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AlgebraQuestion and Answers: Page 1

Question Number 227312 Answers: 2 Comments: 0

tg(15) + ctg(5) = ?

$$\mathrm{tg}\left(\mathrm{15}\right)\:+\:\mathrm{ctg}\left(\mathrm{5}\right)\:=\:? \\ $$

Question Number 227306 Answers: 1 Comments: 1

Question Number 227286 Answers: 2 Comments: 0

tg(4) + ctg(4) = ?

$$\mathrm{tg}\left(\mathrm{4}\right)\:+\:\mathrm{ctg}\left(\mathrm{4}\right)\:=\:? \\ $$

Question Number 227247 Answers: 2 Comments: 0

Question Number 227246 Answers: 1 Comments: 0

Question Number 227245 Answers: 2 Comments: 0

Question Number 227194 Answers: 0 Comments: 2

umm.... hi

$${umm}....\:{hi} \\ $$

Question Number 227174 Answers: 1 Comments: 0

Solve the equation (x−2)(dy/dx)−y=(x−2)^3 given y=10 when x=4. 4/1/2026

$${Solve}\:{the}\:{equation} \\ $$$$\left(\boldsymbol{{x}}−\mathrm{2}\right)\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}}−\boldsymbol{{y}}=\left(\boldsymbol{{x}}−\mathrm{2}\right)^{\mathrm{3}} \\ $$$$\boldsymbol{{given}}\:\boldsymbol{{y}}=\mathrm{10}\:\:\boldsymbol{{when}}\:\boldsymbol{{x}}=\mathrm{4}. \\ $$$$\mathrm{4}/\mathrm{1}/\mathrm{2026} \\ $$

Question Number 227162 Answers: 1 Comments: 0

How can I recall an older question? To be precise, number 175409. I have a solution.

$${How}\:{can}\:{I}\:{recall}\:{an}\:{older}\:{question}? \\ $$$${To}\:{be}\:{precise},\:{number}\:\mathrm{175409}.\:{I}\:{have} \\ $$$${a}\:{solution}. \\ $$

Question Number 227124 Answers: 1 Comments: 0

((2025×2026×2027 + 2026))^(1/3) = ?

$$\sqrt[{\mathrm{3}}]{\mathrm{2025}×\mathrm{2026}×\mathrm{2027}\:+\:\mathrm{2026}}\:=\:?\:\:\:\:\:\:\: \\ $$

Question Number 227115 Answers: 2 Comments: 0

prove:Π_(i=1) ^n i sin(1/i)>(1/(n(n+1)))

$$\mathrm{prove}:\underset{{i}=\mathrm{1}} {\overset{{n}} {\prod}}{i}\:\mathrm{sin}\frac{\mathrm{1}}{{i}}>\frac{\mathrm{1}}{{n}\left({n}+\mathrm{1}\right)} \\ $$

Question Number 227085 Answers: 0 Comments: 3

Question Number 226983 Answers: 1 Comments: 0

Question Number 226981 Answers: 0 Comments: 0

Question Number 226991 Answers: 4 Comments: 0

Question Number 226958 Answers: 2 Comments: 0

3^x =x^9 x^2 = ..?

$$\:\:\:\mathrm{3}^{\mathrm{x}} =\mathrm{x}^{\mathrm{9}} \: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{2}} =\:..? \\ $$

Question Number 226912 Answers: 1 Comments: 0

Question Number 226882 Answers: 1 Comments: 0

Question Number 226880 Answers: 1 Comments: 0

Question Number 226879 Answers: 2 Comments: 0

Question Number 226878 Answers: 1 Comments: 0

Question Number 226877 Answers: 3 Comments: 0

Question Number 226901 Answers: 2 Comments: 1

if x+y=2 with x, y >0, find the minimum of x+(√(x^2 +3y^2 )).

$${if}\:{x}+{y}=\mathrm{2}\:{with}\:{x},\:{y}\:>\mathrm{0},\:{find}\:{the} \\ $$$${minimum}\:{of}\:{x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} }. \\ $$

Question Number 226812 Answers: 2 Comments: 1

if 28x+30y+31z=360 with x, y, z being positive integers, find x+y+z=?

$${if}\:\mathrm{28}{x}+\mathrm{30}{y}+\mathrm{31}{z}=\mathrm{360}\:{with}\:{x},\:{y},\:{z} \\ $$$${being}\:{positive}\:{integers},\:{find} \\ $$$${x}+{y}+{z}=? \\ $$

Question Number 226766 Answers: 1 Comments: 0

Question Number 226743 Answers: 0 Comments: 0

Prove:(1/(2ne))<(1/e)−(1−(1/n))^n <(1/(ne))

$$ \\ $$$${Prove}:\frac{\mathrm{1}}{\mathrm{2}{ne}}<\frac{\mathrm{1}}{{e}}−\left(\mathrm{1}−\frac{\mathrm{1}}{{n}}\right)^{{n}} <\frac{\mathrm{1}}{{ne}} \\ $$

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