Question Number 62047 by hhghg last updated on 14/Jun/19 | ||
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$$\left(\mathrm{4y}\right)^{\mathrm{2}} \\ $$ | ||
Commented by maxmathsup by imad last updated on 15/Jun/19 | ||
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$$=\left(\mathrm{4}{y}\right)×\left(\mathrm{4}{y}\right)\:=\mathrm{16}{y}^{\mathrm{2}} \\ $$ | ||