Question Number 111643 by Dwaipayan Shikari last updated on 04/Sep/20 | ||
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$$\left(\frac{\mathrm{7}}{\mathrm{3}}\right)!\left({with}\:{out}\:{calculator}\right) \\ $$ | ||
Answered by mathdave last updated on 04/Sep/20 | ||
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$${solution}\: \\ $$$${but}\:{x}!=\Gamma\left({x}+\mathrm{1}\right) \\ $$$${let}\left(\frac{\mathrm{7}}{\mathrm{3}}\right)!=\Gamma\left(\frac{\mathrm{10}}{\mathrm{3}}\right)=\mathrm{2}.\mathrm{8871} \\ $$ | ||
Commented by Dwaipayan Shikari last updated on 04/Sep/20 | ||
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$$\left.{I}\:{have}\:{edited}\:{the}\:{question}:\right) \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 04/Sep/20 | ||
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$${Cool}\:{Mr}\:{mathdave}\:{cool}! \\ $$$${Control}\:{your}\:{temper}\:{please}! \\ $$ | ||
Commented by Tawa11 last updated on 06/Sep/21 | ||
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$$\mathrm{great}\:\mathrm{sir} \\ $$ | ||