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Question Number 69616 by azizullah last updated on 25/Sep/19

Commented by Prithwish sen last updated on 25/Sep/19

After 10 years the sum will be 40+20=60 years  After 10 years     shabena will be = (1/3)×60 = 20 years  maria will be =(2/3) ×60 = 40 years  ∴ At present  Shabena is =20 −10 = 10 years  Maria is = 40 −10 = 30 years

$$\mathrm{After}\:\mathrm{10}\:\mathrm{years}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{will}\:\mathrm{be}\:\mathrm{40}+\mathrm{20}=\mathrm{60}\:\mathrm{years} \\ $$$$\mathrm{After}\:\mathrm{10}\:\mathrm{years} \\ $$$$\:\:\:\mathrm{shabena}\:\mathrm{will}\:\mathrm{be}\:=\:\frac{\mathrm{1}}{\mathrm{3}}×\mathrm{60}\:=\:\mathrm{20}\:\mathrm{years} \\ $$$$\mathrm{maria}\:\mathrm{will}\:\mathrm{be}\:=\frac{\mathrm{2}}{\mathrm{3}}\:×\mathrm{60}\:=\:\mathrm{40}\:\mathrm{years} \\ $$$$\therefore\:\mathrm{At}\:\mathrm{present} \\ $$$$\mathrm{Shabena}\:\mathrm{is}\:=\mathrm{20}\:−\mathrm{10}\:=\:\mathrm{10}\:\mathrm{years} \\ $$$$\mathrm{Maria}\:\mathrm{is}\:=\:\mathrm{40}\:−\mathrm{10}\:=\:\mathrm{30}\:\mathrm{years} \\ $$

Commented by TawaTawa last updated on 25/Sep/19

Let maira′s age = x  Let shaheena′s age = y  ∴  x + y = 40  Here,    x = 40 − y  after 10 years,   maira = x + 10  after 10 years,   shaheena = y + 10  ∴     x + 10 = 2(y + 10)  ∴     x + 10 = 2y + 20  ∴     40 − y + 10 = 2y + 20  ∴     50 − y = 2y + 20  ∴     2y + y = 50 − 20  ∴     3y = 30  ∴          y = ((30)/3)  ∴          y = 10  Then,     x = 40 − 10  Then,     x = 30  ∴  maira′s age = 30  ∴   shaheena′s age = 10

$$\mathrm{Let}\:\mathrm{maira}'\mathrm{s}\:\mathrm{age}\:=\:\mathrm{x} \\ $$$$\mathrm{Let}\:\mathrm{shaheena}'\mathrm{s}\:\mathrm{age}\:=\:\mathrm{y} \\ $$$$\therefore\:\:\mathrm{x}\:+\:\mathrm{y}\:=\:\mathrm{40} \\ $$$$\mathrm{Here},\:\:\:\:\mathrm{x}\:=\:\mathrm{40}\:−\:\mathrm{y} \\ $$$$\mathrm{after}\:\mathrm{10}\:\mathrm{years},\:\:\:\mathrm{maira}\:=\:\mathrm{x}\:+\:\mathrm{10} \\ $$$$\mathrm{after}\:\mathrm{10}\:\mathrm{years},\:\:\:\mathrm{shaheena}\:=\:\mathrm{y}\:+\:\mathrm{10} \\ $$$$\therefore\:\:\:\:\:\mathrm{x}\:+\:\mathrm{10}\:=\:\mathrm{2}\left(\mathrm{y}\:+\:\mathrm{10}\right) \\ $$$$\therefore\:\:\:\:\:\mathrm{x}\:+\:\mathrm{10}\:=\:\mathrm{2y}\:+\:\mathrm{20} \\ $$$$\therefore\:\:\:\:\:\mathrm{40}\:−\:\mathrm{y}\:+\:\mathrm{10}\:=\:\mathrm{2y}\:+\:\mathrm{20} \\ $$$$\therefore\:\:\:\:\:\mathrm{50}\:−\:\mathrm{y}\:=\:\mathrm{2y}\:+\:\mathrm{20} \\ $$$$\therefore\:\:\:\:\:\mathrm{2y}\:+\:\mathrm{y}\:=\:\mathrm{50}\:−\:\mathrm{20} \\ $$$$\therefore\:\:\:\:\:\mathrm{3y}\:=\:\mathrm{30} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\mathrm{y}\:=\:\frac{\mathrm{30}}{\mathrm{3}} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\mathrm{y}\:=\:\mathrm{10} \\ $$$$\mathrm{Then},\:\:\:\:\:\mathrm{x}\:=\:\mathrm{40}\:−\:\mathrm{10} \\ $$$$\mathrm{Then},\:\:\:\:\:\mathrm{x}\:=\:\mathrm{30} \\ $$$$\therefore\:\:\mathrm{maira}'\mathrm{s}\:\mathrm{age}\:=\:\mathrm{30} \\ $$$$\therefore\:\:\:\mathrm{shaheena}'\mathrm{s}\:\mathrm{age}\:=\:\mathrm{10} \\ $$

Commented by azizullah last updated on 26/Sep/19

        sir! thanks alot.....

$$\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{sir}}!\:\boldsymbol{\mathrm{thanks}}\:\boldsymbol{\mathrm{alot}}..... \\ $$

Commented by azizullah last updated on 26/Sep/19

       Alot of thanks sir!

$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{Alot}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{thanks}}\:\boldsymbol{\mathrm{sir}}! \\ $$

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