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Question Number 89848 by 9933039645 last updated on 19/Apr/20

Q1. If sinθ=(3/5) then find the value of tanθ+cotθ

$${Q}\mathrm{1}.\:{If}\:{sin}\theta=\frac{\mathrm{3}}{\mathrm{5}}\:{then}\:{find}\:{the}\:{value}\:{of}\:{tan}\theta+{cot}\theta \\ $$

Commented by mahdi last updated on 19/Apr/20

±((25)/(12))  sinθ=(3/5)⇒∣cosθ∣=(√(1−sin^2 θ))=(4/5)  tanθ=((sinθ)/(cosθ))=±(3/4)      cotθ=(1/(tanθ))=±(4/3)

$$\pm\frac{\mathrm{25}}{\mathrm{12}} \\ $$$$\mathrm{sin}\theta=\frac{\mathrm{3}}{\mathrm{5}}\Rightarrow\mid\mathrm{cos}\theta\mid=\sqrt{\mathrm{1}−\mathrm{sin}^{\mathrm{2}} \theta}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$$\mathrm{tan}\theta=\frac{\mathrm{sin}\theta}{\mathrm{cos}\theta}=\pm\frac{\mathrm{3}}{\mathrm{4}}\:\:\:\:\:\:\mathrm{cot}\theta=\frac{\mathrm{1}}{\mathrm{tan}\theta}=\pm\frac{\mathrm{4}}{\mathrm{3}} \\ $$

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