Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 5189 by sanusihammed last updated on 28/Apr/16

Commented by FilupSmith last updated on 28/Apr/16

Q1  V=IR  I=(V/R) ⇒ I=((12)/(16+8))  I=(1/2)    Voltage over 16ohm:  V=IR  V=(1/2)∙16  V_1 =8v    Voltage over 8ohm:  V=IR  V=(1/2)∙8  V_2 =4    Chect voltages:  V=V_1 +V_2   12=8+4  12=12  ∴Correct

$${Q}\mathrm{1} \\ $$$${V}={IR} \\ $$$${I}=\frac{{V}}{{R}}\:\Rightarrow\:{I}=\frac{\mathrm{12}}{\mathrm{16}+\mathrm{8}} \\ $$$${I}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$ \\ $$$$\mathrm{Voltage}\:\mathrm{over}\:\mathrm{16ohm}: \\ $$$${V}={IR} \\ $$$${V}=\frac{\mathrm{1}}{\mathrm{2}}\centerdot\mathrm{16} \\ $$$${V}_{\mathrm{1}} =\mathrm{8}{v} \\ $$$$ \\ $$$$\mathrm{Voltage}\:\mathrm{over}\:\mathrm{8ohm}: \\ $$$${V}={IR} \\ $$$${V}=\frac{\mathrm{1}}{\mathrm{2}}\centerdot\mathrm{8} \\ $$$${V}_{\mathrm{2}} =\mathrm{4} \\ $$$$ \\ $$$$\mathrm{Chect}\:\mathrm{voltages}: \\ $$$${V}={V}_{\mathrm{1}} +{V}_{\mathrm{2}} \\ $$$$\mathrm{12}=\mathrm{8}+\mathrm{4} \\ $$$$\mathrm{12}=\mathrm{12} \\ $$$$\therefore\mathrm{Correct} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com