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AlgebraQuestion and Answers: Page 234

Question Number 123510 Answers: 0 Comments: 0

sorry −(π/2)

$${sorry}\:−\frac{\pi}{\mathrm{2}} \\ $$

Question Number 123509 Answers: 1 Comments: 0

∫_(−(π/)2) ^(π/2) ∣cosx∣=?

$$\underset{−\frac{\pi}{}\mathrm{2}} {\overset{\frac{\pi}{\mathrm{2}}} {\int}}\mid{cosx}\mid=? \\ $$

Question Number 123426 Answers: 0 Comments: 5

find the radii of all circles with center C tangenting the curve h C= ((5),(1) ) h: x^2 −y^2 =1

$$\mathrm{find}\:\mathrm{the}\:\mathrm{radii}\:\mathrm{of}\:\mathrm{all}\:\mathrm{circles}\:\mathrm{with}\:\mathrm{center}\:{C} \\ $$$$\mathrm{tangenting}\:\mathrm{the}\:\mathrm{curve}\:{h} \\ $$$${C}=\begin{pmatrix}{\mathrm{5}}\\{\mathrm{1}}\end{pmatrix} \\ $$$${h}:\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} =\mathrm{1} \\ $$

Question Number 123409 Answers: 1 Comments: 0

x^4 +12x−5=0 show that the sum of two roots of the equation is 2

$${x}^{\mathrm{4}} +\mathrm{12}{x}−\mathrm{5}=\mathrm{0}\:\:\:{show}\:{that}\:{the}\:{sum}\:{of}\:{two}\:{roots} \\ $$$${of}\:{the}\:{equation}\:{is}\:\mathrm{2} \\ $$

Question Number 123362 Answers: 1 Comments: 0

Question Number 123265 Answers: 2 Comments: 2

Question Number 123175 Answers: 1 Comments: 0

Show by recurrence that ∀ n ∈ N, Σ_(k=0 ) ^(n−1) q^k =((q^n −1)/(q−1))

$${Show}\:{by}\:{recurrence}\:{that} \\ $$$$\forall\:{n}\:\in\:\mathbb{N},\:\sum_{{k}=\mathrm{0}\:} ^{{n}−\mathrm{1}} {q}^{{k}} =\frac{{q}^{{n}} −\mathrm{1}}{{q}−\mathrm{1}}\: \\ $$

Question Number 123114 Answers: 2 Comments: 2

Is there any solution(s)?? { ((36x^2 y−27y^3 =8)),((4x^3 −27xy^2 =4)) :} please....

$${Is}\:{there}\:{any}\:{solution}\left({s}\right)?? \\ $$$$\begin{cases}{\mathrm{36}{x}^{\mathrm{2}} {y}−\mathrm{27}{y}^{\mathrm{3}} =\mathrm{8}}\\{\mathrm{4}{x}^{\mathrm{3}} −\mathrm{27}{xy}^{\mathrm{2}} =\mathrm{4}}\end{cases} \\ $$$${please}.... \\ $$

Question Number 123108 Answers: 0 Comments: 2

Question Number 123053 Answers: 0 Comments: 0

Find all P(x) with real coefficients such that P(x^2 +x+1) divides P(x^3 −1)

$${Find}\:{all}\:{P}\left({x}\right)\:{with}\:{real}\:{coefficients}\:{such}\:{that}\: \\ $$$${P}\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)\:{divides}\:{P}\left({x}^{\mathrm{3}} −\mathrm{1}\right) \\ $$

Question Number 123039 Answers: 1 Comments: 0

{ ((3^x +9^(2y) =27)),((2^x +4^(−y) =2^(−3) )) :} x=? y=?

$$\begin{cases}{\mathrm{3}^{{x}} +\mathrm{9}^{\mathrm{2}{y}} =\mathrm{27}}\\{\mathrm{2}^{{x}} +\mathrm{4}^{−{y}} =\mathrm{2}^{−\mathrm{3}} }\end{cases} \\ $$$${x}=?\:{y}=? \\ $$

Question Number 123062 Answers: 1 Comments: 0

Erica′s age is 8 years and her mother is 42. In how many years time will the mother be 3 times as old as her daughter?

$$\mathrm{Erica}'\mathrm{s}\:\mathrm{age}\:\mathrm{is}\:\mathrm{8}\:\mathrm{years}\:\mathrm{and}\:\mathrm{her}\:\mathrm{mother}\:\mathrm{is}\:\mathrm{42}. \\ $$$$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{years}\:\mathrm{time}\:\mathrm{will}\:\mathrm{the}\:\mathrm{mother}\:\mathrm{be} \\ $$$$\mathrm{3}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old}\:\mathrm{as}\:\mathrm{her}\:\mathrm{daughter}? \\ $$

Question Number 123025 Answers: 1 Comments: 4

Question Number 123024 Answers: 1 Comments: 0

Question Number 122957 Answers: 1 Comments: 1

Question Number 122950 Answers: 0 Comments: 1

(√(1+(√(1+2(√(3+...(√(1+2014+(√(1+2015.2016)))))))))) = ?

