shared}\:\mathrm{an}\:\mathrm{amount}\:\mathrm{of}\:\mathrm{money} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{3}:\mathrm{4}:\mathrm{5}.\:\mathrm{if}\:\mathrm{ama}\:\mathrm{had}\:\$\mathrm{8},\mathrm{400}\:\mathrm{more}\:\mathrm{than}\:\mathrm{kwame}. \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{total}\:\mathrm{amount}\:\mathrm{shared}. \\ $$

Question Number 39783 Answers: 1 Comments: 0

Find roots of f(x)=x^4 −10x^3 +35x^2 −50x+24

$${Find}\:{roots}\:{of} \\ $$$${f}\left({x}\right)={x}^{\mathrm{4}} −\mathrm{10}{x}^{\mathrm{3}} +\mathrm{35}{x}^{\mathrm{2}} −\mathrm{50}{x}+\mathrm{24} \\ $$

Question Number 39779 Answers: 1 Comments: 0

f(x)=x^4 −2x^3 +3x^2 −4x+5 Find the roots.

$${f}\left({x}\right)={x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5} \\ $$$${Find}\:{the}\:{roots}. \\ $$

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