Question and Answers Forum

All Questions   Topic List

AlgebraQuestion and Answers: Page 1

Question Number 225330    Answers: 1   Comments: 0

if (fogoh)(x)=cos^2 (x+9) then f(x)=? , g(x)=? , h(x)=?

$${if}\:\:\left({fogoh}\right)\left({x}\right)={cos}^{\mathrm{2}} \left({x}+\mathrm{9}\right) \\ $$$${then}\:\:\:{f}\left({x}\right)=?\:,\:\:{g}\left({x}\right)=?\:\:,\:{h}\left({x}\right)=? \\ $$

Question Number 225323    Answers: 1   Comments: 0

Find: (((3 + 2 (5)^(1/4) )/(3 - 2 (5)^(1/4) )))^(1/4) . (((5)^(1/4) - 1)/( (5)^(1/4) + 1)) = ?

$$\mathrm{Find}:\:\:\:\left(\frac{\mathrm{3}\:+\:\mathrm{2}\:\sqrt[{\mathrm{4}}]{\mathrm{5}}}{\mathrm{3}\:-\:\mathrm{2}\:\sqrt[{\mathrm{4}}]{\mathrm{5}}}\right)^{\frac{\mathrm{1}}{\mathrm{4}}} .\:\:\:\frac{\sqrt[{\mathrm{4}}]{\mathrm{5}}\:-\:\mathrm{1}}{\:\sqrt[{\mathrm{4}}]{\mathrm{5}}\:+\:\mathrm{1}}\:\:=\:? \\ $$

Question Number 225282    Answers: 2   Comments: 4

Q225146 here if the wedge and the ground had no friction it would start going → what is acc. at time t? μ=kx

$${Q}\mathrm{225146} \\ $$$${here}\:{if}\:{the}\:{wedge}\:{and}\:{the} \\ $$$${ground}\:\:{had}\:{no}\:{friction} \\ $$$${it}\:{would}\:{start}\:{going}\:\rightarrow \\ $$$${what}\:{is}\:{acc}.\:{at}\:{time}\:{t}? \\ $$$$\mu={kx} \\ $$

Question Number 225230    Answers: 1   Comments: 3

tg^4 10°+tg^4 50°+tg^4 70°=?

$$\:\:\:{tg}^{\mathrm{4}} \mathrm{10}°+{tg}^{\mathrm{4}} \mathrm{50}°+{tg}^{\mathrm{4}} \mathrm{70}°=? \\ $$

Question Number 225240    Answers: 1   Comments: 0

Question Number 225239    Answers: 0   Comments: 0

Question Number 225241    Answers: 1   Comments: 0

Question Number 225153    Answers: 0   Comments: 0

Question Number 225152    Answers: 0   Comments: 0

Question Number 225150    Answers: 0   Comments: 0

Question Number 225075    Answers: 2   Comments: 0

Question Number 225098    Answers: 2   Comments: 0

Question Number 225020    Answers: 0   Comments: 1

tgx+tgy+tgz=A tg^3 x+tg^3 y+tg^3 z=?

$$\:\:\:{tgx}+{tgy}+{tgz}={A} \\ $$$$\:\:\:{tg}^{\mathrm{3}} {x}+{tg}^{\mathrm{3}} {y}+{tg}^{\mathrm{3}} {z}=? \\ $$

Question Number 224989    Answers: 1   Comments: 0

Calculate D_n = determinant (((x_1 +a_1 ^2 ),(a_1 a_2 ),…,(a_1 a_n )),((a_2 a_1 ),(x_2 +a_2 ^2 ),…,(a_2 a_n )),(⋮,⋮,⋱,⋮),((a_n a_1 ),(a_n a_2 ),…,(x_n +a_n ^2 )))

$$\mathrm{Calculate} \\ $$$${D}_{{n}} =\begin{vmatrix}{{x}_{\mathrm{1}} +{a}_{\mathrm{1}} ^{\mathrm{2}} }&{{a}_{\mathrm{1}} {a}_{\mathrm{2}} }&{\ldots}&{{a}_{\mathrm{1}} {a}_{{n}} }\\{{a}_{\mathrm{2}} {a}_{\mathrm{1}} }&{{x}_{\mathrm{2}} +{a}_{\mathrm{2}} ^{\mathrm{2}} }&{\ldots}&{{a}_{\mathrm{2}} {a}_{{n}} }\\{\vdots}&{\vdots}&{\ddots}&{\vdots}\\{{a}_{{n}} {a}_{\mathrm{1}} }&{{a}_{{n}} {a}_{\mathrm{2}} }&{\ldots}&{{x}_{{n}} +{a}_{{n}} ^{\mathrm{2}} }\end{vmatrix} \\ $$

Question Number 224888    Answers: 0   Comments: 2

Question Number 224886    Answers: 1   Comments: 0

Find for acute θ, sin θ and cos θ in terms of 0<k<1, if ((sin θ(1−cos θ))/(cos θ(1−sin θ)))=k.

$${Find}\:{for}\:{acute}\:\theta,\:\mathrm{sin}\:\theta\:{and}\:\mathrm{cos}\:\theta \\ $$$${in}\:{terms}\:{of}\:\mathrm{0}<{k}<\mathrm{1}, \\ $$$${if}\:\:\:\:\frac{\mathrm{sin}\:\theta\left(\mathrm{1}−\mathrm{cos}\:\theta\right)}{\mathrm{cos}\:\theta\left(\mathrm{1}−\mathrm{sin}\:\theta\right)}={k}. \\ $$

Question Number 224873    Answers: 0   Comments: 5

Question Number 224872    Answers: 0   Comments: 0

Question Number 224847    Answers: 0   Comments: 0

Question Number 224819    Answers: 2   Comments: 0

Question Number 224770    Answers: 0   Comments: 1

(2x^3 +x−3)^3 =3−x^2

$$\:\:\:\left(\mathrm{2}{x}^{\mathrm{3}} +{x}−\mathrm{3}\right)^{\mathrm{3}} =\mathrm{3}−{x}^{\mathrm{2}} \\ $$

Question Number 224763    Answers: 1   Comments: 3

Question Number 224728    Answers: 2   Comments: 2

Question Number 224637    Answers: 0   Comments: 0

Question Number 224635    Answers: 1   Comments: 0

Prove that: sin(54°) = (((√5) + 1)/4)

$$\mathrm{Prove}\:\mathrm{that}:\:\:\:\mathrm{sin}\left(\mathrm{54}°\right)\:=\:\:\frac{\sqrt{\mathrm{5}}\:+\:\mathrm{1}}{\mathrm{4}} \\ $$

Question Number 224629    Answers: 4   Comments: 0

  Pg 1      Pg 2      Pg 3      Pg 4      Pg 5      Pg 6      Pg 7      Pg 8      Pg 9      Pg 10   

Terms of Service

Privacy Policy

Contact: info@tinkutara.com