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Question Number 114656 by vylollloll last updated on 20/Sep/20

2tanx−1=1  ⇔2tanx=1+1  tanx=(2/2)=1

$$\mathrm{2}{tanx}−\mathrm{1}=\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{2}{tanx}=\mathrm{1}+\mathrm{1} \\ $$$${tanx}=\frac{\mathrm{2}}{\mathrm{2}}=\mathrm{1} \\ $$

Commented by vylollloll last updated on 20/Sep/20

Commented by bobhans last updated on 20/Sep/20

5cot 10x−1000=1000  5cot 10x = 1000+1000  5cot 10x=2000⇒cot 10x=((2000)/5)=400

$$\mathrm{5cot}\:\mathrm{10}{x}−\mathrm{1000}=\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}\:=\:\mathrm{1000}+\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}=\mathrm{2000}\Rightarrow\mathrm{cot}\:\mathrm{10}{x}=\frac{\mathrm{2000}}{\mathrm{5}}=\mathrm{400} \\ $$

Answered by 1549442205PVT last updated on 20/Sep/20

tanx=1⇔x=(π/4)+kπ

$$\mathrm{tanx}=\mathrm{1}\Leftrightarrow\mathrm{x}=\frac{\pi}{\mathrm{4}}+\mathrm{k}\pi \\ $$

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