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Question Number 46712 by maxmathsup by imad last updated on 30/Oct/18
$${find}\:{S}\left({z}\right)=\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{{z}^{{n}} }{{n}^{\mathrm{2}} }\:{with}\:{z}\:{complex}\:{and}\:\mid{z}\mid=\mathrm{1}\:. \\ $$