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Question Number 358 by 123456 last updated on 25/Jan/15
![A= [(x,(−y)),(y,x) ] X= [(x),(y) ] Y=AX](Q358.png)
$$\mathrm{A}=\begin{bmatrix}{{x}}&{−{y}}\\{{y}}&{{x}}\end{bmatrix} \\ $$$$\mathrm{X}=\begin{bmatrix}{{x}}\\{{y}}\end{bmatrix} \\ $$$$\mathrm{Y}=\mathrm{AX} \\ $$
Answered by prakash jain last updated on 24/Dec/14
![AX= [((x^2 −y^2 )),((2xy)) ]](Q361.png)
$${AX}=\begin{bmatrix}{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }\\{\mathrm{2}{xy}}\end{bmatrix} \\ $$