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Question Number 48055    Answers: 2   Comments: 6

Solve the system: { ((x^3 +x^2 y−4xy^2 −4y^3 =0)),((x^2 −2xy−3y^2 −x−y=0)) :}

$${Solve}\:{the}\:{system}: \\ $$$$\begin{cases}{{x}^{\mathrm{3}} +{x}^{\mathrm{2}} {y}−\mathrm{4}{xy}^{\mathrm{2}} −\mathrm{4}{y}^{\mathrm{3}} =\mathrm{0}}\\{{x}^{\mathrm{2}} −\mathrm{2}{xy}−\mathrm{3}{y}^{\mathrm{2}} −{x}−{y}=\mathrm{0}}\end{cases} \\ $$

Question Number 47993    Answers: 0   Comments: 5

Solve in R ((59+(√(x−2))))^(1/3) +((12−(√(x−11))))^(1/3) =6

$${Solve}\:{in}\:\mathbb{R} \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{59}+\sqrt{{x}−\mathrm{2}}}+\sqrt[{\mathrm{3}}]{\mathrm{12}−\sqrt{{x}−\mathrm{11}}}=\mathrm{6} \\ $$

Question Number 47986    Answers: 3   Comments: 1

Question Number 47966    Answers: 1   Comments: 1

a(x^2 +y^2 )+b(x+y)= c & x^2 −y^2 = R^2 Solve for x or y .

$${a}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)+{b}\left({x}+{y}\right)=\:{c} \\ $$$$\:\&\:\:\:\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} \:=\:{R}^{\mathrm{2}} \\ $$$${Solve}\:{for}\:{x}\:{or}\:{y}\:. \\ $$

Question Number 47916    Answers: 2   Comments: 1

Question Number 47807    Answers: 1   Comments: 0

sin xy^2 =y^2 +2x diferential express is

$$\mathrm{sin}\:{xy}^{\mathrm{2}} ={y}^{\mathrm{2}} +\mathrm{2}{x} \\ $$$$ \\ $$$$\mathrm{diferential}\:{express}\:\mathrm{is} \\ $$

Question Number 47778    Answers: 1   Comments: 0

f(x)=2x^3 +x^2 −2x−1 f^(−1) (x)=...

$${f}\left({x}\right)=\mathrm{2}{x}^{\mathrm{3}} +{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{1} \\ $$$${f}^{−\mathrm{1}} \left({x}\right)=... \\ $$

Question Number 47712    Answers: 0   Comments: 0

show that ^(^2 C_2 ) C_n = (1/((1−n)!(n−1)(n−2)(n−3)...3(2)(1)))

$${show}\:{that}\: \\ $$$$\:\:^{\:^{\mathrm{2}} \:{C}_{\mathrm{2}} \:} {C}_{{n}} =\:\frac{\mathrm{1}}{\left(\mathrm{1}−{n}\right)!\left({n}−\mathrm{1}\right)\left({n}−\mathrm{2}\right)\left({n}−\mathrm{3}\right)...\mathrm{3}\left(\mathrm{2}\right)\left(\mathrm{1}\right)} \\ $$

Question Number 47543    Answers: 2   Comments: 0

solve (1+ix)^n =n with x unknown real and n integr natural .

$${solve}\:\left(\mathrm{1}+{ix}\right)^{{n}} ={n}\:\:\:{with}\:{x}\:{unknown}\:{real}\:{and}\:{n}\:{integr}\:{natural}\:. \\ $$

Question Number 47394    Answers: 1   Comments: 1

f(z)=((3z+1)/(2−4z)) f(f(z))=...

$${f}\left({z}\right)=\frac{\mathrm{3}{z}+\mathrm{1}}{\mathrm{2}−\mathrm{4}{z}} \\ $$$${f}\left({f}\left({z}\right)\right)=... \\ $$

Question Number 47391    Answers: 2   Comments: 1

z_1 =3+i z_2 =1−2i determinant ((((2z_2 +z_1 −5−i)/(2z_1 −z_2 +3−i))))^2 =..

$${z}_{\mathrm{1}} =\mathrm{3}+{i} \\ $$$${z}_{\mathrm{2}} =\mathrm{1}−\mathrm{2}{i} \\ $$$$\begin{vmatrix}{\frac{\mathrm{2}{z}_{\mathrm{2}} +{z}_{\mathrm{1}} −\mathrm{5}−{i}}{\mathrm{2}{z}_{\mathrm{1}} −{z}_{\mathrm{2}} +\mathrm{3}−{i}}}\end{vmatrix}^{\mathrm{2}} =.. \\ $$

Question Number 47389    Answers: 0   Comments: 1

((√3)−i)^(1+2i) =...

