Question Number 67820 by angezbcn last updated on 31/Aug/19 | ||
$${x}^{\mathrm{3}} −{x}^{\mathrm{2}} −\mathrm{6}{x} \\ $$ | ||
Commented by mr W last updated on 01/Sep/19 | ||
$$={x}\left({x}^{\mathrm{2}} −{x}−\mathrm{6}\right) \\ $$$$={x}\left({x}+\mathrm{2}\right)\left({x}−\mathrm{3}\right) \\ $$ | ||