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AlgebraQuestion and Answers: Page 274

Question Number 89834    Answers: 1   Comments: 1

Find x e^x = x^2 −1 anyother method apart from Newton′s

$${Find}\:{x}\: \\ $$$$\boldsymbol{{e}}^{\boldsymbol{{x}}} =\:\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{1} \\ $$$$\boldsymbol{{anyother}}\:\boldsymbol{{method}}\:\boldsymbol{{apart}}\:\boldsymbol{{from}}\:\boldsymbol{{N}}{ewton}'{s} \\ $$

Question Number 89829    Answers: 0   Comments: 9

Question Number 89826    Answers: 0   Comments: 0

Solve the equation: x^2 + xy + y^2 = 7 ...... (i) y^2 + yz + z^2 = 3 ...... (ii) z^2 + xz + x^2 = 1 ..... (iii)

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\:\:\:\:\:\:\mathrm{x}^{\mathrm{2}} \:\:+\:\:\mathrm{xy}\:\:+\:\:\mathrm{y}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{7}\:\:\:\:\:\:\:\:\:......\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\mathrm{y}^{\mathrm{2}} \:\:+\:\:\mathrm{yz}\:\:+\:\:\mathrm{z}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{3}\:\:\:\:\:\:\:\:\:\:......\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\mathrm{z}^{\mathrm{2}} \:\:+\:\:\mathrm{xz}\:\:+\:\:\mathrm{x}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:.....\:\left(\mathrm{iii}\right) \\ $$

Question Number 89795    Answers: 1   Comments: 0

Question Number 89794    Answers: 0   Comments: 1

true or false (1+(1/1^3 ))(1+(1/2^3 ))(1+(1/3^3 )).....(1+(1/n^3 ))<3

$${true}\:{or}\:{false} \\ $$$$\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{3}} }\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} }\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} }\right).....\left(\mathrm{1}+\frac{\mathrm{1}}{{n}^{\mathrm{3}} }\right)<\mathrm{3} \\ $$

Question Number 89920    Answers: 0   Comments: 1

x=(1/(1+(1/(1+x)))) and y=(2/(2+(1/(1+y )))) find x+y

$${x}=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}+{x}}}\:{and}\:{y}=\frac{\mathrm{2}}{\mathrm{2}+\frac{\mathrm{1}}{\mathrm{1}+{y}\:}}\:{find}\:{x}+{y} \\ $$

Question Number 89687    Answers: 1   Comments: 3

x^3 +x−16=0

$${x}^{\mathrm{3}} +{x}−\mathrm{16}=\mathrm{0} \\ $$

Question Number 89653    Answers: 1   Comments: 4

Question Number 89586    Answers: 1   Comments: 0

2018^(2019) −2019^(2018 ) ≡? (mod 4)

$$ \\ $$$$\mathrm{2018}^{\mathrm{2019}} −\mathrm{2019}^{\mathrm{2018}\:} \equiv?\:\left({mod}\:\mathrm{4}\right) \\ $$

Question Number 89505    Answers: 1   Comments: 0

Question Number 89454    Answers: 0   Comments: 1

Question Number 89592    Answers: 1   Comments: 2

cos(x)=k {−1≤k<0}

$${cos}\left({x}\right)={k}\: \\ $$$$\left\{−\mathrm{1}\leqslant{k}<\mathrm{0}\right\} \\ $$

Question Number 89385    Answers: 1   Comments: 1

Question Number 89344    Answers: 0   Comments: 6

(2x−1)^2 +8(√(2xy)) = 4 4y−(√(8xy−1)) = 1

$$\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{8}\sqrt{\mathrm{2}{xy}}\:=\:\mathrm{4} \\ $$$$\mathrm{4}{y}−\sqrt{\mathrm{8}{xy}−\mathrm{1}}\:=\:\mathrm{1} \\ $$

Question Number 89300    Answers: 1   Comments: 4

.

$$. \\ $$

Question Number 89292    Answers: 1   Comments: 0

Question Number 89280    Answers: 0   Comments: 0

Question Number 89268    Answers: 0   Comments: 0

Please help with this summation. Σ_(k = 0) ^n (− 1)^k ^n C_k y_(n − k) = ???

$$\boldsymbol{\mathrm{Please}}\:\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{summation}}. \\ $$$$\:\:\:\underset{\boldsymbol{\mathrm{k}}\:\:=\:\:\mathrm{0}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\left(−\:\mathrm{1}\right)^{\boldsymbol{\mathrm{k}}} \:\:\overset{\boldsymbol{\mathrm{n}}} {\:}\boldsymbol{\mathrm{C}}_{\boldsymbol{\mathrm{k}}} \:\boldsymbol{\mathrm{y}}_{\boldsymbol{\mathrm{n}}\:\:−\:\:\boldsymbol{\mathrm{k}}} \:\:\:\:=\:\:\:??? \\ $$

Question Number 89271    Answers: 0   Comments: 1

(3/4)×(8/9)×((15)/(16))×...×((2499)/(2500))

$$\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{8}}{\mathrm{9}}×\frac{\mathrm{15}}{\mathrm{16}}×...×\frac{\mathrm{2499}}{\mathrm{2500}} \\ $$

Question Number 89239    Answers: 0   Comments: 5

A new update has been released to fix issues with android 10. If you have android 10 phone please download latest update.

$$\mathrm{A}\:\mathrm{new}\:\mathrm{update}\:\mathrm{has}\:\mathrm{been}\:\mathrm{released}\:\mathrm{to} \\ $$$$\mathrm{fix}\:\mathrm{issues}\:\mathrm{with}\:\mathrm{android}\:\mathrm{10}.\:\mathrm{If}\:\mathrm{you} \\ $$$$\mathrm{have}\:\mathrm{android}\:\mathrm{10}\:\mathrm{phone}\:\mathrm{please}\:\mathrm{download} \\ $$$$\mathrm{latest}\:\mathrm{update}. \\ $$

Question Number 89187    Answers: 0   Comments: 2

Question Number 89172    Answers: 1   Comments: 0

Question Number 89153    Answers: 1   Comments: 0

If P=((RE^2 )/((R+B)^2 )) make R the subject of the formula.

$$\mathrm{If}\:\mathrm{P}=\frac{\mathrm{RE}^{\mathrm{2}} }{\left(\mathrm{R}+\mathrm{B}\right)^{\mathrm{2}} }\:\mathrm{make}\:\mathrm{R}\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\mathrm{the}\:\mathrm{formula}. \\ $$

Question Number 89130    Answers: 0   Comments: 0

$$ \\ $$

Question Number 89125    Answers: 1   Comments: 0

Question Number 89107    Answers: 0   Comments: 0

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