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Question Number 49197 by Tawa1 last updated on 04/Dec/18

A bus travelling along a straight road at 100 km/hr  and the bus   conductor walks at 6 km/hr on the floor of the bus and in the same  direction as the bus.   Find the speed of the conductor relative to the road, and relative to the  bus.  If the bus conductor now walks at the same rate but in opposite  direction as the bus,  find his new speed relative to the road.    Answers  106 km/hr ,      64 km/hr ,         94 km/hr

$$\mathrm{A}\:\mathrm{bus}\:\mathrm{travelling}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{at}\:\mathrm{100}\:\mathrm{km}/\mathrm{hr}\:\:\mathrm{and}\:\mathrm{the}\:\mathrm{bus}\: \\ $$$$\mathrm{conductor}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{6}\:\mathrm{km}/\mathrm{hr}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{conductor}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road},\:\mathrm{and}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{bus}.\:\:\mathrm{If}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{now}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{rate}\:\mathrm{but}\:\mathrm{in}\:\mathrm{opposite} \\ $$$$\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus},\:\:\mathrm{find}\:\mathrm{his}\:\mathrm{new}\:\mathrm{speed}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road}. \\ $$$$ \\ $$$$\mathrm{Answers} \\ $$$$\mathrm{106}\:\mathrm{km}/\mathrm{hr}\:,\:\:\:\:\:\:\mathrm{64}\:\mathrm{km}/\mathrm{hr}\:,\:\:\:\:\:\:\:\:\:\mathrm{94}\:\mathrm{km}/\mathrm{hr} \\ $$

Commented by afachri last updated on 04/Dec/18

v_(conductor ) relative to road = 100 − 6                                                       =  94 km/h

$${v}_{\mathrm{conductor}\:} \mathrm{relative}\:\mathrm{to}\:\mathrm{road}\:=\:\mathrm{100}\:−\:\mathrm{6} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\mathrm{94}\:\mathrm{km}/\mathrm{h} \\ $$

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