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Question Number 91012 by jagoll last updated on 27/Apr/20

(dy/dx) + 2xy = xe^(−x^2 ) y^3

$$\frac{{dy}}{{dx}}\:+\:\mathrm{2}{xy}\:=\:{xe}^{−{x}^{\mathrm{2}} } {y}^{\mathrm{3}} \\ $$

Answered by john santu last updated on 27/Apr/20

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