Question Number 114656 by vylollloll last updated on 20/Sep/20 | ||
$$\mathrm{2}{tanx}−\mathrm{1}=\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{2}{tanx}=\mathrm{1}+\mathrm{1} \\ $$$${tanx}=\frac{\mathrm{2}}{\mathrm{2}}=\mathrm{1} \\ $$ | ||
Commented by vylollloll last updated on 20/Sep/20 | ||
Commented by bobhans last updated on 20/Sep/20 | ||
$$\mathrm{5cot}\:\mathrm{10}{x}−\mathrm{1000}=\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}\:=\:\mathrm{1000}+\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}=\mathrm{2000}\Rightarrow\mathrm{cot}\:\mathrm{10}{x}=\frac{\mathrm{2000}}{\mathrm{5}}=\mathrm{400} \\ $$ | ||
Answered by 1549442205PVT last updated on 20/Sep/20 | ||
$$\mathrm{tanx}=\mathrm{1}\Leftrightarrow\mathrm{x}=\frac{\pi}{\mathrm{4}}+\mathrm{k}\pi \\ $$ | ||