Question Number 209822 by SonGoku last updated on 22/Jul/24
$$\mathrm{A}\:\mathrm{ramp}\:\mathrm{is}\:\mathrm{supported}\:\mathrm{by}\:\mathrm{six}\:\mathrm{pillars}\:\mathrm{and}\:\mathrm{the}\:\mathrm{talleste} \\ $$$$\mathrm{on}\:\mathrm{measures}\:\mathrm{6}\:\mathrm{meters}.\:\mathrm{The}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{eachi} \\ $$$$\mathrm{pllar}\:\mathrm{is}\:\mathrm{5}\:\mathrm{meters}.\:\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{height}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{third}\:\mathrm{pillar}?\: \\ $$
Commented by mr W last updated on 22/Jul/24
$$\frac{{h}_{\mathrm{3}} }{\mathrm{6}}=\frac{\mathrm{4}×\mathrm{5}}{\mathrm{6}×\mathrm{5}} \\ $$$$\Rightarrow{h}_{\mathrm{3}} =\mathrm{4}\:{m} \\ $$
Commented by SonGoku last updated on 22/Jul/24
$$\mathrm{Did}\:\mathrm{you}\:\mathrm{use}\:\mathrm{triangle}\:\mathrm{similarity}? \\ $$
Commented by mr W last updated on 22/Jul/24
Commented by mr W last updated on 22/Jul/24
$$\frac{\mathrm{6}{m}}{\mathrm{5}}=\mathrm{1}.\mathrm{2}\:{m} \\ $$
Commented by mr W last updated on 22/Jul/24
$${then}\:{you}\:{should}\:{have}\:{enclosed}\:{this} \\ $$$${figure}! \\ $$$${without}\:{this}\:{figure}\:{people}\:{may}\:{also} \\ $$$${understand}\:{the}\:{question}\:{in}\:{the}\:{way} \\ $$$${as}\:{i}\:{showed}\:{in}\:{my}\:{diagram}. \\ $$
Commented by SonGoku last updated on 22/Jul/24
Commented by SonGoku last updated on 22/Jul/24
$$\mathrm{I}\:\mathrm{was}\:\mathrm{having}\:\mathrm{trouble}\:\mathrm{attaching}\:\mathrm{the}\:\mathrm{image}. \\ $$
Commented by SonGoku last updated on 23/Jul/24
$$\mathrm{Thank}\:\mathrm{you}! \\ $$