Question and Answers Forum

All Questions      Topic List

Electric Current and Circuits Questions

Previous in All Question      Next in All Question      

Previous in Electric Current and Circuits      Next in Electric Current and Circuits      

Question Number 68062 by aseer imad last updated on 04/Sep/19

Commented by mind is power last updated on 04/Sep/19

2=(5/3)+(5/R)⇒R=15Ω  E=10.2+2.2+(((3.15)/(3+15))).2=24+5=29v

$$\mathrm{2}=\frac{\mathrm{5}}{\mathrm{3}}+\frac{\mathrm{5}}{{R}}\Rightarrow{R}=\mathrm{15}\Omega \\ $$$${E}=\mathrm{10}.\mathrm{2}+\mathrm{2}.\mathrm{2}+\left(\frac{\mathrm{3}.\mathrm{15}}{\mathrm{3}+\mathrm{15}}\right).\mathrm{2}=\mathrm{24}+\mathrm{5}=\mathrm{29}{v} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com