Question Number 20239 by tammi last updated on 24/Aug/17
$$\int\frac{\left(\mathrm{2}{x}+\mathrm{3}\right){dx}}{\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}} \\ $$
Answered by $@ty@m last updated on 25/Aug/17
$$=\int\frac{\mathrm{2}{x}+\mathrm{4}−\mathrm{1}}{\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}}{dx} \\ $$$$=\int\frac{\mathrm{2}{x}+\mathrm{4}}{\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}}{dx}−\int\frac{{dx}}{\sqrt{\left({x}+\mathrm{2}\right)^{\mathrm{2}} −\left(\sqrt{\mathrm{11}}\right)^{\mathrm{2}} }} \\ $$$$=\int\frac{{dt}}{\sqrt{{t}}}−{ln}\mid\left({x}+\mathrm{2}\right)+\sqrt{\left.\left({x}+\mathrm{2}\right)^{\mathrm{2}} −\sqrt{\left(\mathrm{11}\right.}\right)^{\mathrm{2}} }\mid\:,\:{where}\:{t}={x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7} \\ $$$$=\mathrm{2}\sqrt{{t}}−{ln}\mid{x}+\mathrm{2}+\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}\mid+{C} \\ $$$$=\mathrm{2}\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}−{ln}\mid{x}+\mathrm{2}+\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}\mid+{C} \\ $$