Question Number 46651 by gunay last updated on 29/Oct/18
$$\mathrm{3}\frac{\mathrm{8}}{\mathrm{19}}−\mathrm{2x}=\mathrm{1}\frac{\mathrm{6}}{\mathrm{19}} \\ $$$$\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by [email protected] last updated on 29/Oct/18
$$\left(\mathrm{3}+\frac{\mathrm{8}}{\mathrm{19}}\right)−\left(\mathrm{1}+\frac{\mathrm{6}}{\mathrm{19}}\right)=\mathrm{2}{x} \\ $$$$\left(\mathrm{3}−\mathrm{1}+\frac{\mathrm{8}}{\mathrm{19}}−\frac{\mathrm{6}}{\mathrm{19}}\right)=\mathrm{2}{x} \\ $$$$\left(\mathrm{2}+\frac{\mathrm{2}}{\mathrm{19}}\right)=\mathrm{2}{x} \\ $$$${x}=\mathrm{1}+\frac{\mathrm{1}}{\mathrm{19}}=\mathrm{1}\frac{\mathrm{1}}{\mathrm{19}}\:\: \\ $$