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Question Number 75186 by Hassen_Timol last updated on 08/Dec/19

7n ≡ 1 (mod 5)  What is the general form of n ?

7n1(mod5)Whatisthegeneralformofn?

Commented by mr W last updated on 08/Dec/19

7n=5m+1  ⇒n=5k+3

7n=5m+1n=5k+3

Commented by Hassen_Timol last updated on 08/Dec/19

How do you get that from first to second  line, please Sir ?

Howdoyougetthatfromfirsttosecondline,pleaseSir?

Commented by mr W last updated on 08/Dec/19

see my comment inQ19198 or here:

seemycommentinQ19198orhere:

Commented by mr W last updated on 08/Dec/19

Commented by Hassen_Timol last updated on 08/Dec/19

Thank you sir, may god bless you

Thankyousir,maygodblessyou

Commented by mr W last updated on 08/Dec/19

see also Q66832 for other methods

seealsoQ66832forothermethods

Commented by jagannath.02 last updated on 08/Dec/19

sir please solve the thermodynamics question thag i have posted... please sir..

sirpleasesolvethethermodynamicsquestionthagihaveposted...pleasesir..

Answered by Rio Michael last updated on 08/Dec/19

7n ≡ 1(mod 5)  by trial and error we look for   a number n which when multiplied to   7 gives a remainder of 1 when divided by 5.   so   n=1 does not work  n = 2 does not work  n = 3 ⇒ 7(3) = 21    21 = 4(5) + 1 remainder of 1 hence it works  ∴  n = 3 and we write  n ≡ 3(mod 5)  hence n = 5k + 3,  k∈Z

7n1(mod5)bytrialanderrorwelookforanumbernwhichwhenmultipliedto7givesaremainderof1whendividedby5.son=1doesnotworkn=2doesnotworkn=37(3)=2121=4(5)+1remainderof1henceitworksn=3andwewriten3(mod5)hencen=5k+3,kZ

Commented by Hassen_Timol last updated on 09/Dec/19

Thank you Sir

ThankyouSir

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