Question Number 51649 by byaw last updated on 29/Dec/18 | ||
$$\mathrm{It}\:\mathrm{takes}\:\mathrm{man}\:\mathrm{A}\:\mathrm{6}\:\mathrm{days}\:\mathrm{to}\:\mathrm{a}\:\mathrm{piece}\:\mathrm{of} \\ $$$$\mathrm{work}.\:\mathrm{It}\:\mathrm{takes}\:\mathrm{man}\:\mathrm{B}\:\mathrm{4}\:\mathrm{days}\:\mathrm{to}\:\mathrm{do}\: \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{piece}\:\mathrm{of}\:\mathrm{work}.\:\mathrm{How}\:\mathrm{many} \\ $$$$\mathrm{days}\:\mathrm{will}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{take}\:\mathrm{to}\:\mathrm{do}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{piece}\:\mathrm{of}\:\mathrm{work}? \\ $$ | ||
Answered by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 | ||
$${A}\:{perform}\:\frac{\mathrm{1}}{\mathrm{6}}{th}\:{portion}\:{in}\:\mathrm{1}{day} \\ $$$${B}\:{perform}\:\frac{\mathrm{1}}{\mathrm{4}}{th}\:{portion}\:{in}\:\mathrm{1}\:{day} \\ $$$${A}+{B}\:{perform}\:\left(\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{6}}\right)=\left(\frac{\mathrm{3}+\mathrm{2}}{\mathrm{12}}\right)=\frac{\mathrm{5}}{\mathrm{12}}\:{in}\:\mathrm{1}\:{day} \\ $$$${so}\:{A}+{B}\:{complete}\:{work}\:{in}\left(\frac{\mathrm{12}}{\mathrm{5}}\right){days}\:{together} \\ $$ | ||
Answered by aseerimad last updated on 29/Dec/18 | ||
Commented by aseerimad last updated on 29/Dec/18 | ||
$${oh}\:{srry}..{tanmay}\:{sir}\:{already}\:{answered}. \\ $$ | ||