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Question Number 68062 by aseer imad last updated on 04/Sep/19
Commented by mind is power last updated on 04/Sep/19
$$\mathrm{2}=\frac{\mathrm{5}}{\mathrm{3}}+\frac{\mathrm{5}}{{R}}\Rightarrow{R}=\mathrm{15}\Omega \\ $$$${E}=\mathrm{10}.\mathrm{2}+\mathrm{2}.\mathrm{2}+\left(\frac{\mathrm{3}.\mathrm{15}}{\mathrm{3}+\mathrm{15}}\right).\mathrm{2}=\mathrm{24}+\mathrm{5}=\mathrm{29}{v} \\ $$