$$\:\:\sqrt{\mathrm{1}+\sqrt{\mathrm{1}+\mathrm{2}\sqrt{\mathrm{3}+...\sqrt{\mathrm{1}+\mathrm{2014}+\sqrt{\mathrm{1}+\mathrm{2015}.\mathrm{2016}}}}}}\:=\:? \\ $$

Question Number 122897 Answers: 2 Comments: 0

Question Number 122883 Answers: 4 Comments: 2

Σ_1 ^∞ (((sin (x))/x))=?

$$\sum_{\mathrm{1}} ^{\infty} \left(\frac{\mathrm{sin}\:\left(\mathrm{x}\right)}{\mathrm{x}}\right)=? \\ $$

Question Number 122860 Answers: 1 Comments: 0

Question Number 122861 Answers: 0 Comments: 3

is there a formula for this? Σ_(n=0) ^∞ (1/(n^2 +an+b))

$$\mathrm{is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{formula}\:\mathrm{for}\:\mathrm{this}? \\ $$$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} +{an}+{b}} \\ $$

Question Number 122857 Answers: 0 Comments: 0

Question Number 122854 Answers: 1 Comments: 0

Question Number 122821 Answers: 1 Comments: 0

Given { ((x^(ln x+ln y) = 5)),((y^(ln x+ln y) = 2)) :} then { ((x=?)),((y=?)) :}

$$\:{Given}\:\begin{cases}{{x}^{\mathrm{ln}\:{x}+\mathrm{ln}\:{y}} \:=\:\mathrm{5}}\\{{y}^{\mathrm{ln}\:{x}+\mathrm{ln}\:{y}} \:=\:\mathrm{2}}\end{cases} \\ $$$${then}\:\begin{cases}{{x}=?}\\{{y}=?}\end{cases} \\ $$

Question Number 122658 Answers: 0 Comments: 0

we are in C^3 . (S): { ((x+y+z=2i−1 and xyz=2)),((xy+yz+xz=−2(1+i) )) :} P(z)=z^3 +(1−2i)z^2 −2(1+i)−2. show that (a,b,c) is solution of (S) if and only a;b;c are roots of P.

$${we}\:{are}\:{in}\:\mathbb{C}^{\mathrm{3}} . \\ $$$$\left({S}\right):\:\:\begin{cases}{{x}+{y}+{z}=\mathrm{2}{i}−\mathrm{1}\:{and}\:{xyz}=\mathrm{2}}\\{{xy}+{yz}+{xz}=−\mathrm{2}\left(\mathrm{1}+{i}\right)\:}\end{cases} \\ $$$${P}\left({z}\right)={z}^{\mathrm{3}} +\left(\mathrm{1}−\mathrm{2}{i}\right){z}^{\mathrm{2}} −\mathrm{2}\left(\mathrm{1}+{i}\right)−\mathrm{2}. \\ $$$${show}\:{that}\:\left({a},{b},{c}\right)\:{is}\:{solution} \\ $$$${of}\:\left({S}\right)\:{if}\:{and}\:{only}\:{a};{b};{c}\:{are}\: \\ $$$${roots}\:{of}\:{P}. \\ $$

Question Number 122653 Answers: 1 Comments: 0

we define in base x the number y and z by: y=123^(−) ^(x ) and z=201^(−) ^x 1) without knowing x, write the product x×y×z in function of x. 2) we suppose that x+y+z=92 find x;y;z.

$${we}\:{define}\:{in}\:{base}\:{x}\:{the}\: \\ $$$${number}\:{y}\:{and}\:{z}\:{by}: \\ $$$${y}=\overline {\mathrm{123}}\:^{{x}\:} {and}\:{z}=\overline {\mathrm{201}}\:^{{x}} \\ $$$$\left.\mathrm{1}\right)\:{without}\:{knowing}\:{x},\:{write} \\ $$$${the}\:{product}\:{x}×{y}×{z}\:{in}\:{function} \\ $$$${of}\:{x}. \\ $$$$\left.\mathrm{2}\right)\:{we}\:{suppose}\:{that}\:{x}+{y}+{z}=\mathrm{92} \\ $$$${find}\:{x};{y};{z}. \\ $$$$ \\ $$

Question Number 122651 Answers: 1 Comments: 0

show that if 5^(3n) +5^(2n) +5^n +1 is divisible by 13, then n (∈ N) is not a multiple of 4.

$${show}\:{that}\:{if}\: \\ $$$$\mathrm{5}^{\mathrm{3}{n}} +\mathrm{5}^{\mathrm{2}{n}} +\mathrm{5}^{{n}} +\mathrm{1}\:{is}\:{divisible}\:{by} \\ $$$$\mathrm{13},\:{then}\:{n}\:\left(\in\:\mathbb{N}\right)\:{is}\:{not}\:{a}\: \\ $$$${multiple}\:{of}\:\mathrm{4}. \\ $$

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