Question Number 134627 by bobhans last updated on 05/Mar/21 | ||
$$\mathcal{ALGEBRA} \\ $$If Bobby walks to school at 50m/min. He will be late for 3 minutes. If he walks 60 m/min, he arrives at school early by 2 mins. What is the distance between Bobby's home and school? | ||
Answered by som(math1967) last updated on 06/Mar/21 | ||
$$\:\:\frac{{x}}{\mathrm{50}}\:−\frac{{x}}{\mathrm{60}}=\mathrm{5}\:\:\:\:\:\left[{x}={dist}.\:{between}\right. \\ $$$$\left.\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{Bobby}'{s}\boldsymbol{{home}}\:\boldsymbol{{an}}\:\boldsymbol{{school}}\right] \\ $$$$\Rightarrow\frac{\mathrm{6}{x}−\mathrm{5}{x}}{\mathrm{300}}=\mathrm{5} \\ $$$$\Rightarrow{x}=\mathrm{1500} \\ $$$${Distance}\:{between}\:{Bobby}'{s} \\ $$$${home}\:{and}\:{school}=\mathrm{1500}{m} \\ $$ | ||