$$\left(\sqrt{\mathrm{3}}−{i}\right)^{\mathrm{1}+\mathrm{2}{i}} =... \\ $$

Question Number 47331    Answers: 0   Comments: 1

this remained unsolved... ∣x−(3/4)∣×∣x+(5/4)∣=3; x∈C

$$\mathrm{this}\:\mathrm{remained}\:\mathrm{unsolved}... \\ $$$$\mid{x}−\frac{\mathrm{3}}{\mathrm{4}}\mid×\mid{x}+\frac{\mathrm{5}}{\mathrm{4}}\mid=\mathrm{3};\:{x}\in\mathbb{C} \\ $$

Question Number 47291    Answers: 1   Comments: 0

solve for x∈C: ∣x−(3/4)∣×∣x+(5/4)∣=3

$$\mathrm{solve}\:\mathrm{for}\:{x}\in\mathbb{C}: \\ $$$$\mid{x}−\frac{\mathrm{3}}{\mathrm{4}}\mid×\mid{x}+\frac{\mathrm{5}}{\mathrm{4}}\mid=\mathrm{3} \\ $$

Question Number 47239    Answers: 1   Comments: 1

((1.8×10^6 )/(tan(89.9999°))) ∼ π (upto 9 decimal places) can i have some explanations how it is worked out ? Thank you!

$$\frac{\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{6}} }{{tan}\left(\mathrm{89}.\mathrm{9999}°\right)}\:\sim\:\pi\:\left({upto}\:\mathrm{9}\:{decimal}\:{places}\right) \\ $$$${can}\:{i}\:{have}\:{some}\:{explanations}\:{how}\:{it}\:{is}\:{worked}\:{out}\:? \\ $$$${Thank}\:{you}! \\ $$

Question Number 47139    Answers: 1   Comments: 0

Solve for n: 4^n + 2^n − 6 = (2^n − 4)^3 + (4^n − 2)^3 ....

$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{n}:\:\:\:\:\:\:\mathrm{4}^{\mathrm{n}} \:+\:\mathrm{2}^{\mathrm{n}} \:−\:\mathrm{6}\:=\:\left(\mathrm{2}^{\mathrm{n}} \:−\:\mathrm{4}\right)^{\mathrm{3}} \:+\:\left(\mathrm{4}^{\mathrm{n}} \:−\:\mathrm{2}\right)^{\mathrm{3}} \:.... \\ $$

Question Number 47068    Answers: 1   Comments: 0

(a−b)^2

$$\left(\mathrm{a}−\mathrm{b}\right)^{\mathrm{2}} \\ $$

Question Number 47019    Answers: 2   Comments: 2

Question Number 46978    Answers: 2   Comments: 0

Question Number 46974    Answers: 2   Comments: 1

Number of integers n for which 3x^3 −25x+n=0 has three real roots is ?

$${Number}\:{of}\:{integers}\:{n}\:{for}\:{which}\: \\ $$$$\mathrm{3}{x}^{\mathrm{3}} −\mathrm{25}{x}+{n}=\mathrm{0}\:{has}\:{three}\:{real}\:{roots}\:{is}\:? \\ $$$$ \\ $$

Question Number 46973    Answers: 1   Comments: 0

Question Number 46959    Answers: 1   Comments: 5

The reminder when polynomial 1+x^2 +x^4 +x^6 +....+x^(22) is divided by 1+x^ +x^2 +x^3 +.....+x^(11) is =?

$${The}\:{reminder}\:{when}\:{polynomial} \\ $$$$\mathrm{1}+{x}^{\mathrm{2}} +{x}^{\mathrm{4}} +{x}^{\mathrm{6}} +....+{x}^{\mathrm{22}} \:{is}\:{divided}\:{by} \\ $$$$\mathrm{1}+{x}^{} +{x}^{\mathrm{2}} +{x}^{\mathrm{3}} +.....+{x}^{\mathrm{11}} \:{is}\:=? \\ $$

Question Number 46882    Answers: 0   Comments: 2

factorize inside C[x] x^2 +y^2 +z^2

$${factorize}\:{inside}\:{C}\left[{x}\right]\:\:{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} \:+{z}^{\mathrm{2}} \\ $$

Question Number 46881    Answers: 0   Comments: 1

factorize inside C[x] the polynom x^n +y^n

$${factorize}\:{inside}\:{C}\left[{x}\right]\:{the}\:{polynom}\:\:{x}^{{n}} \:+{y}^{{n}} \\ $$

Question Number 46880    Answers: 0   Comments: 0

factorize inside C[x] x^n −y^n with n natural integr

$${factorize}\:{inside}\:{C}\left[{x}\right]\:{x}^{{n}} −{y}^{{n}} \:\:{with}\:{n}\:{natural}\:{integr} \\ $$

Question Number 46785    Answers: 1   Comments: 0

Solve the system: x + y + z = 30 ..... equation (i) (x/3) + (y/2) + 2z = 30 ...... equation (ii)

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{30}\:\:\:\:\:\:\:\:\:.....\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{x}}{\mathrm{3}}\:+\:\frac{\mathrm{y}}{\mathrm{2}}\:+\:\mathrm{2z}\:\:=\:\:\mathrm{30}\:\:\:\:\:......\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\:\: \\ $$

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