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Question Number 68629 by TawaTawa last updated on 14/Sep/19

Answered by $@ty@m123 last updated on 14/Sep/19

∠XYT=∠XTP  ⇒∠XYT=50^o   Let ∠YXT=∠XTY=x  ⇒x+x+50^o =180^o   ⇒x=((130)/2)  ⇒∠YXT=50^o   ⇒∠TZY=50^o

$$\angle{XYT}=\angle{XTP} \\ $$$$\Rightarrow\angle{XYT}=\mathrm{50}^{\mathrm{o}} \\ $$$$\mathrm{L}{et}\:\angle{YXT}=\angle{XTY}={x} \\ $$$$\Rightarrow{x}+{x}+\mathrm{50}^{\mathrm{o}} =\mathrm{180}^{\mathrm{o}} \\ $$$$\Rightarrow{x}=\frac{\mathrm{130}}{\mathrm{2}} \\ $$$$\Rightarrow\angle{YXT}=\mathrm{50}^{\mathrm{o}} \\ $$$$\Rightarrow\angle{TZY}=\mathrm{50}^{\mathrm{o}} \: \\ $$

Commented by TawaTawa last updated on 17/Sep/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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