Question Number 47979 by peter frank last updated on 17/Nov/18
Commented by peter frank last updated on 17/Nov/18
$$\mathrm{plse}\:\mathrm{help} \\ $$
Commented by mr W last updated on 18/Nov/18
$${what}\:{do}\:{you}\:{want}\:{to}\:{know}?\:{about} \\ $$$${sun}\:{and}\:{moon}\:{or}\:{about}\:{diet}? \\ $$
Commented by peter frank last updated on 18/Nov/18
$$\mathrm{both}\:\mathrm{sir}\:\mathrm{part}\:\mathrm{b},\mathrm{c}\:\mathrm{d} \\ $$
Commented by peter frank last updated on 18/Nov/18
$$\mathrm{how}\:\mathrm{do}\:\mathrm{i}\:\mathrm{get}\:\mathrm{those}\:\mathrm{ratio}\left(\mathrm{sun}\:\mathrm{and}\:\mathrm{moon}\right) \\ $$
Commented by mr W last updated on 18/Nov/18
$$\frac{{d}_{{Sun}} }{{d}_{{Moon}} }=\mathrm{400} \\ $$$$\frac{{V}_{{Sun}} }{{V}_{{Moon}} }=\mathrm{400}^{\mathrm{3}} =\mathrm{64000000} \\ $$
Commented by peter frank last updated on 18/Nov/18
$$\mathrm{thank}\:\mathrm{you}.\mathrm{how}\:\mathrm{about}\:\mathrm{diet} \\ $$
Commented by mr W last updated on 19/Nov/18
$$\frac{\mathrm{2}.\mathrm{3}\:{kg}}{\mathrm{1}\:{week}} \\ $$$$=\frac{\mathrm{2}.\mathrm{3}×\mathrm{1000}×\mathrm{1000}\:{milligrams}}{\mathrm{1}×\mathrm{7}×\mathrm{24}×\mathrm{60}×\mathrm{60}\:{seconds}} \\ $$$$\approx\mathrm{3}.\mathrm{80}\:\frac{{milligrams}}{{second}} \\ $$
Commented by peter frank last updated on 19/Nov/18
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$