Question Number 104143 by aurpeyz last updated on 19/Jul/20 | ||
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$$\mathrm{A}\:\mathrm{Satellite}\:\mathrm{orbits}\:\mathrm{the}\:\mathrm{esrth}\:\mathrm{in}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{rsdius}\:\mathrm{8000km}.\:\mathrm{At}\:\mathrm{that}\:\mathrm{distance}\:\mathrm{from}\:\mathrm{the}\:\mathrm{earth}\:\mathrm{g}=\mathrm{6}.\mathrm{2m}/\mathrm{s2}.\:\mathrm{The}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{satelliege}\:\mathrm{is}? \\ $$ | ||
Commented by aurpeyz last updated on 19/Jul/20 | ||
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$$\mathrm{pls}\:\mathrm{help} \\ $$ | ||
Answered by OlafThorendsen last updated on 19/Jul/20 | ||
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$$\overset{\rightarrow} {\mathrm{F}}\:=\:{m}\overset{\rightarrow} {{g}}\:=\:{m}\overset{\rightarrow} {{a}}_{\mathrm{N}} =\:{m}\frac{{v}^{\mathrm{2}} }{\mathrm{R}}\overset{\rightarrow} {{u}} \\ $$$$\Rightarrow\:{v}\:=\:\sqrt{{g}\mathrm{R}}\:=\:\sqrt{\mathrm{6},\mathrm{2}×\mathrm{8}.\mathrm{10}^{\mathrm{6}} } \\ $$$${v}\:=\:\mathrm{7},\mathrm{042}\:{km}/{s} \\ $$ | ||
Commented by aurpeyz last updated on 20/Jul/20 | ||
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$$\mathrm{thnks} \\ $$ | ||
Commented by aurpeyz last updated on 01/Aug/20 | ||
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$${pls}\:{how}\:{did}\:{you}\:{get}\:{R}\:{as}\:\mathrm{8}.\mathrm{10}^{\mathrm{6}} ? \\ $$ | ||