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Question Number 11417 by Joel576 last updated on 25/Mar/17

A = log (5x + 1)(3x + 5)  B = (1/(log (5x+ 1)(x − 1)))  If A + B ≥ 1, x must be ...

$${A}\:=\:\mathrm{log}\:\left(\mathrm{5}{x}\:+\:\mathrm{1}\right)\left(\mathrm{3}{x}\:+\:\mathrm{5}\right) \\ $$$${B}\:=\:\frac{\mathrm{1}}{\mathrm{log}\:\left(\mathrm{5}{x}+\:\mathrm{1}\right)\left({x}\:−\:\mathrm{1}\right)} \\ $$$$\mathrm{If}\:{A}\:+\:{B}\:\geqslant\:\mathrm{1},\:{x}\:\mathrm{must}\:\mathrm{be}\:... \\ $$

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